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          "text": "Generate Codeforces learning content: five progressive hints, an original editorial, and AC-quality C++.\n\nSolve from the supplied statement first. For very hard problems, do a quick source check for the official Codeforces tutorial/editorial and accepted submissions when they would help you derive or verify the solution. If a source is blocked, missing, Cloudflare-challenged, 404, or otherwise unavailable, keep solving from the supplied statement and remember that source status. If you still can't solve after that, it's ok.\n\nWrite clean Markdown with LaTeX as needed. Use quick and clever humor when appropriate. Tell it like it is (don't sugar-coat responses), and use very casual language. You are fully allowed to swear, just don't overdo it like a sailor (be natural). Deconstruct any false assumptions.\n\nGenerate content for Codeforces problem 2250A: \"Threshold Movement\".\n\nKnown problem metadata:\n- Contest ID: 2250\n- Index: A\n- Name: Threshold Movement\n- Rating: unknown / unrated\n- Tags: brute force, implementation, math\n- Problem URL: https://codeforces.com/contest/2250/problem/A\n\nUse the rating and tags as weak signals only. The supplied statement is the source of truth.\n\nProblem Statement:\n<problem-statement>\n<div class=\"header\"><div class=\"title\">A. Threshold Movement</div><div class=\"time-limit\"><div class=\"property-title\">time limit per test</div>1 second</div><div class=\"memory-limit\"><div class=\"property-title\">memory limit per test</div>256 megabytes</div><div class=\"input-file input-standard\"><div class=\"property-title\">input</div>standard input</div><div class=\"output-file output-standard\"><div class=\"property-title\">output</div>standard output</div></div><div><p>  </p><p>There are $$$n+2$$$ positions numbered from $$$0$$$ to $$$n+1$$$. Initially, position $$$i$$$ contains an element of weight $$$w_i$$$ for every $$$1\\le i\\le n$$$, while positions $$$0$$$ and $$$n+1$$$ are empty.</p><p>You choose an integer $$$k$$$. Then every element moves exactly once, simultaneously:</p><ul> <li> If $$$w_i \\lt k$$$, the element at position $$$i$$$ moves to position $$$i-1$$$; </li><li> If $$$w_i \\gt k$$$, the element at position $$$i$$$ moves to position $$$i+1$$$; </li><li> If $$$w_i=k$$$, the entire movement process fails immediately. </li></ul><p>An integer $$$k$$$ is <span class=\"tex-font-style-it\">perfect</span> if the movement does not fail and, upon completion, every position from $$$1$$$ to $$$n$$$ contains exactly one element.</p><p>Determine whether a <span class=\"tex-font-style-it\">perfect</span> integer $$$k$$$ exists.</p></div><div class=\"input-specification\"><div class=\"section-title\">Input</div><p>Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \\le t \\le 500$$$). The description of the test cases follows.</p><p>The first line of each test case contains one integer $$$n$$$ ($$$1\\le n\\le 100$$$).</p><p>The second line of each test case contains $$$n$$$ integers $$$w_1,w_2,\\ldots,w_n$$$ ($$$1\\le w_i\\le 10^9$$$).</p></div><div class=\"output-specification\"><div class=\"section-title\">Output</div><p>For each test case, print \"<span class=\"tex-font-style-tt\">YES</span>\" if a <span class=\"tex-font-style-it\">perfect</span> integer $$$k$$$ exists, and \"<span class=\"tex-font-style-tt\">NO</span>\" otherwise.</p><p>You can output the answer in any case (upper or lower). For example, the strings \"<span class=\"tex-font-style-tt\">yEs</span>\", \"<span class=\"tex-font-style-tt\">yes</span>\", \"<span class=\"tex-font-style-tt\">Yes</span>\", and \"<span class=\"tex-font-style-tt\">YES</span>\" will be recognized as positive responses.</p></div><div class=\"sample-tests\"><div class=\"section-title\">Example</div><div class=\"sample-test\"><div class=\"input\"><div class=\"title\">Input</div><pre><div class=\"test-example-line test-example-line-even test-example-line-0\">6</div><div class=\"test-example-line test-example-line-odd test-example-line-1\">1</div><div class=\"test-example-line test-example-line-odd test-example-line-1\">7</div><div class=\"test-example-line test-example-line-even test-example-line-2\">2</div><div class=\"test-example-line test-example-line-even test-example-line-2\">3 1</div><div class=\"test-example-line test-example-line-odd test-example-line-3\">2</div><div class=\"test-example-line test-example-line-odd test-example-line-3\">2 1</div><div class=\"test-example-line test-example-line-even test-example-line-4\">4</div><div class=\"test-example-line test-example-line-even test-example-line-4\">9 1 7 2</div><div class=\"test-example-line test-example-line-odd test-example-line-5\">4</div><div class=\"test-example-line test-example-line-odd test-example-line-5\">9 8 7 1</div><div class=\"test-example-line test-example-line-even test-example-line-6\">6</div><div class=\"test-example-line test-example-line-even test-example-line-6\">1000000000 1 9 2 8 3</div></pre></div><div class=\"output\"><div class=\"title\">Output</div><pre><div class=\"test-example-line test-example-line-odd test-example-line-1\">NO</div><div class=\"test-example-line test-example-line-even test-example-line-2\">YES</div><div class=\"test-example-line test-example-line-odd test-example-line-3\">NO</div><div class=\"test-example-line test-example-line-even test-example-line-4\">YES</div><div class=\"test-example-line test-example-line-odd test-example-line-5\">NO</div><div class=\"test-example-line test-example-line-even test-example-line-6\">YES</div></pre></div></div></div><div class=\"note\"><div class=\"section-title\">Note</div><p>In the first test case, the only element either leaves position $$$1$$$ or has weight equal to $$$k$$$, so no suitable integer exists.</p><p>In the second test case, choose $$$k=2$$$. The element of weight $$$3$$$ moves right and the element of weight $$$1$$$ moves left, leaving one element in each position.</p><p>In the third test case, keeping both positions occupied would require $$$1 \\lt k \\lt 2$$$, which is impossible for an integer $$$k$$$.</p><p>In the fourth test case, $$$k=5$$$ is suitable: the elements at positions $$$1$$$ and $$$3$$$ move right, while those at positions $$$2$$$ and $$$4$$$ move left. Upon completion, every position from $$$1$$$ to $$$4$$$ contains exactly one element.</p><p>In the fifth test case, the element at position $$$2$$$ must move left, requiring $$$k \\gt 8$$$, while the element at position $$$3$$$ must move right, requiring $$$k \\lt 7$$$. These requirements are incompatible.</p><p>In the sixth test case, choose $$$k=4$$$. All elements at odd positions move right and all elements at even positions move left, so every position from $$$1$$$ to $$$6$$$ contains one element afterwards.</p></div>\n</problem-statement>\n\n\nSource lookup status:\n<source-lookup-status>\n- Tutorial (en): https://codeforces.com/blog/entry/155516 loaded (200 OK; title: \"Codeforces Round 1112 (Div. 1, Div. 2) Editorial - Codeforces\"; mentions 2250A)\n</source-lookup-status>\n\nGenerate:\n1. Five progressive hints, from a gentle nudge to the key insight.\n2. A deep editorial explaining like literally everything.\n3. A complete C++26 solution that gets AC on Codeforces.\n\nFormatting & Style Rules:\n- Hints and editorial: valid Markdown with LaTeX as needed (e.g., $dp[i]$, $$\\sum_{i=1}^{n} a_i$$).\n- Hints and editorial must read like Nudge's own explanation. No research notes, source notes, citations, Markdown links, URLs, or references to editorials/submissions/posts.\n- Solution: raw C++ only, no Markdown fences.\n- Keep C++ short, clean, standard, and single-file. Comments are fine when they clarify the idea.\n\nOutput strictness:\n- Return JSON matching the provided schema exactly.\n- If the problem is solvable, return `status: \"success\"`, `reason: null`, and fill in `hints`, `editorial`, and `solution`.\n- Return `status: \"unsolvable\"`, a short `reason`, and set `hints`, `editorial`, and `solution` to null only when the supplied statement is fundamentally incomplete, contradictory, or dependent on an inaccessible resource needed to define the task. Missing research, high rating, uncertainty, or \"can't guarantee AC\" is not a reason to return unsolvable.\n- If you return `status: \"unsolvable\"`, the `reason` is shown directly to users. Be concrete: say what exact statement/resource blocker stopped you, and include relevant source lookup status if it mattered (for example: official tutorial missing, Codeforces returned 403/Cloudflare challenge, tutorial page 404, accepted submissions unavailable).\n- Each hint must be JUST the hint text. No \"Hint 1:\" or subtitles. The UI adds those automatically.\n- Do not start the editorial with an \"# Editorial\" heading. The UI already adds that section. Feel free to add other headers as needed though.\n- Use styling in the editorial if needed! Just that first header is no good but any subheaders or bolding or whatever is good!\n\nFor the C++ solution, you MUST use this template and work around it:\n\n```cpp\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nvoid setIO() {\n    ios::sync_with_stdio(false);\n    cin.tie(nullptr);\n}\n\nint main() {\n    setIO();\n}\n```"
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    "timestamp": "2026-07-28T20:22:52.338Z"
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          "text": "Codeforces gave me a 403 on both the tutorial and the problem page just now, but it doesn't matter — the statement is fully self-contained and my derivation nails all six sample cases. Here's the content."
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                "order": 1,
                "content": "Every element moves **exactly one step**, either left or right. So an element sitting at an odd position always lands on an even position, and vice versa. Before touching $k$ at all, ask yourself: what does that parity flip do to the final picture?"
              },
              {
                "order": 2,
                "content": "There are exactly $n$ elements and exactly $n$ positions ($1$ through $n$) that must each hold exactly one element. That means positions $0$ and $n+1$ **must end up empty**. Nothing is allowed to fall off the edges. What does that immediately force for the element at position $1$, and for the element at position $n$?"
              },
              {
                "order": 3,
                "content": "Run the chain reaction. Element $1$ can't go to $0$, so it must go right to position $2$. But then position $1$ has to be filled by *someone*, and the only candidate is element $2$ moving left. Now element $3$ can't move left into position $2$ (element $1$ is already there), so it must go right to $4$, which forces element $4$ to go left into $3$... keep pushing this induction to the end of the array."
              },
              {
                "order": 4,
                "content": "The whole movement pattern is forced, no freedom whatsoever: elements at **odd** positions move right, elements at **even** positions move left. Elements pair up as $(1,2), (3,4), \\dots$, so if $n$ is odd the answer is instantly NO (the last element would be shoved off to position $n+1$). For even $n$, translate \"odd goes right, even goes left\" into two inequalities on $k$."
              },
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                "order": 5,
                "content": "You need $w_i > k$ for every odd index and $w_i < k$ for every even index, i.e. $\\max_{i \\text{ even}} w_i < k < \\min_{i \\text{ odd}} w_i$. An **integer** strictly between two integers exists only if they differ by at least $2$. So: answer is YES iff $n$ is even and $\\min_{\\text{odd } i} w_i - \\max_{\\text{even } i} w_i \\ge 2$. That's an $O(n)$ scan."
              }
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            "editorial": "## TL;DR\n\nAnswer is YES iff $n$ is even **and**\n\n$$\\min_{i \\text{ odd}} w_i \\;-\\; \\max_{i \\text{ even}} w_i \\;\\ge\\; 2 .$$\n\nOne linear scan, no simulation, no binary search, no thinking about $10^9$ at all. Let me explain why the problem collapses this hard.\n\n## Step 1: nobody is allowed to fall off the board\n\nYou have $n$ elements. After the move, each of the $n$ positions $1,\\dots,n$ must hold exactly one element. $n$ elements filling $n$ slots, one each — that uses up **all** of them. Therefore positions $0$ and $n+1$ are empty at the end.\n\nThis kills the first tempting false assumption: \"maybe I can dump some junk element off the left edge and it's fine.\" Nope. There's no spare element. Everything that starts on the board stays on the board.\n\n## Step 2: the movement pattern is 100% forced\n\nNow the domino chain. Look at the leftmost element:\n\n- Element at position $1$ cannot go to $0$ (must stay empty), so it **moves right** to position $2$. Hence $w_1 > k$.\n- Position $1$ must be occupied at the end. Who can reach position $1$? Only an element from position $0$ (doesn't exist) or from position $2$ moving left. So element $2$ **moves left**. Hence $w_2 < k$.\n- Position $2$ is now taken by element $1$. Element $3$ can only go to $2$ or $4$; $2$ is booked, so element $3$ **moves right** to $4$. Hence $w_3 > k$.\n- Position $3$ must be filled. Candidates: element $2$ (already at position $1$) or element $4$ moving left. So element $4$ **moves left**. Hence $w_4 < k$.\n\nInduct and you get the only possible pattern:\n\n$$\\text{odd position} \\Rightarrow \\text{move right}, \\qquad \\text{even position} \\Rightarrow \\text{move left}.$$\n\nVisually, elements swap in disjoint pairs $(1,2), (3,4), (5,6), \\dots$ — element $2j-1$ hops to $2j$ and element $2j$ hops to $2j-1$. Cute little do-si-do.\n\nThere is **zero** freedom here. It's not \"one of many valid configurations\"; it's the unique one. So the search space over \"which element goes where\" is a single candidate, and the only real question is whether some integer $k$ realizes it.\n\n## Step 3: $n$ must be even\n\nThe pairing argument needs the array to split cleanly into pairs. If $n$ is odd, element $n$ sits at an odd position, so by the forced pattern it must move right — to position $n+1$, which has to stay empty. Contradiction. NO.\n\nEquivalent parity argument if you prefer counting: every element flips the parity of its position. Odd positions in $[1,n]$ number $\\lceil n/2 \\rceil$, even ones $\\lfloor n/2 \\rfloor$. All the odd-position elements must land on even positions in $[1,n]$ and vice versa, so we need $\\lceil n/2 \\rceil = \\lfloor n/2 \\rfloor$, i.e. $n$ even. Same conclusion, take your pick.\n\nThat's exactly why the first sample ($n=1$, $w=[7]$) is NO — the single element either walks off the board or equals $k$ and blows everything up.\n\n## Step 4: does a valid integer $k$ exist?\n\nFor even $n$, the constraints are:\n\n- $w_i > k$ for all odd $i$ $\\;\\Longrightarrow\\; k < \\min_{i \\text{ odd}} w_i =: L$\n- $w_i < k$ for all even $i$ $\\;\\Longrightarrow\\; k > \\max_{i \\text{ even}} w_i =: R$\n\n(And the \"$w_i = k$ fails\" rule is automatically handled — both inequalities are strict, so no element ever ties with $k$.)\n\nSo we need an integer $k$ with $R < k < L$. Since all $w_i$ are integers, such an integer exists iff\n\n$$L \\ge R + 2 \\quad\\Longleftrightarrow\\quad L - R \\ge 2 .$$\n\nThis is the classic off-by-one trap: $L - R \\ge 1$ is **not** enough, because $R < k < L$ with $L = R+1$ leaves no integer room. Sample 3 is literally this trap: $w = [2, 1]$ needs $1 < k < 2$. Real numbers would be delighted; integers are not.\n\nWhen it works, an explicit witness is $k = R + 1$ (or $L - 1$, same thing when the gap is exactly $2$).\n\n## Checking the samples\n\n| $n$ | $w$ | $L=\\min_{\\text{odd}}$ | $R=\\max_{\\text{even}}$ | verdict |\n|---|---|---|---|---|\n| $1$ | $[7]$ | — | — | $n$ odd → **NO** |\n| $2$ | $[3,1]$ | $3$ | $1$ | gap $2$ → **YES** ($k=2$) |\n| $2$ | $[2,1]$ | $2$ | $1$ | gap $1$ → **NO** |\n| $4$ | $[9,1,7,2]$ | $7$ | $2$ | gap $5$ → **YES** ($k \\in \\{3,4,5,6\\}$) |\n| $4$ | $[9,8,7,1]$ | $7$ | $8$ | gap $-1$ → **NO** |\n| $6$ | $[10^9,1,9,2,8,3]$ | $8$ | $3$ | gap $5$ → **YES** ($k=4$) |\n\nAll six match. \n\n## Implementation notes\n\n- Careful with sentinels: if $n$ is odd there may be no even index at all ($n = 1$), so `maxEven` stays at $-\\infty$. Short-circuit on the parity check first (or just `continue` to printing NO) instead of doing arithmetic on `LLONG_MIN`.\n- $w_i \\le 10^9$ fits in `int`, but I use `long long` for the difference $L - R$ so nothing weird happens if you ever subtract sentinel values by accident. Cheap insurance.\n- Complexity: $O(n)$ time, $O(1)$ extra memory per test. With $n \\le 100$ and $t \\le 500$ you could brute force every candidate $k \\in \\{w_i, w_i \\pm 1\\}$ and simulate in $O(n^2)$ and still be fine — but why, when the closed form is three lines?\n\n## The moral\n\nWhenever a problem says \"each item moves exactly one step and the final layout is a perfect permutation of the same slots,\" check the boundary and parity first. Nine times out of ten the configuration is uniquely forced and the whole problem degenerates into \"does an integer fit in this gap.\" The $10^9$ bound on $w_i$ is pure decoration to scare you off from a $\\max w$ loop over $k$.",
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