{
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    "slug": "glowing-moon",
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    "path": "private/var/folders/t7/b_w5m78j2mbb1ct051p9sv500000gn/T/nudge-opencode-generation-kLldAd",
    "title": "Nudge content generation",
    "agent": "nudge-generation",
    "model": {
      "id": "gpt-5.6-sol",
      "providerID": "openai",
      "variant": "max"
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  "messages": [
    {
      "info": {
        "role": "user",
        "time": {
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        },
        "agent": "nudge-generation",
        "model": {
          "providerID": "openai",
          "modelID": "gpt-5.6-sol",
          "variant": "max"
        },
        "system": "Follow the user prompt and output schema exactly.",
        "format": {
          "type": "json_schema",
          "schema": {
            "type": "object",
            "properties": {
              "status": {
                "type": "string",
                "enum": [
                  "success",
                  "unsolvable"
                ],
                "description": "Set to 'success' when the supplied statement defines a solvable programming problem. Set to 'unsolvable' only if the statement is fundamentally incomplete, contradictory, or depends on an inaccessible required resource."
              },
              "reason": {
                "anyOf": [
                  {
                    "type": "string"
                  },
                  {
                    "type": "null"
                  }
                ],
                "description": "If status is 'unsolvable', provide a detailed failure message to show users. Name the concrete statement/resource blocker and any relevant source lookup/access status, such as missing official tutorial, 403/Cloudflare challenge, 404, or unavailable accepted submissions. Otherwise null."
              },
              "hints": {
                "anyOf": [
                  {
                    "type": "array",
                    "description": "Exactly 5 progressive hints, each building on the last.",
                    "items": {
                      "type": "object",
                      "properties": {
                        "order": {
                          "type": "number",
                          "description": "Hint number, 1 through 5."
                        },
                        "content": {
                          "type": "string",
                          "description": "Markdown hint text."
                        }
                      },
                      "required": [
                        "order",
                        "content"
                      ],
                      "additionalProperties": false
                    }
                  },
                  {
                    "type": "null"
                  }
                ],
                "description": "If status is 'success', provide exactly 5 progressive hints. Otherwise null."
              },
              "editorial": {
                "anyOf": [
                  {
                    "type": "string"
                  },
                  {
                    "type": "null"
                  }
                ],
                "description": "If status is 'success', a prose editorial explaining the solution in Nudge's own voice, with no links, citations, or source/research notes. Otherwise null."
              },
              "solution": {
                "anyOf": [
                  {
                    "type": "string"
                  },
                  {
                    "type": "null"
                  }
                ],
                "description": "If status is 'success', a complete C++ solution. Otherwise null."
              }
            },
            "required": [
              "status",
              "reason",
              "hints",
              "editorial",
              "solution"
            ],
            "additionalProperties": false,
            "title": "problem_response",
            "description": "Submit the generated content for the problem, or report if it is unsolvable."
          },
          "retryCount": 2
        },
        "id": "msg_02fe6ff0c001bqZjx2hP6K4W3X",
        "sessionID": "ses_fd0190104ffe1SAb2sp1pYvTQX"
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      "parts": [
        {
          "type": "text",
          "text": "Generate Codeforces learning content: five progressive hints, an original editorial, and AC-quality C++.\n\nSolve from the supplied statement first. For very hard problems, do a quick source check for the official Codeforces tutorial/editorial and accepted submissions when they would help you derive or verify the solution. If a source is blocked, missing, Cloudflare-challenged, 404, or otherwise unavailable, keep solving from the supplied statement and remember that source status. If you still can't solve after that, it's ok.\n\nWrite clean Markdown with LaTeX as needed. Use quick and clever humor when appropriate. Tell it like it is (don't sugar-coat responses), and use very casual language. You are fully allowed to swear, just don't overdo it like a sailor (be natural). Deconstruct any false assumptions.\n\nGenerate content for Codeforces problem 2257F1: \"Beaver's Jumping Track (Easy Version)\".\n\nKnown problem metadata:\n- Contest ID: 2257\n- Index: F1\n- Name: Beaver's Jumping Track (Easy Version)\n- Rating: unknown / unrated\n- Tags: data structures, dp, matrices\n- Problem URL: https://codeforces.com/contest/2257/problem/F1\n\nUse the rating and tags as weak signals only. The supplied statement is the source of truth.\n\nProblem Statement:\n<problem-statement>\n<div class=\"header\"><div class=\"title\">F1. Beaver's Jumping Track (Easy Version)</div><div class=\"time-limit\"><div class=\"property-title\">time limit per test</div>2 seconds</div><div class=\"memory-limit\"><div class=\"property-title\">memory limit per test</div>1024 megabytes</div><div class=\"input-file input-standard\"><div class=\"property-title\">input</div>standard input</div><div class=\"output-file output-standard\"><div class=\"property-title\">output</div>standard output</div></div><div><p><span class=\"tex-font-style-bf\">This is the easy version of the problem. The difference between the versions is that in this version, the constraint on $$$x$$$ and time limit are lower. You can hack only if you solved all versions of this problem.</span></p><p>The Beaver is training to jump long distances. The Beaver can already jump $$$x$$$ meters. However, just jumping as far as possible is easy and boring. Therefore, the Beaver has created an unusual training track for jumping.</p><p>The track consists of $$$n$$$ platforms; each platform consists of $$$d_i$$$ meter cells. If the Beaver stands on platform number $$$i$$$, jumps, and lands back on the same platform, this results in $$$s_i$$$ penalty points being awarded; otherwise, no penalty points are given. The Beaver can jump forward any integer number of cells less than or equal to $$$x$$$. Note that the Beaver can skip one or more platforms in a single jump without landing on them at all.</p><p>The Beaver has unlimited computational power in its mind and always jumps in such a way as to minimize the total penalty for passing the track. Moreover, the track is not constant, and sometimes the lengths and penalties of some platforms change. Learn to calculate what penalty the Beaver will get if it starts standing on the first cell of platform number $$$l$$$ and finishes standing on the last cell of platform number $$$r$$$.</p></div><div class=\"input-specification\"><div class=\"section-title\">Input</div><p>The first line contains three integers $$$n$$$, $$$q$$$, $$$x$$$&nbsp;— the number of sections of the track, the number of queries, and the maximum jump length, respectively ($$$1 \\leq n \\leq 10^6$$$; $$$1 \\leq q \\leq 10^4$$$; $$$1 \\leq x \\leq 5$$$).</p><p>The second line contains $$$n$$$ integers $$$d_i$$$&nbsp;— the lengths of the platforms ($$$1 \\leq d_i \\leq 10^7$$$).</p><p>The third line contains $$$n$$$ integers $$$s_i$$$&nbsp;— the penalties ($$$1 \\leq s_i \\leq 10^5$$$).</p><p>The following $$$q$$$ lines describe the queries in one of the following formats: </p><ol> <li> \"<span class=\"tex-font-style-tt\">1 $$$i$$$ $$$v$$$</span>\"&nbsp;— set the length of the $$$i$$$-th platform to $$$v$$$ ($$$1 \\leq i \\leq n$$$; $$$1 \\leq v \\leq 10^7$$$); </li><li> \"<span class=\"tex-font-style-tt\">2 $$$i$$$ $$$y$$$</span>\"&nbsp;— set the penalty on the $$$i$$$-th platform to $$$y$$$ ($$$1 \\leq i \\leq n$$$; $$$1 \\leq y \\leq 10^5$$$); </li><li> \"<span class=\"tex-font-style-tt\">? $$$l$$$ $$$r$$$</span>\"&nbsp;— calculate the minimum penalty for passing the track consisting of platforms from $$$l$$$ to $$$r$$$ ($$$1 \\leq l \\leq r \\leq n$$$). </li></ol></div><div class=\"output-specification\"><div class=\"section-title\">Output</div><p>For each query of the third type, output a single number on a separate line&nbsp;— the minimum penalty.</p></div><div class=\"sample-tests\"><div class=\"section-title\">Example</div><div class=\"sample-test\"><div class=\"input\"><div class=\"title\">Input</div><pre><div class=\"test-example-line test-example-line-even test-example-line-0\">5 8 3</div><div class=\"test-example-line test-example-line-even test-example-line-0\">4 2 5 1 3</div><div class=\"test-example-line test-example-line-even test-example-line-0\">4 2 7 1 5</div><div class=\"test-example-line test-example-line-even test-example-line-0\">? 1 3</div><div class=\"test-example-line test-example-line-even test-example-line-0\">2 2 10</div><div class=\"test-example-line test-example-line-even test-example-line-0\">? 1 3</div><div class=\"test-example-line test-example-line-even test-example-line-0\">1 1 2</div><div class=\"test-example-line test-example-line-even test-example-line-0\">? 1 3</div><div class=\"test-example-line test-example-line-even test-example-line-0\">? 2 5</div><div class=\"test-example-line test-example-line-even test-example-line-0\">1 3 2</div><div class=\"test-example-line test-example-line-even test-example-line-0\">? 2 5</div></pre></div><div class=\"output\"><div class=\"title\">Output</div><pre>11\n11\n7\n7\n0\n</pre></div></div></div><div class=\"note\"><div class=\"section-title\">Note</div><p>During the first query, the lengths of the course sections are $$$[4, 2, 5]$$$ with costs $$$[4, 2, 7]$$$; the optimal route is </p><p>$$$$$$1 \\rightarrow 4 \\rightarrow 6 \\rightarrow 8 \\rightarrow 11$$$$$$ In this case, the penalty is $$$4 + 0 + 0 + 7 = 11$$$. </p><p>Before the second query, the penalty of the second course increased, but we never get it; thus, the answer to this query is also $$$11$$$.</p><p>Before the third query, we have the lengths of the courses $$$[2, 2, 5]$$$; then the route $$$$$$1 \\rightarrow 4 \\rightarrow 6 \\rightarrow 9$$$$$$ gives a penalty of 7, as the only penalizing jump is within one platform: $$$6 \\rightarrow 9$$$.</p></div>\n</problem-statement>\n\n\nSource lookup status:\n<source-lookup-status>\n- Tutorial (en): https://codeforces.com/blog/entry/156058 loaded (200 OK; title: \"Codeforces Round 1117 (Div. 2) Editorial - Codeforces\"; mentions 2257F1)\n</source-lookup-status>\n\nGenerate:\n1. Five progressive hints, from a gentle nudge to the key insight.\n2. A deep editorial explaining like literally everything.\n3. A complete C++26 solution that gets AC on Codeforces.\n\nFormatting & Style Rules:\n- Hints and editorial: valid Markdown with LaTeX as needed (e.g., $dp[i]$, $$\\sum_{i=1}^{n} a_i$$).\n- Hints and editorial must read like Nudge's own explanation. No research notes, source notes, citations, Markdown links, URLs, or references to editorials/submissions/posts.\n- Solution: raw C++ only, no Markdown fences.\n- Keep C++ short, clean, standard, and single-file. Comments are fine when they clarify the idea.\n\nOutput strictness:\n- Return JSON matching the provided schema exactly.\n- If the problem is solvable, return `status: \"success\"`, `reason: null`, and fill in `hints`, `editorial`, and `solution`.\n- Return `status: \"unsolvable\"`, a short `reason`, and set `hints`, `editorial`, and `solution` to null only when the supplied statement is fundamentally incomplete, contradictory, or dependent on an inaccessible resource needed to define the task. Missing research, high rating, uncertainty, or \"can't guarantee AC\" is not a reason to return unsolvable.\n- If you return `status: \"unsolvable\"`, the `reason` is shown directly to users. Be concrete: say what exact statement/resource blocker stopped you, and include relevant source lookup status if it mattered (for example: official tutorial missing, Codeforces returned 403/Cloudflare challenge, tutorial page 404, accepted submissions unavailable).\n- Each hint must be JUST the hint text. No \"Hint 1:\" or subtitles. The UI adds those automatically.\n- Do not start the editorial with an \"# Editorial\" heading. The UI already adds that section. Feel free to add other headers as needed though.\n- Use styling in the editorial if needed! Just that first header is no good but any subheaders or bolding or whatever is good!\n\nFor the C++ solution, you MUST use this template and work around it:\n\n```cpp\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nvoid setIO() {\n    ios::sync_with_stdio(false);\n    cin.tie(nullptr);\n}\n\nint main() {\n    setIO();\n}\n```",
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            "output": "---\nimage: //codeforces.com/codeforces.org/s/99500/images/codeforces-sponsored-by-ton.png\ntitle: Codeforces Round 1117 (Div. 2) Editorial - Codeforces\ndescription: Codeforces. Programming competitions and contests, programming community\n---\n\n<!DOCTYPE HTML PUBLIC \"-//W3C//DTD HTML 4.01//EN\"> \n\n  \n[![Codeforces](//codeforces.com/codeforces.org/s/99500/images/codeforces-sponsored-by-ton.png \"Codeforces\")](https://codeforces.com/) \n\n[![In English](//codeforces.com/codeforces.org/s/99500/images/flags/24/gb.png \"In English\")](https://codeforces.com/blog/entry/156058?locale=en) [![По-русски](//codeforces.com/codeforces.org/s/99500/images/flags/24/ru.png \"По-русски\")](https://codeforces.com/blog/entry/156058?locale=ru) \n\n[Enter](https://codeforces.com/enter?back=%2Fblog%2Fentry%2F156058)| [Register](https://codeforces.com/register) \n\n  \n* [Home](https://codeforces.com/)\n* [Top](https://codeforces.com/top)\n* [Catalog](https://codeforces.com/catalog)\n* [Contests](https://codeforces.com/contests)\n* [Gym](https://codeforces.com/gyms)\n* [Problemset](https://codeforces.com/problemset)\n* [Groups](https://codeforces.com/groups)\n* 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[Teams](https://codeforces.com/teams/with/pskobx)\n* [Submissions](https://codeforces.com/submissions/pskobx)\n* [Groups](https://codeforces.com/groups/with/pskobx)\n* [Contests](https://codeforces.com/contests/with/pskobx)\n* [Problemsetting](https://codeforces.com/contests/writer/pskobx)\n\n### [pskobx's blog](https://codeforces.com/blog/pskobx)\n\n[ Codeforces Round 1117 (Div. 2) Editorial ](https://codeforces.com/blog/entry/156058) \n\nBy [pskobx](https://codeforces.com/profile/pskobx \"Master pskobx\"), 6 days ago, ![In English](//codeforces.com/codeforces.org/s/99500/images/flags/24/gb.png \"In English\") \n\nThank you for participating in our round! We hope you enjoyed the problems.\n\n[2257A - Creating Abbreviations](https://codeforces.com/contest/2257/problem/A \"Codeforces Round 1117 (Div. 2)\") Idea: [egorka5opka](https://codeforces.com/profile/egorka5opka \"Master egorka5opka\")\n\n**Solution**\n\nNote that adding abbreviations to the set $$$S$$$ does not create any new possibilities for creating new abbreviations, because a word starting with that letter already exists. Therefore, for each of the 26 letters, we can remember that there is a word that begins with it, and then go through all the abbreviations and check each letter.\n\n**Code**\n\n[387467084](https://codeforces.com/contest/2257/submission/387467084 \"Submission 387467084 by pskobx\")\n\n**Rate the problem**\n\nAmazing [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\nGood [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\nOk [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\nBad [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\nTerrible [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\n[2257B - Gigantomachy](https://codeforces.com/contest/2257/problem/B \"Codeforces Round 1117 (Div. 2)\") Idea: [egorka5opka](https://codeforces.com/profile/egorka5opka \"Master egorka5opka\")\n\n**Solution**\n\nOn each turn, the height at which the giant stands decreases by exactly $$$1$$$, except in cases where he changes mountains. \n\nThus, the first giant will lose after $$$((a\\_1 - a\\_2) + 1) + ((a\\_2 - a\\_3) + 1) + \\\\dots + ((a\\_{n - 1} - a\\_n) + 1) + a\\_n = a\\_1 + n - 1$$$ moves. \n\nSimilarly, the second giant will lose after $$$b\\_1 + m - 1$$$ moves. All left is only to compare these two numbers.\n\nTime complexity: $$$\\\\mathcal{O}(n)$$$.\n\n**Code**\n\n[387467136](https://codeforces.com/contest/2257/submission/387467136 \"Submission 387467136 by pskobx\")\n\n**Rate the problem**\n\nAmazing [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\nGood [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\nOk [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\nBad [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\nTerrible [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\n[2257C - Spying on the Beaver](https://codeforces.com/contest/2257/problem/C \"Codeforces Round 1117 (Div. 2)\") Idea: [egorka5opka](https://codeforces.com/profile/egorka5opka \"Master egorka5opka\")\n\n**Solution**\n\nSuppose we have placed some cameras and remove the corresponding edges from the tree. If all the dams are now in different connected components, we can always uniquely determine where the Beaver went. Conversely, if there is a component containing two dams, we cannot distinguish between them.\n\nSince the original graph is a tree, it is necessary and sufficient to remove $$$m-1$$$ edges.\n\nIf the root contains a dam, we can take the edges leading directly to all the other dams, obtaining a set of size $$$m-1$$$.\n\nIf the root does not contain a dam, we take the same edges but skip one of them. It is important that we cannot skip just any edge: we must choose a dam such that there are no other dams on the path from the root to it. We can take the dam with the smallest depth or vertex number. In this case, we do not even need to run a DFS.\n\nTime complexity: $$$\\\\mathcal{O}(n+m)$$$.\n\n**Code**\n\n[387467226](https://codeforces.com/contest/2257/submission/387467226 \"Submission 387467226 by pskobx\")\n\n**Rate the problem**\n\nAmazing [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\nGood [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\nOk [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\nBad [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\nTerrible [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\n[2257D - Bermuda Rectangle](https://codeforces.com/contest/2257/problem/D \"Codeforces Round 1117 (Div. 2)\") Idea: [pskobx](https://codeforces.com/profile/pskobx \"Master pskobx\"), [oblememan](https://codeforces.com/profile/oblememan \"Master oblememan\"), [egorka5opka](https://codeforces.com/profile/egorka5opka \"Master egorka5opka\")\n\n**Solution**\n\nBefore processing the queries, let us perform some preprocessing. Find all pairs $$$(a, b)$$$ such that $$$a \\\\cdot b = S$$$. There are $$$\\\\mathcal{O}(\\\\sqrt{S})$$$ such pairs, and they can also be found in $$$\\\\mathcal{O}(\\\\sqrt{S})$$$ time with standard algorithms.\n\nThese pairs are the top-right corners of all possible Bermuda rectangles. The union of these rectangles forms a staircase-like shape; let us call it $$$F$$$. The answer to a query is the area of the intersection of the query rectangle with $$$F$$$.\n\nSort the points by $$$x$$$, and for the point with index $$$i$$$, compute the value $$$P\\_i$$$, equal to the area of $$$F$$$ between $$$0$$$ and this $$$x\\_i$$$.\n\nThis information is enough to answer each query efficiently using binary search. We find the position where the boundary of $$$F$$$ crosses the horizontal side of the query rectangle and calculate the answer using the corresponding prefix areas. The exact formulas and case analysis may vary depending on the implementation.\n\nA couple of remarks that may make implementation easier. If there is a point $$$(x, y)$$$, then there is also $$$(y, x)$$$, and since, knowing one coordinate, it is easy to compute the other. Therefore, it is enough to store just the sorted list of divisors of $$$S$$$ and treat them both as $$$x$$$ and as $$$y$$$. \n\nPreprocessing complexity: $$$\\\\mathcal{O}(\\\\sqrt{S})$$$, time complexity per query: $$$\\\\mathcal{O}(\\\\log S)$$$.\n\n**Code**\n\n[387467301](https://codeforces.com/contest/2257/submission/387467301 \"Submission 387467301 by pskobx\")\n\n**Rate the problem**\n\nAmazing [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\nGood [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\nOk [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\nBad [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\nTerrible [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\n[2257E - Busy Beaver](https://codeforces.com/contest/2257/problem/E \"Codeforces Round 1117 (Div. 2)\") Idea: [pskobx](https://codeforces.com/profile/pskobx \"Master pskobx\")\n\n**Solution**\n\nThe first step is to earn as many carrots as possible to maximize our capital. Divide the floors of each building into the shortest consecutive segments whose total profit is non-negative, and calculate the entry threshold of each such segment. The entry threshold is the minimum amount of capital required to construct all floors of the segment in order.\n\nFor example, consider two floors with $$$(a\\_1, a\\_2) = (10, 0)$$$ and $$$(b\\_1, b\\_2) = (0, 100)$$$. Constructing only the first floor is unprofitable, but constructing both floors yields a profit of $$$90$$$ carrots. However, an initial capital of at least $$$10$$$ carrots is required.\n\nIn an ordered set, we keep the next available segment for each building, sorted by its entry threshold. While the segment with the minimum threshold is affordable, we construct the entire segment, add its profit to our capital, and insert the next segment of the same building into the set. If the segment with the minimum threshold is not affordable, then none of the available segments can be constructed, meaning that we have maximized our capital.\n\nIn the second step, we independently try to continue constructing each building from its current height, floor by floor, for as long as the current capital allows. Among all buildings, we choose the maximum resulting height and, in case of a tie, the smallest index.\n\nTime complexity: $$$\\\\mathcal{O}\\\\left(\\\\sum m\\_i \\\\log n\\\\right)$$$.\n\n**Code**\n\n[387467400](https://codeforces.com/contest/2257/submission/387467400 \"Submission 387467400 by pskobx\")\n\n**Rate the problem**\n\nAmazing [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\nGood [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\nOk [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\nBad [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\nTerrible [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\n[2257F1 - Beaver's Jumping Track (Easy Version)](https://codeforces.com/contest/2257/problem/F1 \"Codeforces Round 1117 (Div. 2)\") Idea: [pskobx](https://codeforces.com/profile/pskobx \"Master pskobx\"), [oblememan](https://codeforces.com/profile/oblememan \"Master oblememan\"), [egorka5opka](https://codeforces.com/profile/egorka5opka \"Master egorka5opka\")\n\n**Solution**\n\nSince $$$x$$$ is small, we build a segment tree whose vertices store matrices of size $$$x \\\\times x$$$.\n\nFor an interval of platforms, let $$$c\\[i\\]\\[j\\]$$$ be the minimum penalty if the Beaver starts $$$i$$$ cells after the beginning of the interval and first lands $$$j$$$ cells after its end. Invalid starting positions are ignored.\n\nFor a single platform of length $$$d$$$ and penalty $$$s$$$,\n\n$$$ c\\[i\\]\\[j\\]= \\\\left( \\\\left\\\\lceil\\\\frac{d+j-i}{x}\\\\right\\\\rceil-1 \\\\right)s, $$$\n\nwhere $$$0\\\\le i \\\\lt \\\\min(d,x)$$$ and $$$0\\\\le j \\\\lt x$$$. The last jump leaves the platform and causes no penalty, while all previous jumps stay inside it.\n\nTo merge two consecutive intervals $$$A$$$ and $$$B$$$, enumerate the first landing position $$$k$$$ in $$$B$$$:\n\n$$$ c\\_{A+B}\\[i\\]\\[j\\] = \\\\min\\_k\\\\left(c\\_A\\[i\\]\\[k\\]+c\\_B\\[k\\]\\[j\\]\\\\right). $$$\n\nIf $$$A$$$ contains fewer than $$$x$$$ cells, the Beaver may start directly inside $$$B$$$; in this case, we copy the corresponding values from $$$c\\_B$$$.\n\nFor a query $$$\\[l,r\\]$$$, obtain the matrix for $$$\\[l,r-1\\]$$$ and enumerate the first landing position $$$i$$$ on platform $$$r$$$. The answer is\n\n$$$ \\\\min\\_{0\\\\le i \\\\lt \\\\min(x,d\\_r)} \\\\left( c\\[0\\]\\[i\\] + \\\\left\\\\lceil\\\\frac{d\\_r-i-1}{x}\\\\right\\\\rceil s\\_r \\\\right). $$$\n\nThe case $$$l=r$$$ is calculated directly.\n\nEach update and query takes $$$\\\\mathcal{O}(x^3\\\\log n)$$$ time. Memory complexity is $$$\\\\mathcal{O}(nx^2)$$$. Build is $$$\\\\mathcal{O}(nx^3)$$$.\n\n**Code**\n\n[387467533](https://codeforces.com/contest/2257/submission/387467533 \"Submission 387467533 by pskobx\")\n\n**Rate the problem**\n\nAmazing [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\nGood [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\nOk [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\nBad [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\nTerrible [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\n[2257F2 - Beaver's Jumping Track (Hard Version)](https://codeforces.com/contest/2257/problem/F2 \"Codeforces Round 1117 (Div. 2)\")\n\n**Solution**\n\nSurprisingly, the main problem with the solution from F1 is memory, not time. A segment tree stores $$$\\\\mathcal{O}(n)$$$ matrices, each containing $$$x^2$$$ values. For $$$x=10$$$, this does not fit into the memory limit.\n\nTo reduce memory usage, divide the platforms into blocks of size $$$B$$$ (for example, $$$B=16$$$). For each block, calculate the matrix of the entire block using the same merging formula as in F1\\. Then build a segment tree only over these block matrices.\n\nFor a query, at most two blocks are only partially covered by the required range. Process the platforms in these blocks separately, and use the segment tree to combine all blocks that are fully covered. After an update, recalculate the matrix of the affected block and update it in the segment tree.\n\nFor a block size $$$B$$$, the memory complexity is $$$\\\\mathcal{O}\\\\left(n+\\\\frac{n}{B}x^2\\\\right)$$$.\n\nEach query takes $$$\\\\mathcal{O}\\\\left(Bx^2+x^3\\\\log\\\\frac{n}{B}\\\\right)$$$.\n\nАnd each update takes $$$\\\\mathcal{O}\\\\left(Bx^3+x^3\\\\log\\\\frac{n}{B}\\\\right)$$$.\n\n**Code**\n\n[387467610](https://codeforces.com/contest/2257/submission/387467610 \"Submission 387467610 by pskobx\")\n\n**Rate the problem**\n\nAmazing [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\nGood [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\nOk [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\nBad [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\nTerrible [ ](https://codeforces.com/data/like?action=like \"I like this\") \n\n![](//codeforces.com/codeforces.org/s/99500/images/icons/paperclip-16x16.png) Tutorial of [Codeforces Round 1117 (Div. 2)](https://codeforces.com/contest/2257) \n\n* [![Vote: I like it](//codeforces.com/codeforces.org/s/99500/images/actions/voteup-gray.png \"Vote: I like it\")](#)\n* \\-111\n* [![Vote: I do not like it](//codeforces.com/codeforces.org/s/99500/images/actions/votedown-gray.png \"Vote: I do not like it\")](#)\n\n* [![Author](//codeforces.com/codeforces.org/s/99500/images/blog/user_16x16.png \"Author\")](https://codeforces.com/profile/pskobx) [pskobx ](https://codeforces.com/profile/pskobx)\n* ![Publication date](//codeforces.com/codeforces.org/s/99500/images/blog/date_16x16.png \"Publication date\") 6 days ago\n* [![Comments](//codeforces.com/codeforces.org/s/99500/images/blog/comments_16x16.png \"Comments\")](https://codeforces.com/blog/entry/156058#comments) [209 ](https://codeforces.com/blog/entry/156058#comments)\n\n  \n![Comments](//codeforces.com/codeforces.org/s/99500/images/icons/comments-48x48.png \"Comments\") Comments (209) \n\n[Write comment?](#) \n\n| » [esc\\_qwq](https://codeforces.com/profile/esc%5Fqwq \"Candidate Master esc_qwq\") | 6 days ago, [show (+1)](#) # |\n| --------------------------------------------------------------------------------- | ---------------------------- |\n\n| » [ ![](https://codeforces.com/userpic.codeforces.org/4963270/avatar/be164ba8d5d4a72e.jpg) ](https://codeforces.com/profile/esc%5Fqwq) [esc\\_qwq](https://codeforces.com/profile/esc%5Fqwq \"Candidate Master esc_qwq\") | 6 days ago, [hide](#) [#](https://codeforces.com/blog/entry/156058?#comment-1386304 \"Link to comment\") \\| [![Vote: I like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-voteup-blue.png \"Vote: I like it\")](#) +91 [![Vote: I do not like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-votedown-blue.png \"Vote: I do not like it\")](#) Horrible contest [→](#) [Reply](#) |\n| ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- | -------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- |\n\n* | » » [jypo\\_CYL](https://codeforces.com/profile/jypo%5FCYL \"Newbie jypo_CYL\") | 6 days ago, [show (+1)](#) # |\n| ---------------------------------------------------------------------------- | ---------------------------- |\n\n| » » [ ![](https://codeforces.com/userpic.codeforces.org/3846644/avatar/58b83965b1ab953b.jpg) ](https://codeforces.com/profile/jypo%5FCYL) [jypo\\_CYL](https://codeforces.com/profile/jypo%5FCYL \"Newbie jypo_CYL\") | 6 days ago, [hide](#) [#](https://codeforces.com/blog/entry/156058?#comment-1386363 \"Link to comment\") [^](#comment-1386304 \"Parent comment\") \\| [![Vote: I like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-voteup-blue.png \"Vote: I like it\")](#) +3 [![Vote: I do not like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-votedown-blue.png \"Vote: I do not like it\")](#) so bad D [→](#) [Reply](#) |\n| ------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------ | -------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- |\n\n  * | » » » [unorz](https://codeforces.com/profile/unorz \"Newbie unorz\") | 5 days ago, [show (+1)](#) # |\n| ------------------------------------------------------------------ | ---------------------------- |\n\n| » » » [ ![](https://codeforces.com/userpic.codeforces.org/4392235/avatar/9e0dd13ad8852cf4.jpg) ](https://codeforces.com/profile/unorz) [unorz](https://codeforces.com/profile/unorz \"Newbie unorz\") | 5 days ago, [hide](#) [#](https://codeforces.com/blog/entry/156058?#comment-1386715 \"Link to comment\") [^](#comment-1386363 \"Parent comment\") \\| [![Vote: I like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-voteup-blue.png \"Vote: I like it\")](#) 0 [![Vote: I do not like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-votedown-blue.png \"Vote: I do not like it\")](#) interesting, i loved D! Really resembled USACO problems [→](#) [Reply](#) |\n| --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- | ------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------ |\n\n    * | » » » » [jypo\\_CYL](https://codeforces.com/profile/jypo%5FCYL \"Newbie jypo_CYL\") | 5 days ago, [show](#) # |\n| -------------------------------------------------------------------------------- | ----------------------- |\n\n| » » » » [ ![](https://codeforces.com/userpic.codeforces.org/3846644/avatar/58b83965b1ab953b.jpg) ](https://codeforces.com/profile/jypo%5FCYL) [jypo\\_CYL](https://codeforces.com/profile/jypo%5FCYL \"Newbie jypo_CYL\") | 5 days ago, [hide](#) [#](https://codeforces.com/blog/entry/156058?#comment-1386745 \"Link to comment\") [^](#comment-1386715 \"Parent comment\") \\| [![Vote: I like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-voteup-blue.png \"Vote: I like it\")](#) 0 [![Vote: I do not like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-votedown-blue.png \"Vote: I do not like it\")](#) nah it shouldn't be [→](#) [Reply](#) |\n| ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- | ------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------ |\n\n| » [Vctqwq](https://codeforces.com/profile/Vctqwq \"Specialist Vctqwq\") | 6 days ago, [show (+1)](#) # |\n| --------------------------------------------------------------------- | ---------------------------- |\n\n| » [ ![](https://codeforces.com/userpic.codeforces.org/2479255/avatar/5d52d13c72db55a1.jpg) ](https://codeforces.com/profile/Vctqwq) [Vctqwq](https://codeforces.com/profile/Vctqwq \"Specialist Vctqwq\") | 6 days ago, [hide](#) [#](https://codeforces.com/blog/entry/156058?#comment-1386306 \"Link to comment\") \\| [![Vote: I like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-voteup-blue.png \"Vote: I like it\")](#) +42 [![Vote: I do not like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-votedown-blue.png \"Vote: I do not like it\")](#) Super fast editorial! But these statements are difficult to understand :( [→](#) [Reply](#) |\n| ------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- | ----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- |\n\n* | » » [RizzCoder](https://codeforces.com/profile/RizzCoder \"Newbie RizzCoder\") | 6 days ago, [show](#) # |\n| ---------------------------------------------------------------------------- | ----------------------- |\n\n| » » [ ![](https://codeforces.com/userpic.codeforces.org/5564274/avatar/4212eb081339fb3b.jpg) ](https://codeforces.com/profile/RizzCoder) [RizzCoder](https://codeforces.com/profile/RizzCoder \"Newbie RizzCoder\") | 6 days ago, [hide](#) [#](https://codeforces.com/blog/entry/156058?#comment-1386351 \"Link to comment\") [^](#comment-1386306 \"Parent comment\") \\| [![Vote: I like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-voteup-blue.png \"Vote: I like it\")](#) 0 [![Vote: I do not like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-votedown-blue.png \"Vote: I do not like it\")](#) bro editorial is wrong [→](#) [Reply](#) |\n| ----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- | --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- |\n\n| » [zeyd1234](https://codeforces.com/profile/zeyd1234 \"Specialist zeyd1234\") | 6 days ago, [show](#) # |\n| --------------------------------------------------------------------------- | ----------------------- |\n\n| » [ ![](https://codeforces.com/userpic.codeforces.org/4840403/avatar/50b684c8412376e6.jpg) ](https://codeforces.com/profile/zeyd1234) [zeyd1234](https://codeforces.com/profile/zeyd1234 \"Specialist zeyd1234\") | 6 days ago, [hide](#) [#](https://codeforces.com/blog/entry/156058?#comment-1386311 \"Link to comment\") \\| [![Vote: I like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-voteup-blue.png \"Vote: I like it\")](#) +20 [![Vote: I do not like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-votedown-blue.png \"Vote: I do not like it\")](#) Bad contest... but at least i gain some rating. [→](#) [Reply](#) |\n| --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- | --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- |\n\n| » [\\-rmq](https://codeforces.com/profile/-rmq \"Specialist -rmq\") | 6 days ago, [show (+1)](#) # |\n| ---------------------------------------------------------------- | ---------------------------- |\n\n| » [ ![](https://codeforces.com/userpic.codeforces.org/no-avatar.jpg) ](https://codeforces.com/profile/-rmq) [\\-rmq](https://codeforces.com/profile/-rmq \"Specialist -rmq\") | 6 days ago, [hide](#) [#](https://codeforces.com/blog/entry/156058?#comment-1386326 \"Link to comment\") \\| [![Vote: I like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-voteup-blue.png \"Vote: I like it\")](#) 0 [![Vote: I do not like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-votedown-blue.png \"Vote: I do not like it\")](#) Can you recheck, if correct code is attached in the editorial. Seems different submission is present here [pskobx](https://codeforces.com/profile/pskobx) [→](#) [Reply](#) |\n| -------------------------------------------------------------------------------------------------------------------------------------------------------------------------- | ----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- |\n\n* | » » [RizzCoder](https://codeforces.com/profile/RizzCoder \"Newbie RizzCoder\") | 6 days ago, [show](#) # |\n| ---------------------------------------------------------------------------- | ----------------------- |\n\n| » » [ ![](https://codeforces.com/userpic.codeforces.org/5564274/avatar/4212eb081339fb3b.jpg) ](https://codeforces.com/profile/RizzCoder) [RizzCoder](https://codeforces.com/profile/RizzCoder \"Newbie RizzCoder\") | 6 days ago, [hide](#) [#](https://codeforces.com/blog/entry/156058?#comment-1386333 \"Link to comment\") [^](#comment-1386326 \"Parent comment\") \\| [![Vote: I like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-voteup-blue.png \"Vote: I like it\")](#) 0 [![Vote: I do not like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-votedown-blue.png \"Vote: I do not like it\")](#) yeah I think first has nothing to do with 3 variables [→](#) [Reply](#) |\n| ----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- | ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- |\n* | » » [zeyd1234](https://codeforces.com/profile/zeyd1234 \"Specialist zeyd1234\") | 6 days ago, [show](#) # |\n| ----------------------------------------------------------------------------- | ----------------------- |\n\n| » » [ ![](https://codeforces.com/userpic.codeforces.org/4840403/avatar/50b684c8412376e6.jpg) ](https://codeforces.com/profile/zeyd1234) [zeyd1234](https://codeforces.com/profile/zeyd1234 \"Specialist zeyd1234\") | 6 days ago, [hide](#) [#](https://codeforces.com/blog/entry/156058?#comment-1386338 \"Link to comment\") [^](#comment-1386326 \"Parent comment\") \\| [←](#)Rev. 2 [→](#) [![Vote: I like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-voteup-blue.png \"Vote: I like it\")](#) 0 [![Vote: I do not like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-votedown-blue.png \"Vote: I do not like it\")](#) type (user:XXX), if you want to ping someone. But with \\[\\], instead of (). But if you don't want to get your contribution < -100, please, don't ping someone unless necessary. [→](#) [Reply](#) |\n| ----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- | -------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- |\n* | » » [pskobx](https://codeforces.com/profile/pskobx \"Master pskobx\") | 6 days ago, [show](#) # |\n| ------------------------------------------------------------------- | ----------------------- |\n\n| » » [ ![](https://codeforces.com/userpic.codeforces.org/1250475/avatar/7536d700942a822b.jpg) ](https://codeforces.com/profile/pskobx) [pskobx](https://codeforces.com/profile/pskobx \"Master pskobx\") | 6 days ago, [hide](#) [#](https://codeforces.com/blog/entry/156058?#comment-1386346 \"Link to comment\") [^](#comment-1386326 \"Parent comment\") \\| [![Vote: I like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-voteup-blue.png \"Vote: I like it\")](#) 0 [![Vote: I do not like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-votedown-blue.png \"Vote: I do not like it\")](#) I'll fix it now, thanks [→](#) [Reply](#) |\n| ----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- | ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- |\n\n| » [20111019Yu](https://codeforces.com/profile/20111019Yu \"Master 20111019Yu\") | 6 days ago, [show](#) # |\n| ----------------------------------------------------------------------------- | ----------------------- |\n\n| » [ ![](https://codeforces.com/userpic.codeforces.org/3490545/avatar/2b7d9f312416805a.jpg) ](https://codeforces.com/profile/20111019Yu) [20111019Yu](https://codeforces.com/profile/20111019Yu \"Master 20111019Yu\") | 6 days ago, [hide](#) [#](https://codeforces.com/blog/entry/156058?#comment-1386329 \"Link to comment\") \\| [![Vote: I like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-voteup-blue.png \"Vote: I like it\")](#) +8 [![Vote: I do not like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-votedown-blue.png \"Vote: I do not like it\")](#) How dare you write the wrong range? [→](#) [Reply](#) |\n| ------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- | -------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- |\n\n| » [bandit07](https://codeforces.com/profile/bandit07 \"Newbie bandit07\") | 6 days ago, [show](#) # |\n| ----------------------------------------------------------------------- | ----------------------- |\n\n| » [ ![](https://codeforces.com/userpic.codeforces.org/5022929/avatar/9f7f959d1770105a.jpg) ](https://codeforces.com/profile/bandit07) [bandit07](https://codeforces.com/profile/bandit07 \"Newbie bandit07\") | 6 days ago, [hide](#) [#](https://codeforces.com/blog/entry/156058?#comment-1386332 \"Link to comment\") \\| [![Vote: I like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-voteup-blue.png \"Vote: I like it\")](#) 0 [![Vote: I do not like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-votedown-blue.png \"Vote: I do not like it\")](#) Apart from Figuring out TLE on D, everything was great! [→](#) [Reply](#) |\n| ----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- | --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- |\n\n| » [zhaohongdi114514](https://codeforces.com/profile/zhaohongdi114514 \"Candidate Master zhaohongdi114514\") | 6 days ago, [show (+1)](#) # |\n| --------------------------------------------------------------------------------------------------------- | ---------------------------- |\n\n| » [ ![](https://codeforces.com/userpic.codeforces.org/no-avatar.jpg) ](https://codeforces.com/profile/zhaohongdi114514) [zhaohongdi114514](https://codeforces.com/profile/zhaohongdi114514 \"Candidate Master zhaohongdi114514\") | 6 days ago, [hide](#) [#](https://codeforces.com/blog/entry/156058?#comment-1386334 \"Link to comment\") \\| [![Vote: I like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-voteup-blue.png \"Vote: I like it\")](#) +35 [![Vote: I do not like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-votedown-blue.png \"Vote: I do not like it\")](#) Felt like eating shit. [→](#) [Reply](#) |\n| ------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- | -------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- |\n\n* | » » [ma\\_niu\\_bi](https://codeforces.com/profile/ma%5Fniu%5Fbi \"Expert ma_niu_bi\") | 6 days ago, [show](#) # |\n| ---------------------------------------------------------------------------------- | ----------------------- |\n\n| » » [ ![](https://codeforces.com/userpic.codeforces.org/2710300/avatar/1c5c34a0e21a0f46.jpg) ](https://codeforces.com/profile/ma%5Fniu%5Fbi) [ma\\_niu\\_bi](https://codeforces.com/profile/ma%5Fniu%5Fbi \"Expert ma_niu_bi\") | 6 days ago, [hide](#) [#](https://codeforces.com/blog/entry/156058?#comment-1386672 \"Link to comment\") [^](#comment-1386334 \"Parent comment\") \\| [←](#)Rev. 3 [→](#) [![Vote: I like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-voteup-blue.png \"Vote: I like it\")](#) +3 [![Vote: I do not like it](//codeforces.com/codeforces.org/s/99500/images/actions/comment-votedown-blue.png \"Vote: I do not like it\")](#) My brain's full of shit. [→](#) [Reply](#) |\n| --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- | -------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- |\n\n| » [invoker.\\_](https://codeforces.com/profile/invoker.%5F \"Pupil invoker._\") | 6 days ago, [show (+1)](#) # |\n| ---------------------------------------------------------------------------- | ---------------------------- |\n\n\n...359925 bytes truncated...\n\nThe tool call succeeded but the output was truncated. Full output saved to: /Users/zayd/.local/share/opencode/tool-output/tool_02fe75e44001sYT6N1bAbEFCo5\nUse Grep to search the full content or Read with offset/limit to view specific sections.",
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            "input": {
              "query": "\"387467533\" Codeforces 2257F1 source code",
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            "output": "Title: 1957F1 - Frequency Mismatch (Easy Version) - Pastebin.com\nURL: https://pastebin.com/3UtUh3Yg\nPublished: N/A\nAuthor: N/A\nHighlights:\n1957F1 - Frequency Mismatch (Easy Version) - Pastebin.com\n...\n# 1957F1 - Frequency Mismatch (Easy Version)\n...\nC++ 7.50 KB | Source Code | 0 0\n...\n#pragma GCC optimize(\"Ofast\")\n...\n100\n...\nint node,\n...\nvoid query(Node *downLft1,Node *downLft2,Node *downRgt1,Node *downRgt2,Node *upLft1,Node *upLft2,Node *upRgt1,Node *up\n...\ngt2,ll l\n...\n1,ll l\n...\nl = 1,\n...\n1e5){\n\n---\n\nTitle: Codeforces/1257/f.cpp\nURL: https://github.com/eyangch/competitive-programming/blob/master/Codeforces/1257/f.cpp\nPublished: N/A\nAuthor: N/A\nHighlights:\n# Codeforces/1257/f.cpp\n...\n- Branch: master\n- Repository: eyangch/competitive-programming\n\n---\n\nTitle: CF ROUND 1027 F AC - Pastebin.com\nURL: https://pastebin.com/cD3zjF73\nPublished: N/A\nAuthor: N/A\nHighlights:\nCF ROUND 1027 F AC - Pastebin.com\n...\n# CF ROUND 1027 F AC\n\n pb_jiang \n\n May 27th, 2025 \n\n 689 \n\n1. // Problem: F. Small Operations\n2. // Contest: Codeforces - Codeforces Round 1027 (Div. 3)\n3. // URL: https://codeforces.com/contest/2114/problem/F\n4. // Memory Limit: 256 MB\n5. // Time Limit: 3000 ms\n6. //\n7. // Powered by CP Editor (https://cpeditor.org)\n8. #include <assert.h>\n9. #include \n10. using namespace std;\n11. #ifndef __DEBUG__\n12. #define dbg(...) 42\n13. #endif\n...\nT> using mpq = priority_queue< T, vector< T>, greater< T>>;\n...\n15. namespace\n...\ns = std:: ranges;\n...\n17. using\n...\nl = array\n...\n18. using pll = pair< ll, ll>;\n...\n19. using vl = vector< ll>;\n...\nll calc_\n...\nll x, ll k\n...\n62. ll calc_step2(ll x, ll k)\n...\n87. void solve2()\n\n---\n\nTitle: N/A\nURL: https://codeforces.com/contest/2253/hacks/1180270/test\nPublished: N/A\nAuthor: N/A\nHighlights:\n** Generator source **\n...\n#include \nusing namespace std; \n \n// ======== EXTRA DEFINITION ======== \n// ================================== \n \nstruct _custom_hash { \n static uint64_t process(uint64_t x) { \n x+=0x9e3779b97f4a7c15; \n x=(x^(x>>30))*0xbf58476d1ce4e5b9; \n x=(x^(x>>27))*0x94d049bb133111eb; \n return x^(x>>31); \n } \n \n size_t operator () (uint64_t x) const { \n static const uint64_t rnd=chrono::steady_clock::now().time_since_epoch().count(); \n return process(x+rnd); \n } \n \n template \n size_t operator () (const pair<A,B>& p) const { \n auto h1=operator()(p.first); \n auto h2=operator()(p.second); \n return h1^(h2<<1); \n } \n}; \n \n#ifdef PBDS \n \n#include \n#include \n#include \n#include \n#include \n \ntemplate using _set=__gnu_pbds::tree<T,__gnu_pbds::null_type,less,__gnu_pbds::rb_tree_tag,__gnu_pbds::tree_order_statistics_node_update>; \ntemplate using _multiset=__gnu_pbds::tree<T,__gnu_pbds::null_type,less_equal,__gnu_pbds::rb_tree_tag,__gnu_pbds::tree_order_statistics_node_update>; \ntemplate using _map=__gnu_pbds::tree<Key,Value,less,__gnu_pbds::rb_tree_tag,__gnu_pbds::tree_order_statistics_node_update>; \ntemplate using _multimap=__gnu_pbds::tree<Key,Value,less_equal,__gnu_pbds::rb_tree_tag,__gnu_pbds::tree_order_statistics_node_update>; \ntemplate using _unordered_map=__gnu_pbds::gp_hash_table<Key,Val>; \ntemplate using _hash=__gnu_pbds::gp_hash_table<Key,Val,_custom_hash>; \n \n#endif \n \n// ======== EXTRA DEFINITION ======== \n// ================================== \n \nconst int N=1; \nconst int M=2; \nconst int K=log2((long double)N)+2; \nconst int mod=998244353; \nconst int inf=2e9; \nconst double pi=acos(-1); \nconst double eps=1e-9; \n \n#ifdef OPTIMIZE \n#pragma GCC optimize(\"Ofast\") \n#pragma GCC optimize(\"unroll-loops\") \n#pragma GCC optimize(\"inline-functions\") \n#pragma GCC optimize(\"no-stack-protector\") \n#pragma GCC optimize(\"O3\") \n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,avx2,tune=native\") \n#endif \n \n#define endl '\\n' \n \n#define FRR(file) freopen(file,\"r\",stdin) \n#define FRW(file) freopen(file,\"w\",stdout) \n#define FRE(file) freopen(file,\"w\",stderr) \n \n#define TIMESTAMP cerr<<fixed<<setprecision(3)<<clock()*1.0/CLOCKS_PER_SEC<<\"s\"<<endl; \n \n#define _rep(i,a,b) for (int i=(a);i<=(b);++i) \n#define _reps(i,a,b,c) for (int i=(a);i<=(b);c) \n#define _rrep(i,a,b) for (int i=(a);i>=(b);--i) \n#define _rreps(i,a,b,c) for (int i=(a);i>=(b);c) \n#define _repb(i,n) for (int i=0;i<(1<<(n));++i) \n#define _rrepb(i,n) for (int i=(1<<(n))-1;~i;--i) \n#define _iter(i,a) for (auto i=a.begin();i!=a.end();++i) \n#define _riter(i,a) for (auto i=a.rbegin();i!=a.rend();++i) \n#define _graph(i,u) for (int i=h[u];~i;i=ne[i]) \n#define _dinic(i,u) for (int i=cur[u];~i && k<limit;i=ne[i]) \n#define _for(i,a) for (auto& i:a) \n#define _all(x) (x).begin(),(x).end() \n#define _rall(x) (x).rbegin(),(x).rend() \n#define _per(x) next_permutation(_all(x)) \n#define _pera(x,fr,to) next_permutation((x)+(fr),(x)+(to)+1) \n#define _rper(x) prev_permutation(_all(x)) \n#define _rpera(x,fr,to) prev_permutation((x)+(fr),(x)+(to)+1) \n#define _rev(x) reverse(_all(x)) \n#define _reva(x,fr,to) reverse((x)+(fr),(x)+(to)+1) \n#define _sort(x) sort(_all(x)) \n#define _sorta(x,fr,to) sort((x)+(fr),(x)+(to)+1) \n#define _sortf(type) inline friend bool operator < (const type& a,const type& b) \n#define _rsort(x) sort(_rall(x)) \n#define _rsorta(x,fr,to) do { _sorta(x,fr,to),_reva(x,fr,to); } while (0) \n#define _unique(x) (x).erase(unique(_all(x)),x.end()) \n \ninline void _yes(const bool& a) { puts(a?\"yes\":\"no\"); } \ninline void _Yes(const bool& a) { puts(a?\"Yes\":\"No\"); } \ninline void _YES(const bool& a) { puts(a?\"YES\":\"NO\"); } \ninline void _possible(const bool& a) { puts(a?\"possible\":\"impossible\"); } \ninline void _Possible(const bool& a) { puts(a?\"Possible\":\"Impossible\"); } \ninline void _POSSIBLE(const bool& a) { puts(a?\"POSSIBLE\":\"IMPOSSIBLE\"); } \n \n#define rint register int \n#define i8 int8_t \n#define i16 int16_t \n#define i32 int32_t \n#define i64 int64_t \n#define i128 __int128 \n#define u8 uint8_t \n#define u16 uint16_t \n#define u32 uint32_t \n#define u64 uint64_t \n#define u128 unsigned __int128 \n#define f128 __float128 \n \nint main() { \n puts(\"1\"); \n puts(\"1000000\"); \n int n=1000000; \n int len=2000; \n _rep(i,1,len-1) printf(\"%d %d\\n\",i,i+1); \n int cur=len+1; \n _rep(i,2,len-1) { \n int dest=min(i-1,len-i); \n int las=i; \n while (dest--) { \n if (cur==n+1) break; \n printf(\"%d %d\\n\",las,cur); \n las=cur; \n cur++; \n } \n if (cur==n+1) break; \n } \n return 0; \n}\n\n---\n\nTitle: [CF1257F]Make Them Similar - Programmer All\nURL: https://www.programmerall.com/article/34451170544/\nPublished: N/A\nAuthor: N/A\nHighlights:\n## [CF1257F]Make Them Similar\n...\ntags: other Other\n...\nFolding Half Search\n...\n```\n#include<cstdio>\n#include<cstring>\n#include<map>\nusing namespace std;\n\n#define rep(i,__l,__r) for(signed i=(__l),i##_end_=(__r);i<=i##_end_;++i)\n#define fep(i,__l,__r) for(signed i=(__l),i##_end_=(__r);i>=i##_end_;--i)\n#define erep(i,u) for(signed i=tail[u],v=e[i].to;i;i=e[i].nxt,v=e[i].to)\n#define writc(a,b) fwrit(a),putchar(b)\n#define mp(a,b) make_pair(a,b)\n#define ft first\n#define sd second\ntypedef long long LL;\n// typedef pair<int,int> pii;\ntypedef unsigned long long ull;\ntypedef unsigned uint;\n#define Endl putchar('\\n')\n// #define int long long\n// #define int unsigned\n// #define int unsigned long long\n\n#define cg (c=getchar())\n...\ntemplate<class T>inline void read(T& x){\n    char c;bool f=0;\n    while(cg<'0'||'9'<c)f|=(c=='-');\n    for(x=(c^48);'0'<=cg&&c<='9';x=(x<<1)+(x<<3)+(c^48));\n    if(f)x=-x;\n}\n...\ntemplate<class T>inline T read(const T sample){\n    T x=0;char c;bool f=0;\n    while(cg<'0'||'9'<c)f|=(c=='-');\n    for(x=(c^48);'0'<=cg&&c<='9';x=(x<<1)+(x<<3)+(c^48));\n    return f?-x:x;\n}\n...\ntemplate<class T>void fwrit(const T x){//just short,int and long long\n    if(x<0)return (void)(putchar('-'),fwrit(-x));\n    if(x>9)fwrit(x/10);\n    putchar(x%10^48);\n}\n...\ntemplate<class T>inline T Max(const T x,const T y){return x>y?x:y;}\ntemplate<class T>inline T Min(const T x,const T y){return x<y?x:y;}\ntemplate<class T>inline T fab(const T x){return x>0?x:-x;}\n...\ninline int gcd(const int a,const int b){return b?gcd(b,a%b):a;}\n...\ninline void getInv(int inv[],const int lim,const int MOD){\n    inv[0]=inv[1]=1;for(int i=2;i<=lim;++i)inv[i]=1ll*inv[MOD%i]*(MOD-MOD/i)%MOD;\n}\n...\ninline LL mulMod(const LL a,const LL b,const LL mod){//long long multiplie_mod\n    return ((a*b-(LL)((long double)a/mod*b+1e-8)*mod)%mod+mod)%mod;\n}\n\nconst int MAXN=100;\nconst int MAXK=29;\n\nint n,a[MAXN+5];\nint cnt[MAXK+5][MAXN+5];\nint bitcnt[MAXN+5];\n\ninline void Init(){\n    n=read(1);\n    rep(i,1,n)a[i]=read(1);\n}\n\ninline void Getcnt(){\n    rep(i,0,MAXK){\n        rep(j,1,n)if((a[j]^(1<<i))<a[j])cnt[i][j]=-1;\n        else cnt[i][j]=1;\n    }\n}\n\nstruct node{\n    int a[MAXN+5];\n    node(){memset(a,0,sizeof a);}\n    inline bool operator <(const node rhs)const{\n        rep(i,1,n)if(a[i]^rhs.a[i])\n            return a[i]<rhs.a[i];\n        return 0;\n    }\n}tmp;\n...\nmap<node,int>Map;\nint t[MAXN+5];\nnode arr[1<<17];\nint ax[1<<17],acnt;\n...\ninline void putIn(const int x,const int ind){\n    // printf(\"When ind == %d, x == %d\\n\",ind,x);\n    tmp=node();\n    rep(i,1,n-1)tmp.a[i]=t[i]-t[i+1];\n    // rep(i,1,n-1)writc(tmp.a[i],' ');Endl;\n    if(ind==0){\n        ++acnt;\n        arr[acnt]=tmp,ax[acnt]=x;\n    }\n    else Map[tmp]=x;\n}\n...\nvoid dfs(const int i,const int now,const int lim,const int x){\n    if(now>lim)return putIn(x,i);\n    dfs(i,now+1,lim,x);\n    rep(j,1,n)t[j]+=cnt[now][j];\n    dfs(i,now+1,lim,x^(1<<now));\n    rep(j,1,n)t[j]-=cnt[now][j];\n}\n\ninline void Getbitcnt(){\n    rep(i,1,n){\n        rep(j,0,MAXK)if((a[i]>>j)&1)\n            ++bitcnt[i];\n    }\n    rep(i,1,n-1)bitcnt[i]-=bitcnt[i+1];\n}\n...\nsigned main(){\n    Init();\n    Getcnt();\n    Getbitcnt();\n    dfs(0,0,14,0);\n    dfs(1,15,29,0);\n    rep(i,1,acnt){\n        tmp=node();\n        rep(j,1,n-1)tmp.a[j]=-bitcnt[j]-arr[i].a[j];\n        if(Map.count(tmp)){\n            printf(\"%d\\n\",ax[i]|Map[tmp]);\n            return 0;\n        }\n    }printf(\"-1\\n\");\n\treturn 0;\n}\n\n```\n...\n- CF1257F Make Them Similar\n- Codeforces 1257F Make Them Similar\n- Exercise: Make Them Similar (Folding Half Search)\n- 【CF1257F】Make Them Similar【meet in the middle+hash】\n- codeforces#1257 F. Make Them Similar (Classic encounter problem)\n- Luo Valley CF1257F MAKE Them Similar Gray Questions\n- Educational Codeforces Round 76 (Rated for Div. 2)F - Make Them Similar\n- POJ 1703 Find Them, Catch Them [Type / Rights and Collection + Judgment whether the two elements are in the same collection / different collection / unable to determine + similar food chain]\n- Find them, Catch them\n...\n- POJ170\n...\nFind them, Catch them\n\n---\n\nTitle: Codeforces 1257F Make Them Similar-JZTXT\nURL: https://www.jztxt.com/t/UgY/\nPublished: N/A\nAuthor: N/A\nHighlights:\nCodeforces 1257F Make Them Similar-JZTXT\n...\n# Codeforces 1257F Make Them Similar\n...\n发布时间 2023-07-09 00:41:23作者: lhzawa\n...\n发现 \\(O(2^w)\\) 过不了但是 \\(O(2^{\\frac{w}{2}})\\) 过得了（\\(w\\) 为数二进制形式位数，此题为 \\(30\\)），且异或操作表明每一位之间不会互相影响，很明显上个折半搜索就行。\n...\n考虑怎么合并，\n...\n同样的套路，考虑前半部分得到的为 \\(c\n...\nn}\\)，后半部分为 \\(c'_{1\n...\nn}\\)，则\n...\n\\(c_1 + c'_1 = c_2 + c'_2 =\\cdots = c_n + c'_n\\)。 然后把 \\(c\\)\n...\n1 - c\n...\n2 = c'_\n...\n- c'_1\n...\n\\cdots,\n...\n1 - c\n...\nc'_n - c'_\n...\n后半部分的 \\((c'_2\n...\ncdots,c'_n\n...\n,\\cdots,c\n...\n2^{\\frac{n\n...\n```\n// lhzawa(https://www.cnblogs.com/lhzawa/)\n// Problem: F. Make Them Similar\n// Contest: Codeforces - Educational Codeforces Round 76 (Rated for Div. 2)\n// URL: https://codeforces.com/contest/1257/problem/F\n// Memory Limit: 1024 MB\n// Time Limit: 4000 ms\n// \n// Powered by CP Editor (https://cpeditor.org)\n\n#include<bits/stdc++.h>\nusing namespace std;\n...\nconst int N = 1e2 + 10, M = 30;\nint n;\n...\nint a[N][M], cnt[N];\n...\nmap<basic_string<int>, int> mp;\n...\nvoid dfs1(int w, int s) {\n\tif (w >= M / 2) {\n\t\tbasic_string<int> u;\n\t\tfor (int i = 2; i <= n; i++) {\n\t\t\tu += cnt[1] - cnt[i];\n\t\t}\n\t\tmp[u] = s;\n\t\treturn ;\n\t}\n\tfor (int i = 1; i <= n; i++) {\n\t\tcnt[i] += a[i][w];\n\t}\n\tdfs1(w + 1, s);\n\tfor (int i = 1; i <= n; i++) {\n\t\tcnt[i] -= a[i][w];\n\t}\n\tfor (int i = 1; i <= n; i++) {\n\t\tcnt[i] += 1 - a[i][w];\n\t}\n\tdfs1(w + 1, s + (1 << w));\n\tfor (int i = 1; i <= n; i++) {\n\t\tcnt[i] -= 1 - a[i][w];\n\t}\n\treturn ;\n}\n...\nvoid dfs2(int w, int s) {\n\tif (w >= M) {\n\t\tbasic_string<int> u;\n\t\tfor (int i = 2; i <= n; i++) {\n\t\t\tu += cnt[i] - cnt[1];\n\t\t}\n\t\tif (mp.count(u)) {\n\t\t\tprintf(\"%d\", s + mp[u]);\n\t\t\texit(0);\n\t\t}\n\t\treturn ;\n\t}\n\tfor (int i = 1; i <= n; i++) {\n\t\tcnt[i] += a[i][w];\n\t}\n\tdfs2(w + 1, s);\n\tfor (int i = 1; i <= n; i++) {\n\t\tcnt[i] -= a[i][w];\n\t}\n\tfor (int i = 1; i <= n; i++) {\n\t\tcnt[i] += 1 - a[i][w];\n\t}\n\tdfs2(w + 1, s + (1 << w));\n\tfor (int i = 1; i <= n; i++) {\n\t\tcnt[i] -= 1 - a[i][w];\n\t}\n\treturn ;\n}\n...\nint main() {\n\tscanf(\"%d\", &n);\n\tfor (int i = 1; i <= n; i++) {\n\t\tint x;\n\t\tscanf(\"%d\", &x);\n\t\tfor (int j = 0; j < M; j++, x >>= 1) {\n\t\t\ta[i][j] = x & 1;\n\t\t}\n\t} \n\tdfs1(0, 0);\n\tdfs2(M / 2, 0);\n\tprintf(\"-1\");\n\treturn 0;\n}\n\n---\n\nTitle: Problem - F - Codeforces\nURL: https://codeforces.com/contest/1677/problem/F\nPublished: N/A\nAuthor: N/A\nHighlights:\nProblem - F - Codeforces\n...\nF. Tokitsukaze and Gems\n...\nTokitsukaze has a sequence with length of $$$n$$$. She likes gems very much. There are $$$n$$$ kinds of gems. The gems of the $$$i$$$-th kind are on the $$$i$$$-th position, and there are $$$a_i$$$ gems of the same kind on that position. Define $$$G(l,r)$$$ as the multiset containing all gems on the segment $$$[l,r]$$$ (inclusive).\n...\nA multiset of gems can be represented as $$$S=[s_1,s_2,\\ldots,s_n]$$$, which is a non-negative integer sequence of length $$$n$$$ and means that $$$S$$$ contains $$$s_i$$$ gems of the $$$i$$$-th kind in the multiset. A multiset $$$T=[t_1,t_2,\\ldots,t_n]$$$ is a multisubset of $$$S=[s_1,s_2,\\ldots,s_n]$$$ if and only if $$$t_i\\le s_i$$$ for any $$$i$$$ satisfying $$$1\\le i\\le n$$$.\n...\nNow, given two positive integers $$$k$$$ and $$$p$$$, you need to calculate the result of\n...\n$$$$$$\\sum_{l=1}^n \\sum_{r=l}^n\\sum\\limits_{[t_1,t_2,\\cdots,t_n] \\subseteq G(l,r)}\\left(\\left(\\sum_{i=1}^n p^{t_i}t_i^k\\right)\\left(\\sum_{i=1}^n[t_i \\gt 0]\\right)\\right),$$$$$$\n...\nwhere $$$[t_i \\gt 0]=1$$$ if $$$t_i \\gt 0$$$ and $$$[t_i \\gt 0]=0$$$ if $$$t_i=0$$$.\n...\nSince the answer can be quite large, print it modulo $$$998\\,244\\,353$$$.\n...\nThe first line contains three integers $$$n$$$, $$$k$$$ and $$$p$$$ ($$$1\\le n \\le 10^5$$$; $$$1\\le k\\le 10^5$$$; $$$2\\le p\\le 998\\,244\\,351$$$) — the length of the sequence, the numbers $$$k$$$ and $$$p$$$.\n...\nThe second line contains $$$n$$$ integers $$$a_1, a_2, \\ldots, a_n$$$ ($$$1\\le a_i\\le 998\\,244\\,351$$$) — the number of gems on the $$$i$$$-th position.\n...\nPrint a single integers — the result modulo $$$998\\,244\\,353$$$.\n\n---\n\nTitle: codeforces/1859/F.cpp\nURL: https://github.com/mdarikrayhan/Competitive-Programming/blob/master/codeforces/1859/F.cpp\nPublished: N/A\nAuthor: N/A\nHighlights:\n# codeforces/1859/F.cpp\n...\n- Branch: master\n- Repository: mdarikrayhan/Competitive-Programming\n...\n{\n...\nu] <= tin[v] && tout\n...\ntout[v];\n...\n}\n...\nint root)\n...\ntimer\n...\ndepth\n...\ndfs\n...\n} \n \n int\n...\nk -= (\n...\ni);\n...\nreturn opt;\n...\n} \n int64_t get2(\n...\nw2[\n...\n];\n...\nif(k\n...\n) return opt; \n else \n { \n for(int i = L; i\n...\nif(v\n...\nopt = min(opt, ans2[\n...\n][i]);\n...\n);\n...\n= up[\n...\n} \n } \n return opt; \n } \n \n int lca(int u, int v) //lca of u and v\n...\nif (is_\n...\nreturn u;\n...\nv, u))\n...\n;\n...\n; --i\n...\n(up[u][i\n...\nup[u][\n...\n];\n...\n};\n...\ncode starts\n...\nfastio(); \n int tt; \n cin >> tt; \n while(tt--) \n { \n int n, t, q; \n cin >> n >> t; \n \n vector course(n + 1, false); \n vector<vector<pair<int, int>>> adj(n + 1); \n for(int i = 1, u, v, w; i < n; i ++) cin >> u >> v >> w, adj[u].pb(mp(v, w)), adj[v].pb(mp(u, w)); \n \n char c; \n for(int i = 1; i <= n; i ++) cin >> c, course[i] = (c == '1'); \n \n cin >> q; \n vector<pair<int, int>> qr(q + 1); \n vector<int64_t> ans(q + 1, INF); \n for(int i = 1; i <= q; i ++) cin >> qr[i].first >> qr[i].second; \n \n //\n...\nwhat do we\n...\n//\n...\n(n +\n...\n), invdis(n +\n...\nn +\n...\n, 0);\n...\n[&](int c\n...\n{\n...\nu] + ceil_div(\n...\n, c), dfs\n...\nv.first,\n...\n);\n...\ndis[\n...\n0; \n dfs(1, 0\n...\n;\n...\n); \n near\n...\nassign(n + 1, INF); \n \n for(int i = 1; i <= n; i ++) if(course[i]) \n { \n q.erase(mp(near[i], i)); \n near[i] = 0; \n q.insert(mp(near[i], i)); \n mark[i] =\n...\n; \n }\n...\nq.empty()) \n { \n auto cur = *q.begin(); \n q.erase\n...\ncur); \n \n int u\n...\n; \n mark[u\n...\n;\n...\nv : adj[u]) \n {\n...\nv.first] and near[u] + v.second + ceil_div(v.second, c) < near[v.first]) \n { \n q.erase(mp(near\n...\n[u]\n...\nans\n...\n[qr[i].first\n...\n[qr[i\n...\n- 2 * dis\n...\ntake);\n...\ni] - dis\n...\ni]; \n lca\n...\n{\n...\na = qr\n...\n;\n...\nb);\n...\nt * take +\n\n---\n\nTitle: 1676F.cpp at main · tar3q-az1z/Codeforces-solutions\nURL: https://github.com/tar3q-az1z/Codeforces-solutions/blob/main/1676F.cpp\nPublished: N/A\nAuthor: N/A\nHighlights:\n# 1676F.cpp\n...\n- Branch: main\n- Repository: tar3q-az1z/Codeforces-solutions\n...\n// @Author: Mars_Coder\n// @date: 24-Jul-23 1:29:11 PM +06\n// https://codeforces.com/problemset/problem/1676/F\n...\nint main(void){\n stop_sync;\n untie_ios;\n #ifndef ONLINE_JUDGE\n //freopen(\"generator.txt\", \"r\", stdin);\n freopen(\"input.txt\", \"r\", stdin);\n freopen(\"output.txt\", \"w\", stdout);\n freopen(\"error.txt\", \"w\", stderr);\n #endif\n \n int t(1), tcase(0);\n cin >> t; \n while(++tcase, t--){\n //cout << \"--------Case #\" << tcase << \": --------\\n\";\n int n, k;\n cin >> n >> k; \n vi a(n);\n map<int, int> m;\n for(int i = 0; i < n; ++i){\n cin >> a[i];\n ++m[a[i]];\n }\n sort(All(a));\n unq_v(a);\n int l = -1, r = -1;\n int mx = -1;\n for(int i = 0; i < sz(a); ++i){\n if(m[a[i]] >= k){\n int cnt = 1;\n int j;\n for(j = i + 1; j < sz(a); ++j){\n if(m[a[i] + j - i] < k) break;\n if(m[a[j]] >= k) ++cnt;\n else break;\n }\n if(cnt > mx){\n mx = cnt;\n l = a[i];\n r = a[j - 1];\n }\n i = j - 1;\n //mx = max(mx, cnt);\n }\n }\n if(mx == -1) cout << - 1 << ln;\n else cout << l << ' ' << r << ln;\n }\n return 0;\n}\n\n---\n\nTitle: codeforces/1437/F.cpp\nURL: https://github.com/wuyuhang05/OI-Code/blob/master/codeforces/1437/F.cpp\nPublished: N/A\nAuthor: N/A\nHighlights:\n# codeforces/1437/F.cpp\n\n- Branch: master\n- Repository: wuyuhang05/OI-Code\n...\n#include \n \n#define fi first \n#define se second \n#define db double \n#define U unsigned \n#define P std::pair<int,int> \n#define LL long long \n#define pb push_back \n#define MP std::make_pair \n#define all(x) x.begin(),x.end() \n#define CLR(i,a) memset(i,a,sizeof(i)) \n#define FOR(i,a,b) for(int i = a;i <= b;++i) \n#define ROF(i,a,b) for(int i = a;i >= b;--i) \n#define DEBUG(x) std::cerr << #x << '=' << x << std::endl \n \nconst int MAXN = 5000+5; \nconst int ha = 998244353; \nint a[MAXN],n; \nint f[2][MAXN],cf[MAXN]; \n// 选了 i 个数 最大值是 j \nstd::vector S; \nint las[MAXN];// 选了 i 之后 还有几个数可以放 \nint nxt[MAXN];// 选了 i 之后 下一个必须选啥 \nint cnt[MAXN]; \n \ninline void add(int &x,int y){ \n x += y-ha;x += x>>31&ha; \n} \n \nint main(){ \n scanf(\"%d\",&n); \n FOR(i,1,n) scanf(\"%d\",a+i); \n std::sort(a+1,a+n+1); \n FOR(i,1,n) S.pb(a[i]);S.erase(std::unique(all(S)),S.end()); \n FOR(i,1,n) cnt[std::lower_bound(all(S),a[i])-S.begin()+1]++; \n int m = S.size(); \n FOR(i,1,m){ \n las[i] = las[i-1]; \n while(las[i]+1 <= n && a[las[i]+1]*2 <= S[i-1]) las[i]++; \n } \n nxt[0] = 1; \n FOR(i,1,m){ \n nxt[i] = -1; \n FOR(j,i+1,m){ \n if(S[i-1]*2 <= S[j-1]) {nxt[i] = j;break;} \n } \n } \n int now = 0;f[now][0] = 1; \n FOR(i,1,n){ \n CLR(f[now^1],0);CLR(cf,0); \n FOR(j,0,m){ \n if(!f[now][j]) continue; \n int t = las[j]-i+1+1; \n if(j == 0) t = 0; \n if(t > 0) add(f[now^1][j],1ll*f[now][j]*t%ha); \n if(nxt[j] != -1) add(cf[nxt[j]],f[now][j]); \n } \n FOR(j,1,m) add(cf[j],cf[j-1]),add(f[now^1][j],1ll*cf[j]*cnt[j]%ha); \n now ^= 1; \n// FOR(i,0,m) printf(\"%d \",f[now][i]);puts(\"\"); \n } \n printf(\"%d\\n\",f[now][m]); \n return 0; \n}",
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            "title": "Exa Web Search: \"387467533\" Codeforces 2257F1 source code",
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            "output": "Title: #1112040 (C++17) No.3227 Matrix Query - yukicoder\nURL: https://yukicoder.me/submissions/1112040\nPublished: N/A\nAuthor: N/A\nHighlights:\n#1112040 (C++17) No.3227 Matrix Query - yukicoder\n...\n| 問題 | No.3227 Matrix Query |\n| --- | --- |\n| コンテスト | |\n| ユーザー | このユーザーの提出の表示 yutas |\n| 提出日時 | 2025-08-13 16:22:27 |\n| 言語 | C++17 (gcc 15.2.0 + boost 1.90.0) コンパイル: `g++-15 -O2 -lm -std=c++17 -Wuninitialized -DONLINE_JUDGE -o a.out _filename_` 実行: `./a.out` |\n| 結果 | AC |\n| 実行時間 | 1,183 ms / 8,000 ms |\n| | + 346µs |\n| コード長 | 2,443 bytes |\n| 記録 記録タグの例: 初AC ショートコード 純ショートコード 純主流ショートコード 最速実行時間 | |\n| コンパイル時間 | 1,486 ms |\n| コンパイル使用メモリ | 226,476 KB |\n| 実行使用メモリ | 23,168 KB |\n| 最終ジャッジ日時 | 2026-07-14 00:07:33 |\n| 合計ジャッジ時間 | 22,967 ms |\n| ジャッジサーバーID（参考情報） | judge2_0 / judge3_0 |\n...\nstruct SegmentTree {\nprivate:\n  int n;\n  vector<Mat> node;\n\npublic:\n  SegmentTree(int sz) {\n    n = 1;\n    while (n < sz) {\n      n *= 2;\n    }\n    node.resize(2 * n - 1, {{0, 0}, {0, 0}});\n  }\n\n  void insert(int idx, Mat m, ll mod) {\n    idx += n - 1;\n    node[idx] = m;\n    while (idx > 0) {\n      idx = (idx - 1) / 2;\n      node[idx] = my_calc(node[2 * idx + 1], node[2 * idx + 2], mod);\n    }\n    return;\n  }\n\n  Mat solve(int a, int b, ll mod, int idx = 0, int l = 0, int r = -1) {\n    if (r == -1) {\n      r = n;\n    }\n    if (b <= l || r <= a) {\n      return {{1, 0}, {0, 1}};\n    }\n    if (a <= l && r <= b) {\n      return node[idx];\n    }\n    return my_calc(solve(a, b, mod, 2 * idx + 1, l, (l + r) / 2),\n                   solve(a, b, mod, 2 * idx + 2, (l + r) / 2, r), mod);\n  }\n};\n...\nint main() {\n  cin >> mod >> n;\n  SegmentTree tree(n + 5);\n\n  for (int i = 1; i <= n; i++) {\n    for (int j = 0; j < 2; j++) {\n      for (int k = 0; k < 2; k++) {\n        cin >> a[j][k];\n      }\n    }\n    tree.insert(i, a, mod);\n  }\n\n  cin >> q;\n  for (int i = 1; i <= q; i++) {\n    int idx, l, r;\n    cin >> idx >> l >> r;\n    for (int j = 0; j < 2; j++) {\n      for (int k = 0; k < 2; k++) {\n        cin >> a[j][k];\n      }\n    }\n    tree.insert(idx, a, mod);\n    ans[i] = tree.solve(l, r + 1, mod);\n  }\n\n  for (int i = 1; i <= q; i++) {\n    for (int j = 0; j < 2; j++) {\n      cout << ans[i][j][0] << \" \" << ans[i][j][1] << endl;\n    }\n  }\n\n  return 0;\n}\n\n---\n\nTitle: Dp Transition related queries using Segment Tree - Codeforces\nURL: https://codeforces.com/blog/entry/139260\nPublished: N/A\nAuthor: N/A\nHighlights:\nDp Transition related queries using Segment Tree - Codeforces\n...\nDp Transition related queries using Segment Tree\n...\nwhere we have\n...\n2-Dimensional DP\n...\nN][K] (N\n...\nNow the problem is, given Q queries, for each query, we can modify the transitions between any two adjacent rows Dp[i] to Dp[i+1] , After performing each query, We should recalculate the final values of Dp[0] th row after performing each query. Assume that the transitions are in linear combination of next row of Dp.\n...\n##### Solution Idea:\n...\n- This problem may seem hard, because changing\n...\nrow of dp table, would change\n...\ndp table, which would be hard to recalculate faster. And also the change in one transition affects many entries of DP\n...\nand there is\n...\nwhich could be observed on DP values with respect to these changes.\n...\n- We shall think on some new ways to represent these DP Transitions, and Matrices comes to rescue.\n- The idea of the solution is based on Matrix Exponentiation where we represent the transitions between Dp[i] and Dp[i+1] in a $$$K * K$$$ matrix.\n- Now the final Dp values is the product of all N matrices.\n- So for every query, we need to change a matrix at $$$i^{th}$$$ position, and recalculate the product of all matrices.\n...\n- This can be done with the help of Segment-Tree where we maintain a $$$K * K$$$ matrix in each node representing the product of matrices covered by the segment. Every change in transition is a point update and the root node of Segment Tree reveals the final Dp values which we are interested in.\n...\n- The overall time complexity is $$$O(K^3Nlog(N))$$$\n\n---\n\nTitle: Problem - F1 - Codeforces\nURL: https://codeforces.com/contest/2201/problem/F1\nPublished: N/A\nAuthor: N/A\nHighlights:\nF1. Monotone Monochrome Matrices (Medium Version)\n...\nThis is the medium version of the problem. The difference between the versions is that in this version, the constraints on $$$n$$$ and $$$q$$$ are larger. You can hack only if you solved all versions of this problem.\n...\nA monochrome matrix of size $$$n \\times n$$$ is a matrix of $$$n$$$ rows and $$$n$$$ columns, where each cell is colored either black or white. Let the color of cell $$$(r,c)$$$ in a monochrome matrix $$$C$$$ be denoted as $$$C[r,c]$$$.\n...\nLet's call such a matrix $$$C$$$ monotone if it satisfies the following condition:\n...\nThere exist no two rows $$$1 \\le i \\lt j \\le n$$$ and two columns $$$1 \\le k \\lt l \\le n$$$ that satisfy the following three conditions:\n...\n- $$$C[i,k]=C[j,l]$$$;\n- $$$C[j,k]=C[i,l]$$$;\n- $$$C[i,k] \\neq C[j,k]$$$.\n...\nThere is a monochrome matrix $$$M$$$ of size $$$n \\times n$$$, where all cells are initially white. Please solve $$$q$$$ queries of the following kind:\n...\n- $$$r\\;c$$$: Change the color of the cell $$$(r,c)$$$ in $$$M$$$ to black. Then, determine if $$$M$$$ is monotone or not.\n...\nFor each query, it is guaranteed that the color of the cell $$$(r,c)$$$ was white before the query.\n...\nThe first line of each test case contains two integers $$$n$$$ and $$$q$$$ ($$$2 \\le n \\le\n...\n200\\,000$$$, $$$1 \\le q \\le \\min(n^2,200\\,0\n...\n0)$$$).\n...\nEach of the $$$q$$$ following lines contains two integers $$$r_i$$$, $$$c_i$$$ denoting the $$$i$$$-th query ($$$1 \\le r_i,c_i \\le n$$$).\n...\nFor each query, it is guaranteed that the color of the cell $$$(r,c)$$$ was white before the query.\n...\nIt is guaranteed that the\n...\nof $$$q$$$\n...\nall test cases does not exceed $$$200\\,000$$$.\n...\nIn the first test case, $$$M$$$ has size $$$3 \\times 3$$$. The states of $$$M$$$ after each query are as shown below.\n...\n$$$$$$\\quad\\, \\begin{bmatrix} \\square & \\square & \\square\\\\ \\square & \\blacksquare & \\square\\\\ \\square & \\square & \\square \\end{bmatrix} \\to \\begin{bmatrix} \\square & \\square & \\square\\\\ \\square & \\color{red}{\\blacksquare} & \\color{red}{\\square}\\\\ \\square & \\color{red}{\\square} & \\color{red}{\\blacksquare} \\end{bmatrix} \\to \\begin{bmatrix} \\square & \\square & \\square\\\\ \\square & \\blacksquare & \\blacksquare\\\\ \\square & \\square & \\blacksquare \\end{bmatrix} \\\\\\to \\begin{bmatrix} \\square & \\square & \\square\\\\ \\color{red}{\\square} & \\color{red}{\\blacksquare} & \\blacksquare\\\\ \\color{red}{\\blacksquare} & \\color{red}{\\square} & \\blacksquare \\end{bmatrix} \\to \\begin{bmatrix} \\square & \\square & \\square\\\\ \\square & \\blacksquare & \\blacksquare\\\\ \\blacksquare & \\blacksquare & \\blacksquare \\end{bmatrix} \\to \\begin{bmatrix} \\color{red}{\\blacksquare} & \\color{red}{\\square} & \\square\\\\ \\color{red}{\\square} & \\color{red}{\\blacksquare} & \\blacksquare\\\\ \\blacksquare & \\blacksquare & \\blacksquare \\end{bmatrix} \\\\\\to \\begin{bmatrix} \\color{red}{\\blacksquare} & \\blacksquare & \\color{red}{\\square}\\\\ \\color{red}{\\square} & \\blacksquare & \\color{red}{\\blacksquare}\\\\ \\blacksquare & \\blacksquare & \\blacksquare \\end{bmatrix} \\to \\begin{bmatrix} \\blacksquare & \\blacksquare & \\square\\\\ \\blacksquare & \\blacksquare & \\blacksquare\\\\ \\blacksquare & \\blacksquare & \\blacksquare \\end{bmatrix} \\to \\begin{bmatrix} \\blacksquare & \\blacksquare & \\blacksquare\\\\ \\blacksquare & \\blacksquare & \\blacksquare\\\\ \\blacksquare & \\blacksquare & \\blacksquare \\end{bmatrix}$$$$$$\n...\nOn queries where $$$M$$$ is not monotonic, the four squares highlighted in red denote cells that violate the condition stated above.\n\n---\n\nTitle: New Year and Old Subsequence【Matrix+Line Segment Tree+DP】 - Programmer All\nURL: https://www.programmerall.com/article/9298813515/\nPublished: N/A\nAuthor: N/A\nHighlights:\n## New Year and Old Subsequence【Matrix+Line Segment Tree+DP】\n...\nGiven a sequence of numbers, each query for the substring\\([l,r]\\) How many digits must be deleted at least to ensure that the substring has no subsequence\\('2016'\\) But there are subsequences\\('2017'\\)。 \\(4 ≤ n ≤ 200 000, 1 ≤ q ≤ 200 000\\) Title link: https://codeforces.com/contest/750/problem/E\n...\nUse numbers to indicate the following states: \\(0:\\emptyset\\) \\(1：'2'\\) \\(2:'20'\\) \\(3:'201'\\) \\(4:'2017'\\) construct one\\(5\\times 5\\) The transition matrix,\\(mat[i][j]\\) Means\\(i\\) Can the state be transferred to\\(j\\) State, save the minimum cost if possible. Moreover, an intermediate state can be passed between the two\\(k\\) To convert. Minimize through the addition of matrices. For the conversion matrix, the initial value is: divided by the diagonal\\(0\\), The rest are\\(inf\\). Because the initial state\\(i\\) Can only transition to state\\(i\\) There is no need to delete characters, and it is unreachable to switch to other states. Traverse to the\\(x\\) Characters\\(s[x]\\) When, right\\(s[x]\\) Discussion of the situation: s[x]=‘2’: characters\\(2\\) Only affect status\\(0\\)→Status\\(1\\) The process, so by the state\\(0\\) ->Status\\(1\\) No need to delete characters, that is\\(mat[0][1]=0\\), But by state\\(0\\)->Status\\(0\\), Has been destroyed, so in order to maintain the state\\(0\\)->Status \\(0\\) , The characters need to be\\(2\\) The result of the deletion is stored in the conversion matrix, namely\\(mat[0][0]=1\\); And the rest of the state can not add characters\\(2\\) Into other states, so they are all\\(inf\\)。 s[x]=‘0’: character\\(0\\) Will affect the state\\(1\\)->Status\\(2\\) Process, character\\(0,1,7\\) The truth is the same s[x]=‘1’ s[x]=‘7’ s[x]=‘6’: For characters\\(6\\), Because it cannot contain\\(2016\\), So for maintaining the state\\(3（‘201’）\\)->Status\\(3（‘201’）\\), Need to be deleted\\(6\\), Therefore\\(mat[3][3]=1\\); For status\\(4(‘2017’)\\), That is, if you don't delete\\(6\\), It will contain\\(2016\\), So it should be deleted, i.e.\\(mat[4][4]=1\\), The rest will not be dealt with. process and\\(AC\\) Run on automata\\(DP\\) Similar, see the code for details.\n...\n### Code:\n...\n```\n#include<bits/stdc++.h>\n\nusing namespace std;\n...\nconst int inf=0x3f3f3f3f;\nconst int N=2e5+5;\n...\nstruct matrix\n{\n    int mat[5][5];\n    void init()\n    {\n        for(int i=0;i<5;i++)\n            for(int j=0;j<5;j++)\n                mat[i][j]=inf;\n    }\n    matrix operator +(const matrix &b)const\n    {\n        matrix res;\n        for(int i=0;i<5;i++)\n        {\n            for(int j=0;j<5;j++)\n            {\n                res.mat[i][j]=inf;\n                for(int k=0;k<5;k++)\n                    res.mat[i][j]=min(res.mat[i][j],mat[i][k]+b.mat[k][j]);\n            }\n        }\n        return res;\n    }\n}tree[N<<2];\n...\nchar ss[N];\nvoid build(int l,int r,int rt)\n{\n    if(l==r)\n    {//Construct the transfer matrix:\n        tree[rt].init();\n        for(int i=0;i<5;i++) tree[rt].mat[i][i]=0;\n        if(ss[l]=='2') tree[rt].mat[0][0]=1,tree[rt].mat[0][1]=0;\n        if(ss[l]=='0') tree[rt].mat[1][1]=1,tree[rt].mat[1][2]=0;\n        if(ss[l]=='1') tree[rt].mat[2][2]=1,tree[rt].mat[2][3]=0;\n        if(ss[l]=='7') tree[rt].mat[3][3]=1,tree[rt].mat[3][4]=0;\n        if(ss[l]=='6') tree[rt].mat[4][4]=1,tree[rt].mat[3][3]=1;\n        return;\n    }\n    int mid=(l+r)>>1;\n    build(l,mid,rt<<1);\n    build(mid+1,r,rt<<1|1);\n    tree[rt]=tree[rt<<1]+tree[rt<<1|1];\n}\n...\nmatrix query(int l,int r,int L,int R,int rt)\n{\n    if(L<=l&&r<=R)\n        return tree[rt];\n    int mid=(l+r)>>1;\n    matrix res;\n    res.init();\n    for(int i=0;i<5;i++) res.mat[i][i]=0;\n    if(L<=mid) res=res+query(l,mid,L,R,rt<<1);\n    if(R>mid) res=res+query(mid+1,r,L,R,rt<<1|1);\n    return res;\n}\n...\nint main()\n{\n    int n,q,l,r;\n    scanf(\"%d%d\",&n,&q);\n    scanf(\"%s\",ss+1);\n    build(1,n,1);\n    while(q--)\n    {\n        scanf(\"%d%d\",&l,&r);\n        matrix ans=query(1,n,l,r,1);\n        printf(\"%d\\n\",ans.mat[0][4]==inf?-1:ans.mat[0][4]);\n    }\n    return 0;\n}\n\n```\n...\n- Codeforces750E. New Year and Old Subsequence (Line Segment Tree Maintenance DP)\n- New Year and Old Subsequence【Matrix+Line Segment Tree+DP】\n- 【CF750E】New Year and Old Subsequence\n- Luogu_CF750E New Year and Old Subsequence\n- CF750E New Year and Old Subsequence\n- CF750E New Year and Old Subsequence\n- CF750E - New Year and Old Subsequence\n- Codeforces 750E New Year and Old Subsequence line segment tree + dp (see solution)\n- Codeforces 750E New Year and Old Subsequence-Line Segment Tree-Dynamic Programming\n- 【codeforces 750E】New Year and Old Subsequence\n\n---\n\nTitle: Codeforces 750 E New Year and Old Subsequence - 爱码网\nURL: https://www.likecs.com/show-306341613.html\nPublished: N/A\nAuthor: N/A\nHighlights:\nE. New Year and Old Subsequence思路：线段树维护矩阵乘法。 代码：\n...\nstruct Matrix {\n    int a[5][5];\n    inline void init() {\n        memset(a, INF, sizeof a);\n    }\n    inline Matrix operator * (const Matrix & rhs) const {\n        Matrix res;\n        res.init();\n        for (int k = 0; k < 5; ++k) {\n            for (int i = 0; i < 5; ++i) {\n                for (int j = 0; j < 5; ++j) {\n                    res.a[i][j] = min(res.a[i][j], a[i][k]+rhs.a[k][j]);\n                }\n            }\n        }\n        return res;\n    }\n}tree[N<<2];\n...\ninline int push_up(int rt) {\n    tree[rt] = tree[rt<<1]*tree[rt<<1|1];\n}\n...\nvoid build(int rt, int l, int r) {\n    if(l == r) {\n        tree[rt].init();\n        for (int i = 0; i < 5; ++i) tree[rt].a[i][i] = 0;\n        if(s[l] == '2') tree[rt].a[0][1] = 0, tree[rt].a[0][0] = 1;\n        else if(s[l] == '0') tree[rt].a[1][2] = 0, tree[rt].a[1][1] = 1;\n        else if(s[l] == '1') tree[rt].a[2][3] = 0, tree[rt].a[2][2] = 1;\n        else if(s[l] == '7') tree[rt].a[3][4] = 0, tree[rt].a[3][3] = 1;\n        else if(s[l] == '6') tree[rt].a[3][3] = 1, tree[rt].a[4][4] = 1;\n\n        return ;\n    }\n    int m = l+r >> 1;\n    build(ls);\n    build(rs);\n    push_up(rt);\n}\n...\nMatrix query(int L, int R, int rt, int l, int r) {\n    if(L <= l && r <= R) return tree[rt];\n    int m = l+r >> 1;\n    Matrix res;\n    res.init();\n    for (int i = 0; i < 5; ++i) res.a[i][i] = 0;\n    if(L <= m) res = res * query(L, R, ls);\n    if(R > m) res = res* query(L, R, rs);\n    return res;\n}\n...\nint main() {\n    scanf(\"%d %d\", &n, &q);\n    scanf(\"%s\", s+1);\n    build(1, 1, n);\n    while(q--) {\n        scanf(\"%d %d\", &l, &r);\n        Matrix res = query(l, r, 1, 1, n);\n        if(res.a[0][4] == INF) printf(\"-1\\n\");\n        else printf(\"%d\\n\", res.a[0][4]);\n    }\n    return 0;\n}\n\n```\n...\n- [Codeforces 750E]New Year and Old Subsequence 2021-10-20\n- CodeForces - 750E New Year and Old Subsequence 2022-12-23\n- CF750E New Year and Old Subsequence 2021-12-01\n- Codeforces 750E New Year and Old Subsequence - 线段树 - 动态规划 2021-10-05\n- codeforces750E New Year and Old Subsequence 矩阵dp + 线段树 2021-12-29\n- Codeforces 750 F：New Year and Finding Roots 2022-01-30\n\n---\n\nTitle: [Tutorial]Using Segment Trees to solve Dynamic ...\nURL: https://codeforces.com/blog/entry/101210\nPublished: N/A\nAuthor: N/A\nHighlights:\n[Tutorial]Using Segment Trees to solve Dynamic Programming problems - Codeforces\n...\n[Tutorial]Using Segment Trees to solve Dynamic Programming problems\n...\nOne way to implement this solution is to maintain a matrix $$$dp(i, j)$$$ and process it line by line, column by column. It would be highly inefficient to keep the whole matrix in memory at all times. Since the $$$i$$$-th line of the matrix depends only on the $$$i - 1$$$-th line of the matrix, let's try keeping in memory only the previous line and the current line. Note that this is a common trick to reduce memory usage in dynamic programming problems.\n...\n, they differ in at most one position\n...\nThat position is\n...\nIt would be a shame\n...\ncopy the whole line just to change one number in it,\n...\nlet's keep\n...\nmemory only one line\n...\nmodify it accordingly.\n...\nequal to one plus the maximum\n...\nprefix $$$[1\n...\n1]$$$. For an example of how those values change consider the array $$$v = [5, 2, 3, 2, 4, 1, 7, 6]$$$ and check out the following animation (Yellow means query on prefix, red means update on position):\n...\nSo, let's review, we need a data structure that allows us to both query the maximum on a prefix and update a value at a certain position. A simple segment tree is perfect for this job.\n...\nHere is the problem link and here is a sample submission.\n...\nOnce again, we could maintain a tridimensional-array, however that would be highly inefficient. We can observe that the elements with the first dimension $$$i$$$ depend only on elements with the first dimension $$$i - 1$$$. As before, we can reduce memory usage by maintaining only one matrix. We can also observe that since most of the time $$$dp(i, j, h)$$$ is equal to $$$dp(i -1, j, h)$$$, the elements in the matrix rarely change. Since the necessary operations are finding the sum on the prefix of a line and updating an arbitrary value in the matrix, we can maintain it using an array of segment trees. This allows us to solve the above problem in $$$O(NKlogN)$$$ time complexity and with $$$O(NK)$$$ memory.\n...\nThis problem actually appeared in the past here on codeforces. Also, here is a sample submission.\n...\nuse the website\n...\n. A sample submission implementing\n...\nfound here.\n\n---\n\nTitle: #964551 (C++17(gcc12)) No.2697 Range LIS Query - yukicoder\nURL: https://yukicoder.me/submissions/964551\nPublished: N/A\nAuthor: N/A\nHighlights:\ntemplate<class V,int NV> class SegTree_3 {\npublic:\n\tvector<V> ma;\n\tvector<int> S;\n\tV comp(V l,V r){ \n\t\tV z;\n\t\tint a,b,c,d;\n\t\tFOR(a,4) FOR(b,4) z[a][b]=0;\n\t\tfor(a=0;a<=3;a++) for(b=a;b<=3;b++) for(c=b;c<=3;c++) for(d=c;d<=3;d++) {\n\t\t\tz[a][d]=max(z[a][d],l[a][b]+r[c][d]);\n\t\t}\n\t\t\n\t\treturn z;\n\t};\n\tSegTree_3(){\n\t\tma.resize(NV*2);\n\t\tS.resize(NV*2,-1);\n\t};\n\t\n\tV getval(int x,int y,int l=0,int r=NV,int k=1) {\n\t\tif(r<=x || y<=l || y<=x) {\n\t\t\tV z;\n\t\t\tFOR(x,4) FOR(y,4) z[x][y]=0;\n\t\t\t\n\t\t\treturn z;\n\t\t}\n\t\tif(S[k]>=0) {\n\t\t\tauto v=V();\n\t\t\tx=max(x,l);\n\t\t\ty=min(y,r);\n\t\t\tv[S[k]][S[k]]=y-x;\n\t\t\treturn v;\n\t\t}\n\t\tif(x<=l && r<=y) return ma[k];\n\t\treturn comp(getval(x,y,l,(l+r)/2,k*2),getval(x,y,(l+r)/2,r,k*2+1));\n\t}\n\t\n\tvoid update(int x,int y, int v,int l=0,int r=NV,int k=1) {\n\t\tif(l>=r||y<=x) return;\n\t\tif(x<=l && r<=y) {\n\t\t\tS[k]=v;\n\t\t}\n\t\telse if(l < y && x < r) {\n\t\t\tif(S[k]>=0) {\n\t\t\t\tS[2*k]=S[2*k+1]=S[k];\n\t\t\t\tS[k]=-1;\n\t\t\t}\n\t\t\tupdate(x,y,v,l,(l+r)/2,k*2);\n\t\t\tupdate(x,y,v,(l+r)/2,r,k*2+1);\n\t\t\tma[k]=comp(getval(x,y,l,(l+r)/2,k*2),getval(x,y,(l+r)/2,r,k*2+1));\n\t\t}\n\t}\n};\n...\nSegTree_3<array<array<int,4>,4>,1<<18> st;\n\nint N,Q;\nvoid solve() {\n\tint i,j,k,l,r,x,y; string s;\n\t\n\tcin>>N;\n\tFOR(i,N) {\n\t\tcin>>x;\n\t\tst.update(i+1,i+2,x);\n\t}\n\tcin>>Q;\n\twhile(Q--) {\n\t\tint L,R;\n\t\tcin>>i>>L>>R;\n\t\tif(i==1) {\n\t\t\tauto v=st.getval(L,R+1);\n\t\t\tint ma=0;\n\t\t\tFOR(x,4) FOR(y,4) ma=max(ma,v[x][y]);\n\t\t\tcout<<ma<<endl;\n\t\t}\n\t\telse {\n\t\t\tcin>>x;\n\t\t\tst.update(L,R+1,x);\n\t\t}\n\t}\n\t\t\t\n\t\t\n}\n...\nint main(int argc,char** argv){\n\tstring s;int i\n...\nif\n...\n1) ios::\n...\n+=argv[i\n...\nsolve(); return\n...\n;\n}\n\n---\n\nTitle: #676083 (C++17) No.1597 Matrix Sort - yukicoder\nURL: https://yukicoder.me/submissions/676083\nPublished: N/A\nAuthor: N/A\nHighlights:\n#676083 (C++17) No.1597 Matrix Sort - yukicoder\n...\n| 問題 | No.1597 Matrix Sort |\n| --- | --- |\n| コンテスト |\n| ユーザー | このユーザーの提出の表示 sak |\n| 提出日時 | 2021-07-09 22:07:52 |\n| 言語 |\n| 結果 |\n| 実行時間 | 797 ms / 1,500 ms |\n| コード長 | 2,265 bytes |\n| コンパイル時間 | 1,547 ms |\n| コンパイル使用メモリ | 215,920 KB |\n| 実行使用メモリ | 267,136 KB |\n| 最終ジャッジ日時 | 2026-06-21 15:14:11 |\n| 合計ジャッジ時間 |\n...\n12,352 ms |\n...\n| ジャッジサーバーID（参考情報） | judge3_0 / judge1_1\n...\n// ----------------------------------------------------------------------\n// ----------------------------------------------------------------------\n\nstruct SegTree {\n  ll size;\n  vector<ll> pos;\n  SegTree(ll N) { size = 1; while(size<N) size<<=1; pos.resize(2*size,0); }\n  ll operator[](const ll &x) const { return pos[x+size]; }\n\n  void set(ll x, const ll v) { pos[x+size] = v; }\n  void update(ll x, const ll v) { set(x,v); x+=size; while (x>>=1) operate(x); }\n  ll query(ll a, ll b) {\n    ll L = 0, R = 0;\n    for (a+=size, b+=size; a<b; a>>=1, b>>=1) {\n      if (a&1) { L = q(L,pos[a]); a++; }\n      if (b&1) { b--; R = q(pos[b],R); }\n    }\n    return q(L,R);\n  }\n  void operate(ll i) { pos[i] = q(pos[i*2], pos[i*2+1]); }\n  ll q(ll x, ll y) { return x + y; }\n};\n...\nint main() {\n  ll N, K, P; cin >> N >> K >> P;\n  ll A[N]; rep(i,N) cin >> A[i];\n  ll B[N]; rep(i,N) cin >> B[i];\n\n  SegTree st(P); rep(i,N) st.update(B[i],st[B[i]]+1);\n  // rep(mid,P) {\n  //   ll cnt = 0;\n  //   rep(i,N) {\n  //     if (A[i]<=mid) cnt += st.query(mid-A[i],P-A[i]);\n  //     else cnt += st.query(0,P-A[i]) + st.query(P+mid-A[i],P);\n  //   }\n  //   cout << mid << \":\" << cnt << endl;\n  // }\n\n  ll l = 0, r = P-1;\n  while (l!=r) {\n    ll mid = (l+r+1)/2;\n    ll cnt = 0;\n    rep(i,N) {\n      if (A[i]<=mid) cnt += st.query(mid-A[i],P-A[i]);\n      else cnt += st.query(0,P-A[i]) + st.query(P+mid-A[i],P);\n    }\n    if (cnt>=N*N-K+1) l = mid;\n    else r = mid-1;\n  }\n  ll result = l;\n  cout << result << endl;\n  return 0;\n}\n\n---\n\nTitle: #964352 (C++17) No.2697 Range LIS Query - yukicoder\nURL: https://yukicoder.me/submissions/964352\nPublished: N/A\nAuthor: N/A\nHighlights:\ndiff # 964352 \n\n```\n#include <bits/stdc++.h>\nusing namespace std;\n\nstruct SS{int v[5][5],len;};\nusing FF = int;\n...\nclass LazySegmentTree{\n    public:\n    int siz = 1;\n    vector<SS> dat;\n    vector<FF> lazy;\n \n    FF ID = 0;\n    SS op(SS a,SS b){\n        if(a.len == 0) return b;\n        if(b.len == 0) return a;\n        SS ret; ret.len = a.len+b.len;\n        for(int i=1; i<5; i++) for(int k=i; k<5; k++) ret.v[i][k] = 0;\n        for(int i=1; i<5; i++) for(int k=i; k<5; k++) for(int l=k; l<5; l++) for(int m=l; m<5; m++){\n            ret.v[i][m] = max(ret.v[i][m],a.v[i][k]+b.v[l][m]);\n        }\n        return ret;\n    }\n    SS mapping(FF f, SS x){\n        if(f == 0) return x;\n        SS ret; ret.len = x.len;\n        for(int i=1; i<5; i++) for(int k=i; k<5; k++) ret.v[i][k] = 0;\n        ret.v[f][f] = x.len; return ret;\n    }\n    FF composition(FF f, FF g){\n        if(f == ID) return g;\n        if(g == ID) return f;\n        return f;\n    }\n    SS e(){SS ret; ret.len = 0; return ret;}\n    FF id(){return ID;}\n \n    //op区間演算 mapping lazy→data composition lazy→lazy\n    //e 単位元 id map(id,a)=a\n \n    void make(int N){\n        while(siz < N) siz *= 2;\n        dat.resize(siz*2,e());\n        lazy.resize(siz*2,ID);\n    }\n \n    void make2(int N,vector<SS> &A){\n        make(N);\n        for(int i=0; i<N; i++){\n            int pos = i+siz-1;\n            dat.at(pos) = A.at(i);\n        }\n        for(int i=siz-2; i>=0; i--) dat.at(i) = op(dat.at(i*2+1),dat.at(i*2+2));\n    }\n    \n    void eval(int u,int a,int b){\n        if(lazy.at(u) != id()){\n            dat.at(u) = mapping(lazy.at(u),dat.at(u));\n            if(b-a > 1){\n                lazy.at(u*2+1) = composition(lazy.at(u),lazy.at(u*2+1));\n                lazy.at(u*2+2) = composition(lazy.at(u),lazy.at(u*2+2));\n            }\n            lazy.at(u) = id();\n        }\n    }\n \n    void findadd(int L,int R,int a,int b,int u,FF x){\n        eval(u,a,b);\n        if(R <= a || b <= L) return;\n        if(L <= a && b <= R){\n            lazy.at(u) = composition(x,lazy.at(u));\n            eval(u,a,b);\n        }\n        else{\n            findadd(L,R,a,(a+b)/2,u*2+1,x);\n            findadd(L,R,(a+b)/2,b,u*2+2,x);\n            dat.at(u) = op(dat.at(u*2+1),dat.at(u*2+2));\n        }\n    }\n    void update(int L,int R,FF x){findadd(L,R,0,siz,0,x);}\n \n    SS findans(int L,int R,int a,int b,int u){\n        if(R <= a || b <= L) return e();\n        eval(u,a,b);\n        if(L <= a && b <= R) return dat.at(u);\n \n        return op(findans(L,R,a,(a+b)/2,u*2+1),findans(L,R,(a+b)/2,b,u*2+2));\n    }\n \n    SS get(int pos){return findans(pos,pos+1,0,siz,0);}\n    SS rangeans(int l,int r){return findans(l,r,0,siz,0);}\n    SS allrange(){return findans(0,siz,0,siz,0);}\n};\n...\nint main() {\n    ios_base::sync_with_stdio(false);\n    cin.tie(nullptr);\n\n    int N; cin >> N;\n    vector<SS> A(N);\n    for(int i=0; i<N; i++){\n        int a; cin >> a;\n        SS now; now.len = 1;\n        for(int i=1; i<5; i++) for(int k=i; k<5; k++) now.v[i][k] = 0;\n        now.v[a][a] = 1; A.at(i) = now;\n    }\n    LazySegmentTree Z; Z.make2(N,A);\n\n    int Q; cin >> Q;\n    while(Q--){\n        int t,l,r; cin >> t >> l >> r; l--;\n        if(t == 1){\n            SS now = Z.rangeans(l,r);\n            int answer = 0;\n            for(int i=1; i<5; i++) for(int k=i; k<5; k++) answer = max(answer,now.v[i][k]);\n            cout << answer << endl;\n        }\n        if(t == 2){\n            int x; cin >> x;\n            Z.update(l,r,x);\n        }\n    }\n}\n\n---\n\nTitle: Segment Tree Problems\nURL: https://codeforces.com/blog/entry/22616\nPublished: N/A\nAuthor: N/A\nHighlights:\nSegment Tree Problems - Codeforces\n...\nHi :) These are some segment tree problems on codeforces. Ofcourse it is not complete and I hope we will complete it with your help. And great thank to NikaraBika for helping me.\n...\nUPD : more Segment Tree\n...\nClassic : 339D - Xenia and Bit Operations 356A - Knight Tournament 459D - Pashmak and Parmida's problem 61E - Enemy is weak 380C - Sereja and Brackets 474F - Ant colony 292E - Copying Data 501D - Misha and Permutations Summation 220E - Little Elephant and Inversions 338E - Optimize! 19D - Points 351D - Jeff and Removing Periods 515E - Drazil and Park 540E - Infinite Inversions 609F - Frogs and mosquitoes 594D - REQ 455E - Function\n...\nLazy Propagating:\n...\n52C - Circular RMQ 145E - Lucky Queries 558E - A Simple Task 240F - TorCoder 446C - DZY Loves Fibonacci Numbers 115E - Linear Kingdom Races 438D - The Child and Sequence 121E - Lucky Array 610E - Alphabet Permutations 580E - Kefa and Watch\n...\nSegment tree with Vector: 369E - Valera and Queries 610D - Vika and Segments\n...\n- New Year Domino\n...\nSegment Tree & Dp: 474E - Pillars 597C - Subsequences 56E - Domino Principle\n...\nSegment Tree & Bits: 482B - Interesting Array 242E - XOR on Segment\n...\nSegment Tree & Tree: 383C - Propagating tree 343D - Water Tree 173E - Camping Groups 276E - Little Girl and Problem on Trees 396C - On Changing Tree 516D - Drazil and Morning Exercise 375D - Tree and Queries",
            "metadata": {
              "provider": "exa",
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            },
            "title": "Exa Web Search: Codeforces 2257F1 accepted solution C++ matrix segment tree",
            "time": {
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              "end": 1787510110808
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          "messageID": "msg_02fe7696b001KxXfgxb2XpBWxK"
        },
        {
          "type": "tool",
          "tool": "websearch",
          "callID": "call_LiLOfERK84yCeqjsWCmvx4S9",
          "state": {
            "status": "completed",
            "input": {
              "query": "\"Beaver's Jumping Track\" solution code",
              "numResults": 10,
              "livecrawl": "preferred",
              "type": "deep",
              "contextMaxCharacters": 30000
            },
            "output": "Title: Codeforces Round 1117 (Div. 2) Editorial\nURL: https://codeforces.com/blog/entry/156058\nPublished: 2026-08-17T18:35:10.079Z\nAuthor: N/A\nHighlights:\nBad \n\nTerrible \n\n2257F1 - Beaver's Jumping Track (Easy Version) Idea: pskobx, oblememan, egorka5opka\n...\nSince $$$x$$$ is small, we build a segment tree whose vertices store matrices of size $$$x \\times x$$$.\n\nFor an interval of platforms, let $$$c[i][j]$$$ be the minimum penalty if the Beaver starts $$$i$$$ cells after the beginning of the interval and first lands $$$j$$$ cells after its end. Invalid starting positions are ignored.\n\nFor a single platform of length $$$d$$$ and penalty $$$s$$$,\n\n$$$ c[i][j]= \\left( \\left\\lceil\\frac{d+j-i}{x}\\right\\rceil-1 \\right)s, $$$\n\nwhere $$$0\\le i \\lt \\min(d,x)$$$ and $$$0\\le j \\lt x$$$. The last jump leaves the platform and causes no penalty, while all previous jumps stay inside it.\n...\nTo merge two consecutive intervals $$$A$$$ and $$$B$$$, enumerate the first landing position $$$k$$$ in $$$B$$$:\n\n$$$ c_{A+B}[i][j] = \\min_k\\left(c_A[i][k]+c_B[k][j]\\right). $$$\n...\nIf $$$A$$$ contains fewer than $$$x$$$ cells, the Beaver may start directly inside $$$B$$$; in this case, we copy the corresponding values from $$$c_B$$$.\n...\nFor a query $$$[l,r]$$$, obtain the matrix for $$$[l,r-1]$$$ and enumerate the first landing position $$$i$$$ on platform $$$r$$$. The answer is\n...\n$$$ \\min_{0\\le i \\lt \\min(x,d_r)} \\left( c[0][i] + \\left\\lceil\\frac{d_r-i-1}{x}\\right\\rceil s_r \\right). $$$\n...\nThe case $$$l=r$$$ is calculated directly.\n...\nEach update and query takes $$$\\mathcal{O}(x^3\\log n)$$$ time. Memory complexity is $$$\\mathcal{O}(nx^2)$$$. Build is $$$\\mathcal{O}(nx^3)$$$.\n...\nRate the problem\n...\nAmazing \n\nGood \n\nOk \n\nBad \n\nTerrible \n\n2257F2 - Beaver's Jumping Track (Hard Version)\n...\nSurprisingly, the main problem with the solution from F1 is memory, not time. A segment tree stores $$$\\mathcal{O}(n)$$$ matrices, each containing $$$x^2$$$ values. For $$$x=10$$$, this does not fit into the memory limit.\n...\nTo reduce memory usage, divide the platforms into blocks of size $$$B$$$ (for example, $$$B=16$$$). For each block, calculate the matrix of the entire block using the same merging formula as in F1. Then build a segment tree only over these block matrices.\n...\nFor a query, at most two blocks are only partially covered by the required range. Process the platforms in these blocks separately, and use the segment tree to combine all blocks that are fully covered. After an update, recalculate the matrix of the affected block and update it in the segment tree.\n...\nFor a block size $$$B$$$, the memory complexity is $$$\\mathcal{O}\\left(n+\\frac{n}{B}x^2\\right)$$$.\n...\nEach query takes $$$\\mathcal{O}\\left(Bx^2+x^3\\log\\frac{n}{B}\\right)$$$.\n...\nАnd each update takes $$$\\mathcal{O}\\left(Bx^3+x^3\\log\\frac{n}{B}\\right)$$$.\n\n---\n\nTitle: CFTracker\nURL: https://cftracker.netlify.app/\nPublished: N/A\nAuthor: N/A\nHighlights:\nCFTracker\n\n---\n\nTitle: Problemset\nURL: https://codeforces.com/problemset\nPublished: N/A\nAuthor: N/A\nHighlights:\nProblemset - Codeforces\n\n|\n\nProblems\n\nCodeforces(c) Copyright 2010-2026 Mike Mirzayanov\n\nThe only programming contests Web 2.0 platform\n\nServer time: Aug/14/2026 12:51:30 (n1).\n\nDesktop version, switch to mobile version.\n\nPrivacy Policy| Terms and Conditions\n\nSupported by\n\nUser lists\n\n| Name |\n| --- |\n\n---\n\nTitle: Problemset\nURL: https://codeforces.com/problemset?order=by_solved_desc\nPublished: N/A\nAuthor: N/A\nHighlights:\nProblemset - Codeforces\n\n|\n\nProblems\n\nElections in Saransk (hard version)\n\nElections in Saransk (easy version)\n\nbrute force, dp\n\nBrand New Tatar TV Show\n\nGames on the Train\n\nStripe, Token and Two Players\n\nVessels, Heights and Two Versions (Hard Version)\n\nVlad, Misha and Two Arrays\n\nXOR, Expression and Two Binary Numbers\n\nVessels, Heights and Two Versions (Easy Version)\n\nPalindrome, Twelve and Two Terms\n\nbrute force, constructive algorithms, math\n\nEuclid, Sequence and Two Numbers\n\nPermutation Transmission (Difficult Version)\n\nPermutation Transmission (Easy Version)\n\nGoods on the Shelf\n\nbrute force, data structures, implementation, two pointers\n\nCost of a Bracket Sequence\n\nbrute force, math\n\nThe Cake Is a Lie\n\ngreedy, math, number theory, number theory\n\nSeating Arrangement (Hard Version)\n\nSeating Arrangement (Easy Version)\n\ndfs and similar, dp, math, trees\n\nconstructive algorithms, greedy, implementation, two pointers\n\nChipmunk Theo and Equality\n\nGame on Growing Tree\n\nArrange the Numbers in a Circle\n\nMe When Median Problem\n\nbinary search, greedy\n\nWe Be Flipping (Hard Version)\n\nWe Be Flipping (Easy Version)\n\nconstructive algorithms, greedy\n\nSlimes on a Line\n\nMomoyo and the Network\n\nAmanojaku and Sequence (Hard Version)\n\nAmanojaku and Sequence (Easy Version)\n\nSanae, Cross and Color\n\nbinary search, data structures, implementation\n\nCirno and Number (Hard Version)\n\nCirno and Number (Easy Version)\n\nMarisa Steals Reimu's Takeout\n\nbinary search, data structures, math\n\nIt Just Keeps Going Sideways\n\nIt All Went Sideways\n\nbinary search, data structures, dp, greedy\n\nconstructive algorithms, math\n\nmath, number theory\n\nMental Monumental (Hard Version)\n\ndata structures, greedy, math, two pointers\n\nMental Monumental (Easy Version)\n\nbrute force, graphs, greedy, number theory\n\nCovering Points with Circles\n\nbrute force, greedy\n\nA Number Between Two Others\n\nZhily and Mex and Max\n\nZhily and Array Operating\n\nconstructive algorithms, greedy\n\nZhily and Colorful Strings\n\ndivide and conquer, fft, math\n\ndata structures, divide and conquer, trees\n\nZhily and Bracket Swapping\n\nconstructive algorithms, greedy\n\nbinary search, bitmasks, constructive algorithms, interactive\n\nconstructive algorithms, data structures, sortings\n\nconstructive algorithms, math\n\nCodeforces(c) Copyright 2010-2026 Mike Mirzayanov\n\nThe only programming contests Web 2.0 platform\n\nServer time: Jun/14/2026 18:46:43 (k1).\n\nDesktop version, switch to mobile version.\n\nPrivacy Policy| Terms and Conditions\n\nSupported by\n\nUser lists\n\n| Name |\n| --- |\n\n---\n\nTitle: Codehunt\nURL: https://codehunt.cc/\nPublished: N/A\nAuthor: N/A\nHighlights:\nCodehunt\n\nCodehunt\n\n---\n\nTitle: 2018 Grade 5/6 BCC\nURL: https://cemc.uwaterloo.ca/sites/default/files/documents/2024/2018BCCContestSolutions5_6.html\nPublished: N/A\nAuthor: N/A\nHighlights:\n#### Explanation of Answer\n...\n#### Explanation of Answer\n...\n#### Explanation of Answer\n...\n#### Explanation of Answer\n...\n#### Connections to\n...\n#### Explanation of Answer\n...\n### Beaver Jump Challenge\n...\nBeavers take part in an annual challenge. Starting from rock number 0, they jump clockwise from rock to rock. For example, if a beaver jumps 8 times, it ends up on rock number 3:\n...\n0 \\(\\rightarrow\\) 1 \\(\\rightarrow\\) 2 \\(\\rightarrow\\) 3 \\(\\rightarrow\\) 4 \\(\\rightarrow\\) 0 \\(\\rightarrow\\) 1 \\(\\rightarrow\\) 2 \\(\\rightarrow\\) 3\n...\nOne of the beavers showed off and jumped an astonishing 129 times. On which rock did it end up?\n...\n2. 3\n...\n3. 2\n...\n4. 1\n...\n(A) 4\n...\n#### Explanation of Answer\n...\nIf a beaver jumps 5 times, it ends up where it starts. Let’s call it a “lap\". Since \\(129 = 25 \\times 5 + 4\\), the beaver will do 25 laps and have 4 jumps left. In these last four jumps, the beaver goes from rock number 0 to rock number 4.\n...\n#### Connections to Computer Science\n...\nYou may have seen this operation in math class before. It’s part of what you might know as Long Division or Euclidean division which calculates an integer quotient and a remainder.\n...\nIn this case you’re asked to calculate the remainder of 129 when it is divided by 5. Since this operation is used very commonly in computers, it has a name: modulo operation. Usually “%\" or “mod\" is used as an operator. So, for our equation we could write: \\(129\\ \\%\\ 5 = 4\\).\n...\nTypical applications of this operator are in programs containing loops (just like our beaver jumping in loops), and when variables overflow because\n...\nare too big. Modular arithmetic is also used heavily in\n...\nosystems, such as RSA cryptography, used to\n...\nour passwords safe\n...\nCountry of Original Author\n...\n#### Explanation of Answer\n...\n#### Explanation of Answer\n...\n#### Explanation of Answer\n...\n#### Connections to\n...\n#### Explanation of Answer\n...\n#### Explanation of Answer\n\n---\n\nTitle: Year 5 and 6 (ENGLISH VERSION)\nURL: https://www.mathe-kaenguru.de/chronik/aufgaben/downloads/kaenguru2023_56_en.pdf\nPublished: N/A\nAuthor: N/A\nHighlights:\nRabbit, beaver and kangaroo want to jump on the ring track shown. They start at the same time in field A and jump in the direction of the arrow. The beaver jumps in every field, the rabbit in every 3rd field and the kangaroo in every 5th field until they land in field Z. Who needs the smallest number of jumps to do this? (A) the kangaroo (B) the beaver (C) the kangaroo and the beaver (D) the rabbit (E) All three need the same number of jumps.\n\n---\n\nTitle: 2022 Beaver Computing Challenge (Grade 9 & 10) Questions, Answers, Explanations, and Connections\nURL: https://cemc.uwaterloo.ca/sites/default/files/documents/2022/2022BCCContestSolutions9_10.pdf\nPublished: N/A\nAuthor: N/A\nHighlights:\nExplanation of Answer\n...\n### Jumping Game\n...\nVerunka has invented a game to play on her sidewalk. Her sidewalk is 13 squares long and there is a coin on the very last square.\n...\nVerunka marks each square (except the last) with either an or an . Then, she begins playing by jumping on the square labelled START and using the following rules:\n...\n• After landing on a square marked , jump forward 3 squares.\n...\n• After landing on a square marked , jump backwards 1 square.\n...\nVerunka wins if three things happen:\n...\n1. She can always follow the rules (i.e. remain on the sidewalk).\n\n2. She lands on the square with the coin.\n\n3. She visits all 13 squares on the sidewalk.\n...\nFor which marking will Verunka win the game?\n...\nIn Options A and C, Verunka will not be able to follow the rules. That is, she will reach an less than 3 squares from the coin.\n...\nVerunka lands on the square with the coin in Option B, but she does not visit each square along the way. Specifically, she never visits any squares marked with an .\n...\nThe correct answer is Option D as shown. The numbers underneath the squares indicate the order in which Verunka visits them.\n...\nExplanation of Answer\n...\nThis task focusses on tracing a simple algorithm on certain input.\n...\nThe algorithm is fairly straightforward, and can be modelled using a conditional statement: if Verunka lands on an “X” square, then jump forward three squares; if Verunka lands on an “O” square, then jump backwards one square. Many programming languages have the ability to write conditional statements, typically with an if-statement.\n...\nIn order to trace this algorithm, we must keep track of the state, which will change at each jump. The state for this particular task must keep track of the current square that Verunka occupies as well as all the squares that she has visited. In programming languages, this could be implemented by way of an array, where each cell of the array keeps track of whether or not Verunka has jumped there.\n...\nFinally, the input to the algorithm is the sequence of “X” and “O” squares. The input can be viewed as accepted or valid if all squares are visited, and rejected or invalid otherwise. 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1em;\n}\n._StreamsSidebarFrame_frame ._StreamsSidebarFrame_stream ._StreamsSidebarFrame_user {\n  margin: 0 0 0.5em 0;\n  font-size: 0.8em;\n}\n._StreamsSidebarFrame_frame ._StreamsSidebarFrame_stream ._StreamsSidebarFrame_timeMark {\n  color: #777;\n  font-size: 0.9em;\n}\n._StreamsSidebarFrame_frame ._StreamsSidebarFrame_stream:last-of-type {\n  border-bottom: unset;\n  margin: unset;\n  padding: 0 0.5em 0.5em 1em;\n}\n._StreamsSidebarFrame_frame ._viewAll {\n  text-align: right;\n}\n.moreRunningStreamsSidebarNote {\n  color: #777 !important;\n  text-decoration: none;\n}\n</style>\n\n\n<script data-nocturne=\"true\"> $(function () {\n\n}); </script>\n\n<div class=\"roundbox sidebox top-contributed borderTopRound \" style=\"\">\n<div class=\"caption titled\">&rarr; Top rated\n<div class=\"top-links\">\n</div>\n</div>\n<table class=\"rtable \">\n<tbody>\n<tr>\n<th class=\"left\" style=\"width:2.25em;\">#</th>\n<th class=\"\">User</th>\n<th class=\"\" style=\"width:5em;\">Rating</th>\n</tr>\n<tr>\n<td class=\"left dark\">1</td>\n<td class=\" dark\"><a href=\"/profile/Benq\" title=\"Legendary Grandmaster Benq\" class=\"rated-user user-legendary\"><span class=\"legendary-user-first-letter\">B</span>enq</a></td>\n<td class=\" dark\">3857</td>\n</tr>\n<tr>\n<td class=\"left \">2</td>\n<td class=\"\"><a href=\"/profile/jiangly\" title=\"Legendary Grandmaster jiangly\" class=\"rated-user user-legendary\"><span class=\"legendary-user-first-letter\">j</span>iangly</a></td>\n<td class=\"\">3812</td>\n</tr>\n<tr>\n<td class=\"left dark\">3</td>\n<td class=\" dark\"><a href=\"/profile/maroonrk\" title=\"Legendary Grandmaster maroonrk\" class=\"rated-user user-legendary\"><span class=\"legendary-user-first-letter\">m</span>aroonrk</a></td>\n<td class=\" dark\">3536</td>\n</tr>\n<tr>\n<td class=\"left \">4</td>\n<td class=\"\"><a href=\"/profile/tourist\" title=\"Legendary Grandmaster tourist\" class=\"rated-user user-legendary\"><span class=\"legendary-user-first-letter\">t</span>ourist</a></td>\n<td class=\"\">3530</td>\n</tr>\n<tr>\n<td class=\"left dark\">5</td>\n<td class=\" dark\"><a href=\"/profile/Kevin114514\" title=\"Legendary Grandmaster Kevin114514\" class=\"rated-user user-legendary\"><span class=\"legendary-user-first-letter\">K</span>evin114514</a></td>\n<td class=\" dark\">3510</td>\n</tr>\n<tr>\n<td class=\"left \">6</td>\n<td class=\"\"><a href=\"/profile/turmax\" title=\"Legendary Grandmaster turmax\" class=\"rated-user user-legendary\"><span class=\"legendary-user-first-letter\">t</span>urmax</a></td>\n<td class=\"\">3402</td>\n</tr>\n<tr>\n<td class=\"left dark\">7</td>\n<td class=\" dark\"><a href=\"/profile/Um_nik\" title=\"Legendary Grandmaster Um_nik\" class=\"rated-user user-legendary\"><span class=\"legendary-user-first-letter\">U</span>m_nik</a></td>\n<td class=\" dark\">3389</td>\n</tr>\n<tr>\n<td class=\"left \">8</td>\n<td class=\"\"><a href=\"/profile/Radewoosh\" title=\"Legendary Grandmaster Radewoosh\" class=\"rated-user user-legendary\"><span class=\"legendary-user-first-letter\">R</span>adewoosh</a></td>\n<td class=\"\">3367</td>\n</tr>\n<tr>\n<td class=\"left dark\">9</td>\n<td class=\" dark\"><a href=\"/profile/heuristica\" title=\"Legendary Grandmaster heuristica\" class=\"rated-user user-legendary\"><span class=\"legendary-user-first-letter\">h</span>euristica</a></td>\n<td class=\" dark\">3322</td>\n</tr>\n<tr>\n<td class=\"left bottom\">10</td>\n<td class=\"bottom\"><a href=\"/profile/strapple\" title=\"Legendary Grandmaster strapple\" class=\"rated-user user-legendary\"><span class=\"legendary-user-first-letter\">s</span>trapple</a></td>\n<td class=\"bottom\">3308</td>\n</tr>\n</tbody>\n</table>\n<div class=\"bottom-links\">\n<table style=\"width:100%;\">\n<tbody>\n<tr>\n<td style=\"text-align:left;\">\n<a href=\"/ratings/countries\">Countries</a> |\n<a href=\"/ratings/cities\">Cities</a> |\n<a href=\"/ratings/organizations\">Organizations</a>\n</td>\n<td style=\"text-align:right;\">\n<a href=\"/ratings\">View all &rarr;</a>\n</td>\n</tr>\n</tbody>\n</table>\n</div>\n</div><div class=\"roundbox sidebox top-contributed borderTopRound \" style=\"\">\n        <div class=\"caption titled\">&rarr; Top contributors\n            <div class=\"top-links\">\n            </div>\n        </div>\n        <table class=\"rtable \">\n            <tbody>\n                <tr>\n                            <th class=\"left\" style=\"width:2.25em;\">#</th>\n                            <th class=\"\">User</th>\n                            <th class=\"\" style=\"width:5em;\">Contrib.</th>\n                </tr>\n                    <tr>\n                                <td class=\"left  dark\">1</td>\n                                <td class=\" dark\"><a href=\"/profile/Qingyu\" title=\"Legendary Grandmaster Qingyu\" class=\"rated-user user-legendary\"><span class=\"legendary-user-first-letter\">Q</span>ingyu</a></td>\n                                <td class=\" dark\">155</td>\n                    </tr>\n                    <tr>\n                                <td class=\"left \">2</td>\n                                <td class=\"\"><a href=\"/profile/maspy\" title=\"Legendary Grandmaster maspy\" class=\"rated-user user-legendary\"><span class=\"legendary-user-first-letter\">m</span>aspy</a></td>\n                                <td class=\"\">149</td>\n                    </tr>\n                    <tr>\n                                <td class=\"left  dark\">3</td>\n                                <td class=\" dark\"><a href=\"/profile/Um_nik\" title=\"Legendary Grandmaster Um_nik\" class=\"rated-user user-legendary\"><span class=\"legendary-user-first-letter\">U</span>m_nik</a></td>\n                                <td class=\" dark\">144</td>\n                    </tr>\n                    <tr>\n                                <td class=\"left \">4</td>\n                                <td class=\"\"><a href=\"/profile/adamant\" title=\"Master adamant\" class=\"rated-user user-orange\">adamant</a></td>\n                                <td class=\"\">137</td>\n                    </tr>\n                    <tr>\n                                <td class=\"left  dark\">5</td>\n                                <td class=\" dark\"><a href=\"/profile/maroonrk\" title=\"Legendary Grandmaster maroonrk\" class=\"rated-user user-legendary\"><span class=\"legendary-user-first-letter\">m</span>aroonrk</a></td>\n                                <td class=\" dark\">135</td>\n                    </tr>\n                    <tr>\n                                <td class=\"left \">6</td>\n                                <td class=\"\"><a href=\"/profile/Errichto\" title=\"International Grandmaster Errichto\" class=\"rated-user user-red\">Errichto</a></td>\n                                <td class=\"\">133</td>\n                    </tr>\n                    <tr>\n                                <td class=\"left  dark\">6</td>\n                                <td class=\" dark\"><a href=\"/profile/DNR\" title=\"Master DNR\" class=\"rated-user user-orange\">DNR</a></td>\n                                <td class=\" dark\">133</td>\n                    </tr>\n                    <tr>\n                                <td class=\"left \">8</td>\n                                <td class=\"\"><a href=\"/profile/Dominater069\" title=\"Legendary Grandmaster Dominater069\" class=\"rated-user user-legendary\"><span class=\"legendary-user-first-letter\">D</span>ominater069</a></td>\n                                <td class=\"\">131</td>\n                    </tr>\n                    <tr>\n                                <td class=\"left  dark\">9</td>\n                                <td class=\" dark\"><a href=\"/profile/Proof_by_QED\" title=\"Master Proof_by_QED\" class=\"rated-user user-orange\">Proof_by_QED</a></td>\n                                <td class=\" dark\">130</td>\n                    </tr>\n                    <tr>\n                                <td class=\"left bottom\">10</td>\n                                <td class=\"bottom\"><a href=\"/profile/BledDest\" title=\"International Grandmaster BledDest\" class=\"rated-user user-red\">BledDest</a></td>\n                                <td class=\"bottom\">129</td>\n                    </tr>\n            </tbody>\n        </table>\n            <div class=\"bottom-links\">\n                <table style=\"width:100%;\">\n                    <tbody>\n                        <tr>\n                            <td style=\"text-align:left;\">\n                            </td>\n                            <td style=\"text-align:right;\">\n                                    <a href=\"/top-contributed\">View all &rarr;</a>\n                            </td>\n                        </tr>\n                 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type=\"text/javascript\">\n        $(document).ready(function () {\n    $(\".handleBox\").autocompleteHandle();\n    $(\".handleForm\").attr(\"autocomplete\", \"off\").submit(function () {\n        var link = \"/profile/userHandle\".replace(\n            \"userHandle\", $(this).find(\".handleBox\").val()\n        );\n        window.location = link;\n        return false;\n    });\n        });\n    </script>\n\n\n<div class=\"roundbox sidebox borderTopRound \" style=\"\">\n        <div class=\"caption titled\">&rarr; Recent actions\n            <div class=\"top-links\">\n            </div>\n        </div>\n        <div class=\"recent-actions\">\n            <ul>\n                        <li><div style=\"font-size:0.9em;padding:0.5em 0;\">\n<a href=\"/profile/afedor\" title=\"Master afedor\" class=\"rated-user user-orange\">afedor</a>        &rarr;\n        <a href=\"/blog/entry/62889\">List of anime-themed contests</a>\n&nbsp;&nbsp;<img alt=\"New comment(s)\" title=\"New comment(s)\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png\" style=\"vertical-align:middle;\"/>\n        <img alt=\"Necropost\" title=\"Necropost\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/hourglass.png\"  style=\"vertical-align:middle; position: relative; top: 1px;\"/>\n</div>\n</li>\n                        <li><div style=\"font-size:0.9em;padding:0.5em 0;\">\n<a href=\"/profile/night.watchman\" title=\"Pupil night.watchman\" class=\"rated-user user-green\">night.watchman</a>        &rarr;\n        <a href=\"/blog/entry/128725\">CP vs Chess</a>\n&nbsp;&nbsp;<img alt=\"New comment(s)\" title=\"New comment(s)\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png\" style=\"vertical-align:middle;\"/>\n        <img alt=\"Necropost\" title=\"Necropost\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/hourglass.png\"  style=\"vertical-align:middle; position: relative; top: 1px;\"/>\n</div>\n</li>\n                        <li><div style=\"font-size:0.9em;padding:0.5em 0;\">\n<a href=\"/profile/Errichto\" title=\"International Grandmaster Errichto\" class=\"rated-user user-red\">Errichto</a>        &rarr;\n        <a href=\"/blog/entry/156122\">Petition to Display Color of Max Rating</a>\n&nbsp;&nbsp;<img alt=\"New comment(s)\" title=\"New comment(s)\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png\" style=\"vertical-align:middle;\"/>\n</div>\n</li>\n                        <li><div style=\"font-size:0.9em;padding:0.5em 0;\">\n<a href=\"/profile/AmShZ\" title=\"Grandmaster AmShZ\" class=\"rated-user user-red\">AmShZ</a>        &rarr;\n        <a href=\"/blog/entry/156138\">Repovive Premier Round 7 — $300 in Prizes</a>\n&nbsp;&nbsp;<img alt=\"New comment(s)\" title=\"New comment(s)\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png\" style=\"vertical-align:middle;\"/>\n</div>\n</li>\n                        <li><div style=\"font-size:0.9em;padding:0.5em 0;\">\n<a href=\"/profile/Bullet\" title=\"Specialist Bullet\" class=\"rated-user user-cyan\">Bullet</a>        &rarr;\n        <a href=\"/blog/entry/156192\">Invitation to Brain Booster Round #11 (Monday 24 August at 8.30 pm (BST), Rated for all)</a>\n&nbsp;&nbsp;<img alt=\"New comment(s)\" title=\"New comment(s)\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png\" style=\"vertical-align:middle;\"/>\n</div>\n</li>\n                        <li><div style=\"font-size:0.9em;padding:0.5em 0;\">\n<a href=\"/profile/Errichto\" title=\"International Grandmaster Errichto\" class=\"rated-user user-red\">Errichto</a>        &rarr;\n        <a href=\"/blog/entry/155971\">Olympiad Classes by Harbour.Space</a>\n&nbsp;&nbsp;<img alt=\"Text created or updated\" title=\"Text created or updated\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/x-update-12x12.png\" style=\"vertical-align:middle;\"/>\n</div>\n</li>\n                        <li><div style=\"font-size:0.9em;padding:0.5em 0;\">\n<a href=\"/profile/hassanzn04\" title=\"Expert hassanzn04\" class=\"rated-user user-blue\">hassanzn04</a>        &rarr;\n        <a href=\"/blog/entry/155844\">Discussion Regarding lebronjamal&#39;s Recent Performance</a>\n&nbsp;&nbsp;<img alt=\"New comment(s)\" title=\"New comment(s)\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png\" style=\"vertical-align:middle;\"/>\n</div>\n</li>\n                        <li><div style=\"font-size:0.9em;padding:0.5em 0;\">\n<a href=\"/profile/ece2023110\" title=\"Newbie ece2023110\" class=\"rated-user user-gray\">ece2023110</a>        &rarr;\n        <a href=\"/blog/entry/156194\">Built ErithX because most contest trackers feel too noisy</a>\n&nbsp;&nbsp;<img alt=\"Text created or updated\" title=\"Text created or updated\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/x-update-12x12.png\" style=\"vertical-align:middle;\"/>\n</div>\n</li>\n                        <li><div style=\"font-size:0.9em;padding:0.5em 0;\">\n<a href=\"/profile/zeyd1234\" title=\"Specialist zeyd1234\" class=\"rated-user user-cyan\">zeyd1234</a>        &rarr;\n        <a href=\"/blog/entry/155967\">Is Codeforces Div. 2/3 turning into a pure ad-hoc math speedrun?</a>\n&nbsp;&nbsp;<img alt=\"New comment(s)\" title=\"New comment(s)\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png\" style=\"vertical-align:middle;\"/>\n</div>\n</li>\n                        <li><div style=\"font-size:0.9em;padding:0.5em 0;\">\n<a href=\"/profile/Faraz\" title=\"Pupil Faraz\" class=\"rated-user user-green\">Faraz</a>        &rarr;\n        <a href=\"/blog/entry/156190\">Need of some Segtree / Merge sort tree Problems for practice</a>\n&nbsp;&nbsp;<img alt=\"New comment(s)\" title=\"New comment(s)\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png\" style=\"vertical-align:middle;\"/>\n</div>\n</li>\n                        <li><div style=\"font-size:0.9em;padding:0.5em 0;\">\n<a href=\"/profile/codej_40404\" title=\"Specialist codej_40404\" class=\"rated-user user-cyan\">codej_40404</a>        &rarr;\n        <a href=\"/blog/entry/156187\">can i get up to 1600 ratings?</a>\n&nbsp;&nbsp;<img alt=\"New comment(s)\" title=\"New comment(s)\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png\" style=\"vertical-align:middle;\"/>\n</div>\n</li>\n                        <li><div style=\"font-size:0.9em;padding:0.5em 0;\">\n<a href=\"/profile/j.archit\" title=\"Pupil j.archit\" class=\"rated-user user-green\">j.archit</a>        &rarr;\n        <a href=\"/blog/entry/156189\">CF Teleport – Instantly send Codeforces problems and test cases to VS Code.</a>\n&nbsp;&nbsp;<img alt=\"New comment(s)\" title=\"New comment(s)\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png\" style=\"vertical-align:middle;\"/>\n</div>\n</li>\n                        <li><div style=\"font-size:0.9em;padding:0.5em 0;\">\n<a href=\"/profile/Qingyu\" title=\"Legendary Grandmaster Qingyu\" class=\"rated-user user-legendary\"><span class=\"legendary-user-first-letter\">Q</span>ingyu</a>        &rarr;\n        <a href=\"/blog/entry/154559\">assert in GCC 16</a>\n&nbsp;&nbsp;<img alt=\"New comment(s)\" title=\"New comment(s)\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png\" style=\"vertical-align:middle;\"/>\n</div>\n</li>\n                        <li><div style=\"font-size:0.9em;padding:0.5em 0;\">\n<a href=\"/profile/Faraz\" title=\"Pupil Faraz\" class=\"rated-user user-green\">Faraz</a>        &rarr;\n        <a href=\"/blog/entry/155526\">Roll back needed...</a>\n&nbsp;&nbsp;<img alt=\"New comment(s)\" title=\"New comment(s)\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png\" style=\"vertical-align:middle;\"/>\n</div>\n</li>\n                        <li><div style=\"font-size:0.9em;padding:0.5em 0;\">\n<a href=\"/profile/ICPCNews\" title=\"Unrated, ICPCNews\" class=\"rated-user user-black\">ICPCNews</a>        &rarr;\n        <a href=\"/blog/entry/155646\">ICPC Challenge powered by Huawei</a>\n&nbsp;&nbsp;<img alt=\"New comment(s)\" title=\"New comment(s)\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png\" style=\"vertical-align:middle;\"/>\n</div>\n</li>\n                        <li><div style=\"font-size:0.9em;padding:0.5em 0;\">\n<a href=\"/profile/Tsukasa_Tsukuyomi\" title=\"Specialist Tsukasa_Tsukuyomi\" class=\"rated-user user-cyan\">Tsukasa_Tsukuyomi</a>        &rarr;\n        <a href=\"/blog/entry/156182\">Alternate solution to AtCoder ABC472 Problem E — Odd Cycle</a>\n&nbsp;&nbsp;<img alt=\"New comment(s)\" title=\"New comment(s)\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png\" style=\"vertical-align:middle;\"/>\n</div>\n</li>\n                        <li><div style=\"font-size:0.9em;padding:0.5em 0;\">\n<a href=\"/profile/MIRZAPURI\" title=\"Specialist MIRZAPURI\" class=\"rated-user user-cyan\">MIRZAPURI</a>        &rarr;\n        <a href=\"/blog/entry/154928\">Are we necromancers for enjoying a dead thing?</a>\n&nbsp;&nbsp;<img alt=\"New comment(s)\" title=\"New comment(s)\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png\" style=\"vertical-align:middle;\"/>\n</div>\n</li>\n                        <li><div style=\"font-size:0.9em;padding:0.5em 0;\">\n<a href=\"/profile/Tagl\" title=\"Expert Tagl\" class=\"rated-user user-blue\">Tagl</a>        &rarr;\n        <a href=\"/blog/entry/156181\">ICPC Europe Women&#39;s Programming Contest Finals</a>\n&nbsp;&nbsp;<img alt=\"New comment(s)\" title=\"New comment(s)\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png\" style=\"vertical-align:middle;\"/>\n</div>\n</li>\n                        <li><div style=\"font-size:0.9em;padding:0.5em 0;\">\n<a href=\"/profile/_tran.haian_0317.\" title=\"Candidate Master _tran.haian_0317.\" class=\"rated-user user-violet\">_tran.haian_0317.</a>        &rarr;\n        <a href=\"/blog/entry/143734\">Road to Expert</a>\n&nbsp;&nbsp;<img alt=\"New comment(s)\" title=\"New comment(s)\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png\" style=\"vertical-align:middle;\"/>\n        <img alt=\"Necropost\" title=\"Necropost\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/hourglass.png\"  style=\"vertical-align:middle; position: relative; top: 1px;\"/>\n</div>\n</li>\n                        <li><div style=\"font-size:0.9em;padding:0.5em 0;\">\n<a href=\"/profile/htoshiro\" title=\"Expert htoshiro\" class=\"rated-user user-blue\">htoshiro</a>        &rarr;\n        <a href=\"/blog/entry/156005\">dp on a functional graph</a>\n&nbsp;&nbsp;<img alt=\"New comment(s)\" title=\"New comment(s)\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png\" style=\"vertical-align:middle;\"/>\n</div>\n</li>\n                        <li><div style=\"font-size:0.9em;padding:0.5em 0;\">\n<a href=\"/profile/MateoCV\" title=\"Master MateoCV\" class=\"rated-user user-orange\">MateoCV</a>        &rarr;\n        <a href=\"/blog/entry/133298\">[GYM] 2024 Argentinian Programming Tournament (TAP)</a>\n&nbsp;&nbsp;<img alt=\"New comment(s)\" title=\"New comment(s)\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png\" style=\"vertical-align:middle;\"/>\n        <img alt=\"Necropost\" title=\"Necropost\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/hourglass.png\"  style=\"vertical-align:middle; position: relative; top: 1px;\"/>\n</div>\n</li>\n                        <li><div style=\"font-size:0.9em;padding:0.5em 0;\">\n<a href=\"/profile/BledDest\" title=\"International Grandmaster BledDest\" class=\"rated-user user-red\">BledDest</a>        &rarr;\n        <a href=\"/blog/entry/155047\">Educational Codeforces Round 192 Editorial</a>\n&nbsp;&nbsp;<img alt=\"New comment(s)\" title=\"New comment(s)\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png\" style=\"vertical-align:middle;\"/>\n</div>\n</li>\n                        <li><div style=\"font-size:0.9em;padding:0.5em 0;\">\n<a href=\"/profile/PersistentLife\" title=\"Grandmaster PersistentLife\" class=\"rated-user user-red\">PersistentLife</a>        &rarr;\n        <a href=\"/blog/entry/156161\">As an CNOI Gold Medalist: How I Train CNOI Gold Medal Winning Competitive Programmers</a>\n&nbsp;&nbsp;<img alt=\"New comment(s)\" title=\"New comment(s)\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png\" style=\"vertical-align:middle;\"/>\n</div>\n</li>\n                        <li><div style=\"font-size:0.9em;padding:0.5em 0;\">\n<a href=\"/profile/dino_merlin\" title=\"Expert dino_merlin\" class=\"rated-user user-blue\">dino_merlin</a>        &rarr;\n        <a href=\"/blog/entry/155100\">Finally specialist again after 3 long, horrible, exruciating years</a>\n&nbsp;&nbsp;<img alt=\"New comment(s)\" title=\"New comment(s)\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png\" style=\"vertical-align:middle;\"/>\n</div>\n</li>\n                        <li><div style=\"font-size:0.9em;padding:0.5em 0;\">\n<a href=\"/profile/jay_jayjay\" title=\"Master jay_jayjay\" class=\"rated-user user-orange\">jay_jayjay</a>        &rarr;\n        <a href=\"/blog/entry/155979\">TeamsCode Summer 2026 Virtual Programming Contest</a>\n&nbsp;&nbsp;<img alt=\"New comment(s)\" title=\"New comment(s)\" src=\"//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png\" style=\"vertical-align:middle;\"/>\n</div>\n</li>\n            </ul>\n        </div>\n            <div class=\"bottom-links\">\n                <table style=\"width:100%;\">\n                    <tbody>\n                        <tr>\n                            <td style=\"text-align:left;\">\n                            </td>\n                            <td style=\"text-align:right;\">\n                                    <a href=\"/recent-actions\">Detailed &rarr;</a>\n                            </td>\n                        </tr>\n                    </tbody>\n                </table>\n            </div>\n    </div></div>\n                        <div id=\"pageContent\" class=\"content-with-sidebar\">\n<div style=\"margin-bottom:2em;\">\n\n\n<div class=\"has-topic-id topic\" topicId=\"156288\">\n    <div class=\"title\">\n\n...132951 bytes truncated...\n\nThe tool call succeeded but the output was truncated. Full output saved to: /Users/zayd/.local/share/opencode/tool-output/tool_02fe7d792001egqfuhjZbWhLsJ\nUse Grep to search the full content or Read with offset/limit to view specific sections.",
            "metadata": {
              "truncated": true,
              "outputPath": "/Users/zayd/.local/share/opencode/tool-output/tool_02fe7d792001egqfuhjZbWhLsJ"
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            "title": "https://codeforces.com/problemset/submission/2257/387467533?locale=en (text/html;charset=UTF-8)",
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              "end": 1787510118292
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              "timeout": 120
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            "output": "---\nimage: //codeforces.com/codeforces.org/s/99500/images/codeforces-sponsored-by-ton.png\ntitle: Codeforces\ndescription: Codeforces. Programming competitions and contests, programming community\n---\n\n<!DOCTYPE HTML PUBLIC \"-//W3C//DTD HTML 4.01//EN\"> \n\n  \n[![Codeforces](//codeforces.com/codeforces.org/s/99500/images/codeforces-sponsored-by-ton.png \"Codeforces\")](https://codeforces.com/) \n\n[![In English](//codeforces.com/codeforces.org/s/99500/images/flags/24/gb.png \"In English\")](https://codeforces.com/?locale=en) [![По-русски](//codeforces.com/codeforces.org/s/99500/images/flags/24/ru.png \"По-русски\")](https://codeforces.com/?locale=ru) \n\n[Enter](https://codeforces.com/enter?back=%2F)| [Register](https://codeforces.com/register) \n\n  \n* [Home](https://codeforces.com/)\n* [Top](https://codeforces.com/top)\n* [Catalog](https://codeforces.com/catalog)\n* [Contests](https://codeforces.com/contests)\n* [Gym](https://codeforces.com/gyms)\n* [Problemset](https://codeforces.com/problemset)\n* [Groups](https://codeforces.com/groups)\n* [Rating](https://codeforces.com/ratings)\n* [Edu](https://codeforces.com/edu/courses)\n* [API](https://codeforces.com/apiHelp)\n* [Calendar](https://codeforces.com/calendar)\n* [Help](https://codeforces.com/help)\n  \n  \n→ Pay attention \n\nContest is running  \n[ICPC 2026 Online Challenge 1 powered by Huawei](https://codeforces.com/contest/2251/standings)  \n5 days  \n[Register now »](https://codeforces.com/contestRegistration/2251) \n\n→ Top rated \n\n| #  | User                                                                                          | Rating |\n| -- | --------------------------------------------------------------------------------------------- | ------ |\n| 1  | [Benq](https://codeforces.com/profile/Benq \"Legendary Grandmaster Benq\")                      | 3857   |\n| 2  | [jiangly](https://codeforces.com/profile/jiangly \"Legendary Grandmaster jiangly\")             | 3812   |\n| 3  | [maroonrk](https://codeforces.com/profile/maroonrk \"Legendary Grandmaster maroonrk\")          | 3536   |\n| 4  | [tourist](https://codeforces.com/profile/tourist \"Legendary Grandmaster tourist\")             | 3530   |\n| 5  | [Kevin114514](https://codeforces.com/profile/Kevin114514 \"Legendary Grandmaster Kevin114514\") | 3510   |\n| 6  | [turmax](https://codeforces.com/profile/turmax \"Legendary Grandmaster turmax\")                | 3402   |\n| 7  | [Um\\_nik](https://codeforces.com/profile/Um%5Fnik \"Legendary Grandmaster Um_nik\")             | 3389   |\n| 8  | [Radewoosh](https://codeforces.com/profile/Radewoosh \"Legendary Grandmaster Radewoosh\")       | 3367   |\n| 9  | [heuristica](https://codeforces.com/profile/heuristica \"Legendary Grandmaster heuristica\")    | 3322   |\n| 10 | [strapple](https://codeforces.com/profile/strapple \"Legendary Grandmaster strapple\")          | 3308   |\n\n| [Countries](https://codeforces.com/ratings/countries) \\| [Cities](https://codeforces.com/ratings/cities) | [Organizations](https://codeforces.com/ratings/organizations) | [View all →](https://codeforces.com/ratings) |\n| -------------------------------------------------------------------------------------------------------- | ------------------------------------------------------------- | -------------------------------------------- |\n\n→ Top contributors \n\n| #  | User                                                                                             | Contrib. |\n| -- | ------------------------------------------------------------------------------------------------ | -------- |\n| 1  | [Qingyu](https://codeforces.com/profile/Qingyu \"Legendary Grandmaster Qingyu\")                   | 155      |\n| 2  | [maspy](https://codeforces.com/profile/maspy \"Legendary Grandmaster maspy\")                      | 149      |\n| 3  | [Um\\_nik](https://codeforces.com/profile/Um%5Fnik \"Legendary Grandmaster Um_nik\")                | 144      |\n| 4  | [adamant](https://codeforces.com/profile/adamant \"Master adamant\")                               | 137      |\n| 5  | [maroonrk](https://codeforces.com/profile/maroonrk \"Legendary Grandmaster maroonrk\")             | 135      |\n| 6  | [Errichto](https://codeforces.com/profile/Errichto \"International Grandmaster Errichto\")         | 133      |\n| 6  | [DNR](https://codeforces.com/profile/DNR \"Master DNR\")                                           | 133      |\n| 8  | [Dominater069](https://codeforces.com/profile/Dominater069 \"Legendary Grandmaster Dominater069\") | 131      |\n| 9  | [Proof\\_by\\_QED](https://codeforces.com/profile/Proof%5Fby%5FQED \"Master Proof_by_QED\")          | 130      |\n| 10 | [BledDest](https://codeforces.com/profile/BledDest \"International Grandmaster BledDest\")         | 129      |\n\n|  | [View all →](https://codeforces.com/top-contributed) |\n|  | ---------------------------------------------------- |\n\n→ Find user \n\nHandle: \n\n→ Recent actions \n\n* [afedor](https://codeforces.com/profile/afedor \"Master afedor\") → [List of anime-themed contests](https://codeforces.com/blog/entry/62889) ![New comment\\(s\\)](//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png \"New comment(s)\") ![Necropost](//codeforces.com/codeforces.org/s/99500/images/icons/hourglass.png \"Necropost\")\n* [night.watchman](https://codeforces.com/profile/night.watchman \"Pupil night.watchman\") → [CP vs Chess](https://codeforces.com/blog/entry/128725) ![New comment\\(s\\)](//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png \"New comment(s)\") ![Necropost](//codeforces.com/codeforces.org/s/99500/images/icons/hourglass.png \"Necropost\")\n* [Errichto](https://codeforces.com/profile/Errichto \"International Grandmaster Errichto\") → [Petition to Display Color of Max Rating](https://codeforces.com/blog/entry/156122) ![New comment\\(s\\)](//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png \"New comment(s)\")\n* [AmShZ](https://codeforces.com/profile/AmShZ \"Grandmaster AmShZ\") → [Repovive Premier Round 7 — $300 in Prizes](https://codeforces.com/blog/entry/156138) ![New comment\\(s\\)](//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png \"New comment(s)\")\n* [Bullet](https://codeforces.com/profile/Bullet \"Specialist Bullet\") → [Invitation to Brain Booster Round #11 (Monday 24 August at 8.30 pm (BST), Rated for all)](https://codeforces.com/blog/entry/156192) ![New comment\\(s\\)](//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png \"New comment(s)\")\n* [Errichto](https://codeforces.com/profile/Errichto \"International Grandmaster Errichto\") → [Olympiad Classes by Harbour.Space](https://codeforces.com/blog/entry/155971) ![Text created or updated](//codeforces.com/codeforces.org/s/99500/images/icons/x-update-12x12.png \"Text created or updated\")\n* [hassanzn04](https://codeforces.com/profile/hassanzn04 \"Expert hassanzn04\") → [Discussion Regarding lebronjamal's Recent Performance](https://codeforces.com/blog/entry/155844) ![New comment\\(s\\)](//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png \"New comment(s)\")\n* [ece2023110](https://codeforces.com/profile/ece2023110 \"Newbie ece2023110\") → [Built ErithX because most contest trackers feel too noisy](https://codeforces.com/blog/entry/156194) ![Text created or updated](//codeforces.com/codeforces.org/s/99500/images/icons/x-update-12x12.png \"Text created or updated\")\n* [zeyd1234](https://codeforces.com/profile/zeyd1234 \"Specialist zeyd1234\") → [Is Codeforces Div. 2/3 turning into a pure ad-hoc math speedrun?](https://codeforces.com/blog/entry/155967) ![New comment\\(s\\)](//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png \"New comment(s)\")\n* [Faraz](https://codeforces.com/profile/Faraz \"Pupil Faraz\") → [Need of some Segtree / Merge sort tree Problems for practice](https://codeforces.com/blog/entry/156190) ![New comment\\(s\\)](//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png \"New comment(s)\")\n* [codej\\_40404](https://codeforces.com/profile/codej%5F40404 \"Specialist codej_40404\") → [can i get up to 1600 ratings?](https://codeforces.com/blog/entry/156187) ![New comment\\(s\\)](//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png \"New comment(s)\")\n* [j.archit](https://codeforces.com/profile/j.archit \"Pupil j.archit\") → [CF Teleport – Instantly send Codeforces problems and test cases to VS Code.](https://codeforces.com/blog/entry/156189) ![New comment\\(s\\)](//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png \"New comment(s)\")\n* [Qingyu](https://codeforces.com/profile/Qingyu \"Legendary Grandmaster Qingyu\") → [assert in GCC 16](https://codeforces.com/blog/entry/154559) ![New comment\\(s\\)](//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png \"New comment(s)\")\n* [Faraz](https://codeforces.com/profile/Faraz \"Pupil Faraz\") → [Roll back needed...](https://codeforces.com/blog/entry/155526) ![New comment\\(s\\)](//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png \"New comment(s)\")\n* [ICPCNews](https://codeforces.com/profile/ICPCNews \"Unrated, ICPCNews\") → [ICPC Challenge powered by Huawei](https://codeforces.com/blog/entry/155646) ![New comment\\(s\\)](//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png \"New comment(s)\")\n* [Tsukasa\\_Tsukuyomi](https://codeforces.com/profile/Tsukasa%5FTsukuyomi \"Specialist Tsukasa_Tsukuyomi\") → [Alternate solution to AtCoder ABC472 Problem E — Odd Cycle](https://codeforces.com/blog/entry/156182) ![New comment\\(s\\)](//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png \"New comment(s)\")\n* [MIRZAPURI](https://codeforces.com/profile/MIRZAPURI \"Specialist MIRZAPURI\") → [Are we necromancers for enjoying a dead thing?](https://codeforces.com/blog/entry/154928) ![New comment\\(s\\)](//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png \"New comment(s)\")\n* [Tagl](https://codeforces.com/profile/Tagl \"Expert Tagl\") → [ICPC Europe Women's Programming Contest Finals](https://codeforces.com/blog/entry/156181) ![New comment\\(s\\)](//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png \"New comment(s)\")\n* [\\_tran.haian\\_0317.](https://codeforces.com/profile/%5Ftran.haian%5F0317. \"Candidate Master _tran.haian_0317.\") → [Road to Expert](https://codeforces.com/blog/entry/143734) ![New comment\\(s\\)](//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png \"New comment(s)\") ![Necropost](//codeforces.com/codeforces.org/s/99500/images/icons/hourglass.png \"Necropost\")\n* [htoshiro](https://codeforces.com/profile/htoshiro \"Expert htoshiro\") → [dp on a functional graph](https://codeforces.com/blog/entry/156005) ![New comment\\(s\\)](//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png \"New comment(s)\")\n* [MateoCV](https://codeforces.com/profile/MateoCV \"Master MateoCV\") → [\\[GYM\\] 2024 Argentinian Programming Tournament (TAP)](https://codeforces.com/blog/entry/133298) ![New comment\\(s\\)](//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png \"New comment(s)\") ![Necropost](//codeforces.com/codeforces.org/s/99500/images/icons/hourglass.png \"Necropost\")\n* [BledDest](https://codeforces.com/profile/BledDest \"International Grandmaster BledDest\") → [Educational Codeforces Round 192 Editorial](https://codeforces.com/blog/entry/155047) ![New comment\\(s\\)](//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png \"New comment(s)\")\n* [PersistentLife](https://codeforces.com/profile/PersistentLife \"Grandmaster PersistentLife\") → [As an CNOI Gold Medalist: How I Train CNOI Gold Medal Winning Competitive Programmers](https://codeforces.com/blog/entry/156161) ![New comment\\(s\\)](//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png \"New comment(s)\")\n* [dino\\_merlin](https://codeforces.com/profile/dino%5Fmerlin \"Expert dino_merlin\") → [Finally specialist again after 3 long, horrible, exruciating years](https://codeforces.com/blog/entry/155100) ![New comment\\(s\\)](//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png \"New comment(s)\")\n* [jay\\_jayjay](https://codeforces.com/profile/jay%5Fjayjay \"Master jay_jayjay\") → [TeamsCode Summer 2026 Virtual Programming Contest](https://codeforces.com/blog/entry/155979) ![New comment\\(s\\)](//codeforces.com/codeforces.org/s/99500/images/icons/comment-12x12.png \"New comment(s)\")\n\n|  | [Detailed →](https://codeforces.com/recent-actions) |\n|  | --------------------------------------------------- |\n\n[ ICPC Challenge powered by Huawei ](https://codeforces.com/blog/entry/155646) \n\nBy [ICPCNews](https://codeforces.com/profile/ICPCNews \"Unrated, ICPCNews\"), 3 weeks ago, ![In English](//codeforces.com/codeforces.org/s/99500/images/flags/24/gb.png \"In English\") \n\n![text](https://codeforces.com/predownloaded/af/22/af228fee1abb015217d8c524de74898aeff36419.png)\n\n#### Hello, Codeforces!\n\nWe are happy to invite you to an exciting online event: **ICPC Online Challenge powered by Huawei**.\n\n#### This Challenge features the problem\n\nScheduling Algorithm for Collaborative Inference System With the rapid advancement of artificial intelligence, large language model (LLM) services are becoming increasingly integrated into people’s daily lives and work. At the same time, the economic efficiency and data security of these services are receiving greater attention.\n\n**Edge-Cloud Collaborative Inference** has emerged as a promising approach to addressing these challenges. In this architecture, LLM inference is divided between a user’s on-premises edge environment and the cloud. Using a U-shaped split, the first and last layers of the model run on the edge, while the computationally intensive middle layers run in the cloud. This allows private inputs and outputs to remain on the user’s side while cloud resources are used for the heavier computation.\n\nHowever, this architecture requires repeated interaction between the edge and the cloud during both the prefill and decoding stages. When requests are processed sequentially, these interactions can create “bubbles”—periods in which computing resources remain idle while waiting for other parts of the system.\n\nYour challenge is to design a **concurrent scheduling strategy** that:\n\n* maximizes overall system throughput; and\n* ensures that every request satisfies its latency Service Level Objective (SLO).\n\nParticipants will need to carefully coordinate computation and communication across the edge and cloud while balancing throughput and per-request latency requirements.\n\nWe hope you will enjoy this challenging optimization problem inspired by real-world AI infrastructure.\n\n**Start:** August 14, 2026 11:00 UTC (UTC+0)\n\n**Finish:** August 28, 2026 10:59 UTC (UTC+0)\n\n[REGISTER](https://codeforces.com/contestRegistration/2251) \n\n#### Prizes\n\n| Rank                                                                                                                                                                                           | Prize                                                                                                                                                                                   |\n| ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- | --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- |\n| Grand Prize (Rank 1)                                                                                                                                                                           | € 12 000 EUR + [ travel and an invitation to the the 50th Annual ICPC World Finals in a guest role](https://docs.google.com/document/d/1nbqIxp13MKrxoIn5hbA3TCV%5F9ah4b1kVXs1Z291KnOk/) |\n| First Prize (Rank 2-6)                                                                                                                                                                         | € 8,000 EUR                                                                                                                                                                             |\n| Second Prize (Rank 7-16)                                                                                                                                                                       | € 3,000 EUR                                                                                                                                                                             |\n| Third Prize (Rank 17-50):                                                                                                                                                                      | € 800 EUR                                                                                                                                                                               |\n| \\* If the allocated Huawei Challenge prize cannot be delivered to your region for any reason it may be replaced by another prize (if no legal restrictions), at the discretion of the Sponsor. |                                                                                                                                                                                         |\n\nBy participating in this Challenge, you agree to the official [Rules](https://docs.google.com/document/d/1y%5FU1fJpahNUthKYFg1o3E2n99lO1tm7cyjf7%5FNrGJSo/edit?usp=sharing).\n\nThe use of AI tools, including generative AI and AI-assisted coding tools, is permitted during the Challenge. Participants remain fully responsible for the correctness, originality, and compliance of their submissions with all applicable rules.\n\nTo be eligible for a prize, you must register through: <https://icpc.global/regionals/finder/ICPC-Online-Challenge-2026>.\n\nIf you cannot access the rules document, please contact [manager@icpc.global](mailto:manager@icpc.global).\n\nGood luck, and we hope you enjoy this complex yet exciting Challenge!\n\n[Full text and comments »](https://codeforces.com/blog/entry/155646) \n\n![Tags](//codeforces.com/codeforces.org/s/99500/images/blog/tags.png \"Tags\") [icpc](https://codeforces.com/search?query=icpc), [programming](https://codeforces.com/search?query=programming), [icpc challenge](https://codeforces.com/search?query=icpc+challenge), [huawei](https://codeforces.com/search?query=huawei) \n\n* [![Vote: I like it](//codeforces.com/codeforces.org/s/99500/images/actions/voteup-gray.png \"Vote: I like it\")](#)\n* +143\n* [![Vote: I do not like it](//codeforces.com/codeforces.org/s/99500/images/actions/votedown-gray.png \"Vote: I do not like it\")](#)\n\n* [![Author](//codeforces.com/codeforces.org/s/99500/images/blog/user_16x16.png \"Author\")](https://codeforces.com/profile/ICPCNews) [ICPCNews ](https://codeforces.com/profile/ICPCNews)\n* ![Publication date](//codeforces.com/codeforces.org/s/99500/images/blog/date_16x16.png \"Publication date\") 3 weeks ago\n* [![Comments](//codeforces.com/codeforces.org/s/99500/images/blog/comments_16x16.png \"Comments\")](https://codeforces.com/blog/entry/155646#comments) [147 ](https://codeforces.com/blog/entry/155646#comments)\n\n  \n[ Pardis Technology Olympics 2026 — Algorithm & Data Tracks ](https://codeforces.com/blog/entry/155873) \n\nBy [codern\\_org](https://codeforces.com/profile/codern%5Forg \"Unrated, codern_org\"), [history](https://codeforces.com/topic/156515/en11), 13 days ago, ![In English](//codeforces.com/codeforces.org/s/99500/images/flags/24/gb.png \"In English\") \n\n![](https://codeforces.com/predownloaded/2a/15/2a152b93d403ac6b6679522f2358ed0cf864e2bb.png) \n\n💻 Are you ready to test your problem-solving skills and push your limits in the world of algorithms and data processing? The **Technology Olympics 2026** brings you two exciting competitions where creativity, logic, and technical mastery meet high-level challenges—and top teams win prizes!\n\n### 🎈 Algorithm Track\n\n* Preliminary Round (Online): Friday, September 25, 2026\n* Final Round (Onsite – Tehran, Iran): Wednesday, November 3, 2026\n* Closing Ceremony: Thursday, November 4, 2026\n\nThe problems were authored and prepared by [alireza\\_kaviani](https://codeforces.com/profile/alireza%5Fkaviani \"International Grandmaster alireza_kaviani\"), [eren\\_\\_](https://codeforces.com/profile/eren%5F%5F \"Grandmaster eren__\"), [ArshiaDadras](https://codeforces.com/profile/ArshiaDadras \"Master ArshiaDadras\"), [AlefHeKaaf](https://codeforces.com/profile/AlefHeKaaf \"Candidate Master AlefHeKaaf\") and [AiPd](https://codeforces.com/profile/AiPd \"Grandmaster AiPd\").\n\n### 📊 Data Processing Track\n\n* Preliminary Round (Online – 24 Hours): Friday, September 11, 2026\n* Final Round (Onsite – Tehran, Iran): Thursday, November 4, 2026\n* Closing Ceremony: Thursday, November 4, 2026\n\n### 🏆 Prizes for Each Track\n\nTop 5 Teams in Preliminary Round:\n\n* Travel support to Tehran (up to $200 per person)\n* **Hotel accommodation** during the onsite final\n* Meals and refreshments during the event\n* Teams ranked 6th to 10th will also qualify for the onsite final\n\nCash prizes:\n\n* 🥇 1st: **$600**\n* 🥈 2nd: **$450**\n* 🥉 3rd: **$300**\n* 🏅 4th: **$250**\n* 🏅 5th: **$200**\n\nCash prizes will be awarded upon participation in the onsite final. Qualified international teams will also receive travel and accommodation support according to the rules of each track, including:\n\n* Travel support to Tehran (up to $200 per person)\n* Hotel accommodation during the onsite final\n* Meals and refreshments during the event\n* Teams ranked 6th to 10th will also qualify for the onsite final.\n* Qualified teams will be invited to an online briefing webinar before the final round, covering competition rules, travel arrangements, event schedules, submission procedures, evaluation criteria, and other logistical details.\n\n[Register Contest!](https://codern.org/international/contest#contests) \n\n[Full text and comments »](https://codeforces.com/blog/entry/155873) \n\n* [![Vote: I like it](//codeforces.com/codeforces.org/s/99500/images/actions/voteup-gray.png \"Vote: I like it\")](#)\n* +82\n* [![Vote: I do not like it](//codeforces.com/codeforces.org/s/99500/images/actions/votedown-gray.png \"Vote: I do not like it\")](#)\n\n* [![Author](//codeforces.com/codeforces.org/s/99500/images/blog/user_16x16.png \"Author\")](https://codeforces.com/profile/codern%5Forg) [codern\\_org ](https://codeforces.com/profile/codern%5Forg)\n* ![Publication date](//codeforces.com/codeforces.org/s/99500/images/blog/date_16x16.png \"Publication date\") 13 days ago\n* [![Comments](//codeforces.com/codeforces.org/s/99500/images/blog/comments_16x16.png \"Comments\")](https://codeforces.com/blog/entry/155873#comments) [30 ](https://codeforces.com/blog/entry/155873#comments)\n\n  \n[ Codeforces Round 1117 (Div. 2) ](https://codeforces.com/blog/entry/155915) \n\nBy [pskobx](https://codeforces.com/profile/pskobx \"Master pskobx\"), 12 days ago, ![In English](//codeforces.com/codeforces.org/s/99500/images/flags/24/gb.png \"In English\") \n\n### Hello, Codeforces!\n\n**![](https://codeforces.com/predownloaded/cc/d0/ccd0458c062087cf5ebf529724552c8f401920c8.jpg)**\n\nWe are excited and pleased to announce that [Codeforces Round 1117 (Div. 2)](https://codeforces.com/contest/2257 \"Codeforces Round 1117 (Div. 2)\") will be held on [Aug/17/2026 17:35 (Moscow time)](https://www.timeanddate.com/worldclock/fixedtime.html?day=17&month=8&year=2026&hour=17&min=35&sec=0&p1=166). This round will be rated for all participants with rating below $$$2100$$$. You will be given $$$2$$$ hours to solve $$$6$$$ problems and some problems will be divided into subtasks. \n\nAll problems were authored and prepared by [egorka5opka](https://codeforces.com/profile/egorka5opka \"Master egorka5opka\"), [oblememan](https://codeforces.com/profile/oblememan \"Master oblememan\") and me.\n\nWe are extremely grateful to these wonderful people:\n\n* [Akulyat](https://codeforces.com/profile/Akulyat \"Grandmaster Akulyat\") for coordinating the round and assistance in preparing problems;\n* [Um\\_nik](https://codeforces.com/profile/Um%5Fnik \"Legendary Grandmaster Um_nik\") for preliminary review of the round;\n* Our testers: [300iq](https://codeforces.com/profile/300iq \"International Grandmaster 300iq\"), [\\_\\_baozii\\_\\_](https://codeforces.com/profile/%5F%5Fbaozii%5F%5F \"International Grandmaster __baozii__\"), [Tizz1e](https://codeforces.com/profile/Tizz1e \"Expert Tizz1e\"), [Friendiks](https://codeforces.com/profile/Friendiks \"Grandmaster Friendiks\"), [\\_icy\\_](https://codeforces.com/profile/%5Ficy%5F \"Expert _icy_\"), [Wileyne](https://codeforces.com/profile/Wileyne \"Expert Wileyne\"), [Megnis](https://codeforces.com/profile/Megnis \"Newbie Megnis\"), [omsincoconut](https://codeforces.com/profile/omsincoconut \"Candidate Master omsincoconut\"), [\\_istil](https://codeforces.com/profile/%5Fistil \"Grandmaster _istil\"), [AksLolCoding](https://codeforces.com/profile/AksLolCoding \"Grandmaster AksLolCoding\"), [madlogic](https://codeforces.com/profile/madlogic \"Candidate Master madlogic\") for their time and effort in testing the problems.\n\nThe score distribution is below.\n\n$$$500-750-1250-1750−2250−(2750+1000)$$$\n\n**GLHF!**\n\n**UPD1** For those who were affected by the incorrect constraints on problem D and wish for the round not to affect their rating, please leave a comment stating \"I don't want the round to be rated for me\" in the \"Ask a question\" section found on the main contest page under the problems.  \nThis applies only to those who were genuinely affected, meaning you must have received a TL (or any other suitable verdict) for that problem.\n\n**UPD1.1** Requests are accepted until [Tuesday, August 18, 2026 at 12:00UTC](https://www.timeanddate.com/worldclock/fixedtime.html?day=18&month=8&year=2026&hour=15&min=00&sec=0&p1=166) (please note the timezone).  \nThe rollback will be done after that. \n\n**UPD2** [Editorial](https://codeforces.com/blog/entry/156058)\n\n**UPD3** Winners and First to solve\n\nOfficial participants:\n\n| Place | Participant                                                                                       |\n| ----- | ------------------------------------------------------------------------------------------------- |\n| 1     | [Payea](https://codeforces.com/profile/Payea \"Candidate Master Payea\")                            |\n| 2     | [azizs](https://codeforces.com/profile/azizs \"Candidate Master azizs\")                            |\n| 3     | [mahath\\_b.1](https://codeforces.com/profile/mahath%5Fb.1 \"Expert mahath_b.1\")                    |\n| 4     | [lady\\_\\_hunter](https://codeforces.com/profile/lady%5F%5Fhunter \"Candidate Master lady__hunter\") |\n| 5     | [naixinganhuoyyp](https://codeforces.com/profile/naixinganhuoyyp \"Expert naixinganhuoyyp\")        |\n\nUnofficial participants:\n\n| Place | Participant                                                                                 |\n| ----- | ------------------------------------------------------------------------------------------- |\n| 1     | [Zexistu](https://codeforces.com/profile/Zexistu \"Candidate Master Zexistu\")                |\n| 2     | [maspy](https://codeforces.com/profile/maspy \"Legendary Grandmaster maspy\")                 |\n| 3     | [PiGoat](https://codeforces.com/profile/PiGoat \"Master PiGoat\")                             |\n| 4     | [potato167](https://codeforces.com/profile/potato167 \"International Grandmaster potato167\") |\n| 5     | [xl123](https://codeforces.com/profile/xl123 \"Newbie xl123\")                                |\n\nFirst to solve:\n\n| Task | Participant                                                                                  |\n| ---- | -------------------------------------------------------------------------------------------- |\n| A    | [veizxz\\_\\_](https://codeforces.com/profile/veizxz%5F%5F \"Unrated, veizxz__\")                |\n| B    | [wangzeyu2013](https://codeforces.com/profile/wangzeyu2013 \"Candidate Master wangzeyu2013\")  |\n| C    | [Zexistu](https://codeforces.com/profile/Zexistu \"Candidate Master Zexistu\")                 |\n| D    | [Gouransh06](https://codeforces.com/profile/Gouransh06 \"Unrated, Gouransh06\")                |\n| E    | [IBACKFORREVENGE](https://codeforces.com/profile/IBACKFORREVENGE \"Unrated, IBACKFORREVENGE\") |\n| F1   | [NDesku](https://codeforces.com/profile/NDesku \"Candidate Master NDesku\")                    |\n| F2   | [hungcubuso1vn](https://codeforces.com/profile/hungcubuso1vn \"Master hungcubuso1vn\")         |\n\n[Full text and comments »](https://codeforces.com/blog/entry/155915) \n\n![](//codeforces.com/codeforces.org/s/99500/images/icons/paperclip-16x16.png) Announcement of [Codeforces Round 1117 (Div. 2)](https://codeforces.com/contest/2257) \n\n* [![Vote: I like it](//codeforces.com/codeforces.org/s/99500/images/actions/voteup-gray.png \"Vote: I like it\")](#)\n* +105\n* [![Vote: I do not like it](//codeforces.com/codeforces.org/s/99500/images/actions/votedown-gray.png \"Vote: I do not like it\")](#)\n\n* [![Author](//codeforces.com/codeforces.org/s/99500/images/blog/user_16x16.png \"Author\")](https://codeforces.com/profile/pskobx) [pskobx ](https://codeforces.com/profile/pskobx)\n* ![Publication date](//codeforces.com/codeforces.org/s/99500/images/blog/date_16x16.png \"Publication date\") 12 days ago\n* [![Comments](//codeforces.com/codeforces.org/s/99500/images/blog/comments_16x16.png \"Comments\")](https://codeforces.com/blog/entry/155915#comments) [147 ](https://codeforces.com/blog/entry/155915#comments)\n\n  \n[ Codeforces Round 1116 (Div. 1, Div. 2) ](https://codeforces.com/blog/entry/155668) \n\nBy [paulzrm](https://codeforces.com/profile/paulzrm \"Grandmaster paulzrm\"), 3 weeks ago, ![In English](//codeforces.com/codeforces.org/s/99500/images/flags/24/gb.png \"In English\") \n\nHello, Codeforces!\n\nWe are glad to invite you to participate in [Codeforces Round 1116 (Div. 1)](https://codeforces.com/contest/2255 \"Codeforces Round 1116 (Div. 1)\") and [Codeforces Round 1116 (Div. 2)](https://codeforces.com/contest/2256 \"Codeforces Round 1116 (Div. 2)\") on [Aug/09/2026 17:35 (Moscow time)](https://www.timeanddate.com/worldclock/fixedtime.html?day=9&month=8&year=2026&hour=17&min=35&sec=0&p1=166).\n\nThe round will be rated for participants from both divisions. You will be given **6 problems** and **2 hours and 30 minutes** to solve them. At least one of the problems will be divided into subtasks.\n\nPlease note that this contest contains **at least one run-twice (communication) problem**. Please read the guides for [run-twice problems](https://codeforces.com/blog/entry/147996) before the contest if you are unfamiliar with them.\n\nAll problems were authored and prepared by [Error\\_Yuan](https://codeforces.com/profile/Error%5FYuan \"Grandmaster Error_Yuan\") and me, [paulzrm](https://codeforces.com/profile/paulzrm \"Grandmaster paulzrm\").\n\nMore than eight years after [Codeforces Round 449](https://codeforces.com/blog/entry/56101), **Chtholly Nota Seniorious — the happiest girl in the world — is returning to Codeforces!**\n\nIn this round, you will once again meet Chtholly, Nephren, Ithea, Willem, and other characters from [What Do You Do at the End of the World? Are You Busy? Will You Save Us?](https://en.wikipedia.org/wiki/WorldEnd), and help them overcome a new series of challenges.\n\n![](https://codeforces.com/predownloaded/ae/00/ae00282775d937b7ec7ee69d83b1aaccfb65e232.png) \n\nWe would like to thank:\n\n* [Error\\_Yuan](https://codeforces.com/profile/Error%5FYuan \"Grandmaster Error_Yuan\") for his excellent coordination, patient guidance, and invaluable help throughout the preparation of the round.\n* [Alexdat2000](https://codeforces.com/profile/Alexdat2000 \"Master Alexdat2000\") for translating the statements to Russian.\n* [HugeWide](https://codeforces.com/profile/HugeWide \"International Grandmaster HugeWide\"), my teammate, for VIP testing and for all his help throughout the preparation of the round.\n* [HHH666666](https://codeforces.com/profile/HHH666666 \"Grandmaster HHH666666\"), [XG0000](https://codeforces.com/profile/XG0000 \"Master XG0000\"), [Mitsukasa\\_Ayase](https://codeforces.com/profile/Mitsukasa%5FAyase \"International Grandmaster Mitsukasa_Ayase\"), [zt17](https://codeforces.com/profile/zt17 \"Expert zt17\"), [a\\_little\\_cute](https://codeforces.com/profile/a%5Flittle%5Fcute \"International Master a_little_cute\"), [aaa\\_Pigeon2](https://codeforces.com/profile/aaa%5FPigeon2 \"International Grandmaster aaa_Pigeon2\"), [StarSilk](https://codeforces.com/profile/StarSilk \"Legendary Grandmaster StarSilk\"), [tiger2005](https://codeforces.com/profile/tiger2005 \"Legendary Grandmaster tiger2005\"), [Proof\\_by\\_QED](https://codeforces.com/profile/Proof%5Fby%5FQED \"Master Proof_by_QED\"), [\\_istil](https://codeforces.com/profile/%5Fistil \"Grandmaster _istil\"), [nifeshe](https://codeforces.com/profile/nifeshe \"Grandmaster nifeshe\"), [floptron1](https://codeforces.com/profile/floptron1 \"Candidate Master floptron1\"), [arvindr9](https://codeforces.com/profile/arvindr9 \"Master arvindr9\") and [WorldWarV](https://codeforces.com/profile/WorldWarV \"Candidate Master WorldWarV\") for testing the round and providing valuable feedback.\n* [KAN](https://codeforces.com/profile/KAN \"Legendary Grandmaster KAN\") and [MikeMirzayanov](https://codeforces.com/profile/MikeMirzayanov \"Headquarters, MikeMirzayanov\") for the great Codeforces and Polygon platforms.\n* [You](https://codeforces.com/profile/) for participating in this round.\n\nThe scoring distribution will be announced later.\n\nWe hope you enjoy the problems and Chtholly’s story.\n\n**Good luck and have fun!**\n\n**UPD1**: The Scoring distribution is:\n\n* Div. 1: 500 — 1000 — 1750 — 1750 — (1750 + 1250) — 3500\n* Div. 2: 500 — 1000 — 1500 — 2000 — 2750 — 3000\n\n**UPD2:** The [editorial](https://codeforces.com/blog/entry/155840) is out.\n\n**UPD3:** Congratulations to the winners!\n\nDiv. 1 (subject to change):\n\n1. [turmax](https://codeforces.com/profile/turmax \"Legendary Grandmaster turmax\")\n2. [noimi](https://codeforces.com/profile/noimi \"Legendary Grandmaster noimi\")\n3. [maspy](https://codeforces.com/profile/maspy \"Legendary Grandmaster maspy\")\n4. [squareOf105](https://codeforces.com/profile/squareOf105 \"Legendary Grandmaster squareOf105\")\n5. [Milmon](https://codeforces.com/profile/Milmon \"International Grandmaster Milmon\")\n\nDiv. 2 (subject to change):\n\n1. [lvsedeqinglvse](https://codeforces.com/profile/lvsedeqinglvse \"Candidate Master lvsedeqinglvse\")\n2. [Cucumber0721](https://codeforces.com/profile/Cucumber0721 \"Newbie Cucumber0721\")\n3. [Smarth\\_coder](https://codeforces.com/profile/Smarth%5Fcoder \"Expert Smarth_coder\")\n4. [asterunee](https://codeforces.com/profile/asterunee \"Specialist asterunee\")\n5. [Chth\\_kitten](https://codeforces.com/profile/Chth%5Fkitten \"Candidate Master Chth_kitten\")\n\nWe would also like to congratulate the first solvers of each problem (subject to change):\n\n1. Div. 2 A: [Forestmy17](https://codeforces.com/profile/Forestmy17 \"Expert Forestmy17\") 00:01\n2. Div. 2 B: [asterunee](https://codeforces.com/profile/asterunee \"Specialist asterunee\") 00:04\n3. Div. 1 A / Div. 2 C: [A\\_G](https://codeforces.com/profile/A%5FG \"International Grandmaster A_G\") 00:02\n4. Div. 1 B / Div. 2 D: [maspy](https://codeforces.com/profile/maspy \"Legendary Grandmaster maspy\") 00:05\n5. Div. 1 C / Div. 2 E: [literalchild](https://codeforces.com/profile/literalchild \"International Grandmaster literalchild\") 00:19\n6. Div. 1 D / Div. 2 F: [de1uxegg](https://codeforces.com/profile/de1uxegg \"Master de1uxegg\") 00:23\n7. Div. 1 E1: [\\_\\_baozii\\_\\_](https://codeforces.com/profile/%5F%5Fbaozii%5F%5F \"International Grandmaster __baozii__\") 01:02\n8. Div. 1 E2: [ABCaCaCa\\_](https://codeforces.com/profile/ABCaCaCa%5F \"Master ABCaCaCa_\") 01:10\n9. Div. 1 F: [turmax](https://codeforces.com/profile/turmax \"Legendary Grandmaster turmax\") 01:34\n\n[Full text and comments »](https://codeforces.com/blog/entry/155668) \n\n![](//codeforces.com/codeforces.org/s/99500/images/icons/paperclip-16x16.png) Announcement of [Codeforces Round 1116 (Div. 1)](https://codeforces.com/contest/2255) \n\n![](//codeforces.com/codeforces.org/s/99500/images/icons/paperclip-16x16.png) Announcement of [Codeforces Round 1116 (Div. 2)](https://codeforces.com/contest/2256) \n\n* [![Vote: I like it](//codeforces.com/codeforces.org/s/99500/images/actions/voteup-gray.png \"Vote: I like it\")](#)\n* +445\n* [![Vote: I do not like it](//codeforces.com/codeforces.org/s/99500/images/actions/votedown-gray.png \"Vote: I do not like it\")](#)\n\n* [![Author](//codeforces.com/codeforces.org/s/99500/images/blog/user_16x16.png \"Author\")](https://codeforces.com/profile/paulzrm) [paulzrm ](https://codeforces.com/profile/paulzrm)\n* ![Publication date](//codeforces.com/codeforces.org/s/99500/images/blog/date_16x16.png \"Publication date\") 3 weeks ago\n* [![Comments](//codeforces.com/codeforces.org/s/99500/images/blog/comments_16x16.png \"Comments\")](https://codeforces.com/blog/entry/155668#comments) [125 ](https://codeforces.com/blog/entry/155668#comments)\n\n  \n[ Educational Codeforces Round 193 \\[rated for Div. 2\\] ](https://codeforces.com/blog/entry/155718) \n\nBy [BledDest](https://codeforces.com/profile/BledDest \"International Grandmaster BledDest\"), 3 weeks ago, translation, ![In English](//codeforces.com/codeforces.org/s/99500/images/flags/24/gb.png \"In English\") \n\n![Neapolis University Pafos](https://codeforces.com/predownloaded/9a/33/9a332fadbb47050ba9405057df022a6e37eaf5c0.png)\n\nHello Codeforces!\n\nThe series of Educational Rounds continues thanks to the support of the [Neapolis University Pafos](https://www.nup.ac.cy/). They offer a BSc in Computer Science and AI with [JetBrains Scholarships](https://lp.jetbrains.com/academy/csai-program/). Gain cutting-edge skills in AI and machine learning, preparing you for high-demand tech careers. Limited scholarships available — don't miss your chance to study in Europe for free!\n\n[Educational Codeforces Round 193 (Rated for Div. 2)](https://codeforces.com/contest/2253 \"Educational Codeforces Round 193 (Rated for Div. 2)\") will start on [Aug/07/2026 17:35 (Moscow time)](https://www.timeanddate.com/worldclock/fixedtime.html?day=7&month=8&year=2026&hour=17&min=35&sec=0&p1=166).\n\nThis round will be **rated for the participants with rating lower than 2100**. It will be held on extended ICPC rules. The penalty for each incorrect submission until the submission with a full solution is 10 minutes. After the end of the contest, you will have 12 hours to hack any solution you want. You will have access to copy any solution and test it locally.\n\nYou will be given **6 problems** and **2 hours** to solve them.\n\nThe problems were proposed and prepared by Maxim [FelixArg](https://codeforces.com/profile/FelixArg \"Master FelixArg\") Novotochinov and me.\n\nHuge thanks to Mike [MikeMirzayanov](https://codeforces.com/profile/MikeMirzayanov \"Headquarters, MikeMirzayanov\") Mirzayanov, the creator of Codeforces and Polygon — two great competitive programming platforms. Without them, the Educational Rounds would be impossible.\n\nAlso, big shoutout to round testers: [awoo](https://codeforces.com/profile/awoo \"Master awoo\"), [Alenochka](https://codeforces.com/profile/Alenochka \"Expert Alenochka\"), [pusheen\\_1024](https://codeforces.com/profile/pusheen%5F1024 \"Specialist pusheen_1024\"), [savolay](https://codeforces.com/profile/savolay \"Pupil savolay\"), [yegor.l](https://codeforces.com/profile/yegor.l \"Newbie yegor.l\")!\n\nWe wish you good luck in the contest!\n\n**upd:** [The editorial can be found here](https://codeforces.com/blog/entry/155813).\n\n[Full text and comments »](https://codeforces.com/blog/entry/155718) \n\n![](//codeforces.com/codeforces.org/s/99500/images/icons/paperclip-16x16.png) Announcement of [Educational Codeforces Round 193 (Rated for Div. 2)](https://codeforces.com/contest/2253) \n\n* [![Vote: I like it](//codeforces.com/codeforces.org/s/99500/images/actions/voteup-gray.png \"Vote: I like it\")](#)\n* +95\n* [![Vote: I do not like it](//codeforces.com/codeforces.org/s/99500/images/actions/votedown-gray.png \"Vote: I do not like it\")](#)\n\n* [![Author](//codeforces.com/codeforces.org/s/99500/images/blog/user_16x16.png \"Author\")](https://codeforces.com/profile/BledDest) [BledDest ](https://codeforces.com/profile/BledDest)\n* ![Publication date](//codeforces.com/codeforces.org/s/99500/images/blog/date_16x16.png \"Publication date\") 3 weeks ago\n* [![Comments](//codeforces.com/codeforces.org/s/99500/images/blog/comments_16x16.png \"Comments\")](https://codeforces.com/blog/entry/155718#comments) [123 ](https://codeforces.com/blog/entry/155718#comments)\n\n  \n[ Codeforces Round 1115 (Div. 2) ](https://codeforces.com/blog/entry/155601) \n\nBy [Bufu](https://codeforces.com/profile/Bufu \"Candidate Master Bufu\"), 3 weeks ago, ![In English](//codeforces.com/codeforces.org/s/99500/images/flags/24/gb.png \"In English\") \n\n# _Hello, Codeforces!_\n\nWe are excited to invite you to participate in [Codeforces Round 1115 (Div. 2)](https://codeforces.com/contest/2252), which will take place on [Aug/06/2026 17:35 (Moscow time)](https://www.timeanddate.com/worldclock/fixedtime.html?day=6&month=8&year=2026&hour=17&min=35&sec=0&p1=166).\n\nThe round will be **rated for all participants with a rating below 2100**. Participants from Division 1 are warmly welcome to participate unofficially.\n\nYou will be given **6 problems** and **2 hours** to solve them.\n\nThe round was prepared by [TomitaMatei](https://codeforces.com/profile/TomitaMatei \"Master TomitaMatei\") and me, [Bufu](https://codeforces.com/profile/Bufu \"Candidate Master Bufu\").\n\nWe would like to express our deepest gratitude to everyone who made this round possible:\n\n* [cry](https://codeforces.com/profile/cry \"International Master cry\") for their excellent coordination and infinite patience while reviewing the problems!\n* [Alexdat2000](https://codeforces.com/profile/Alexdat2000 \"Master Alexdat2000\") for translating the statements to Russian.\n* [Um\\_nik](https://codeforces.com/profile/Um%5Fnik \"Legendary Grandmaster Um_nik\") and [KAN](https://codeforces.com/profile/KAN \"Legendary Grandmaster KAN\") for pre-reviewing the round!\n* Our wonderful team of testers for solving the problems and providing highly valuable feedback: [Intellegent](https://codeforces.com/profile/Intellegent \"International Master Intellegent\"), [awesomeguy856](https://codeforces.com/profile/awesomeguy856 \"Grandmaster awesomeguy856\"), [\\_istil](https://codeforces.com/profile/%5Fistil \"Grandmaster _istil\"), [andrei\\_n](https://codeforces.com/profile/andrei%5Fn \"Expert andrei_n\"), [Friedrich](https://codeforces.com/profile/Friedrich \"Candidate Master Friedrich\"), [\\_\\_baozii\\_\\_](https://codeforces.com/profile/%5F%5Fbaozii%5F%5F \"International Grandmaster __baozii__\"), [simplelife](https://codeforces.com/profile/simplelife \"Expert simplelife\"), [omsincoconut](https://codeforces.com/profile/omsincoconut \"Candidate Master omsincoconut\"), [madlogic](https://codeforces.com/profile/madlogic \"Candidate Master madlogic\"), [nik\\_exists](https://codeforces.com/profile/nik%5Fexists \"Expert nik_exists\"), [Edeeva](https://codeforces.com/profile/Edeeva \"Candidate Master Edeeva\"), [SpyrosAliv](https://codeforces.com/profile/SpyrosAliv \"Candidate Master SpyrosAliv\"), and [Argentum47](https://codeforces.com/profile/Argentum47 \"Candidate Master Argentum47\").\n* [MikeMirzayanov](https://codeforces.com/profile/MikeMirzayanov \"Headquarters, MikeMirzayanov\") and [KAN](https://codeforces.com/profile/KAN \"Legendary Grandmaster KAN\") for creating and maintaining the amazing Codeforces and Polygon platforms!\n* [You](https://codeforces.com/profile) for participating in the round!\n\nThe score distribution will be:\n\n**$$$500$$$ — $$$1000$$$ — $$$1250$$$ — $$$1750$$$ — $$$2250$$$ — $$$2750$$$**\n\nGood luck, have fun, and may the rating be with you!\n\n**UPD**: Congratulations to the winners!\n\nUnofficial participants:\n\n1. [abc864197532](https://codeforces.com/profile/abc864197532 \"International Grandmaster abc864197532\")\n2. [Rubikun](https://codeforces.com/profile/Rubikun \"Grandmaster Rubikun\")\n3. [maspy](https://codeforces.com/profile/maspy \"Legendary Grandmaster maspy\")\n4. [CryptoQuant](https://codeforces.com/profile/CryptoQuant \"Master CryptoQuant\")\n5. [Lynkcat](https://codeforces.com/profile/Lynkcat \"Legendary Grandmaster Lynkcat\")\n\nOfficial participants: (subject to change)\n\n1. [Kodik](https://codeforces.com/profile/Kodik \"Expert Kodik\")\n2. [sahajoydeep467](https://codeforces.com/profile/sahajoydeep467 \"Specialist sahajoydeep467\")\n3. [Wonter](https://codeforces.com/profile/Wonter \"Candidate Master Wonter\")\n4. [jeduardobras](https://codeforces.com/profile/jeduardobras \"Expert jeduardobras\")\n5. [Gemini17](https://codeforces.com/profile/Gemini17 \"Expert Gemini17\")\n\n**UPD 2**: The [editorial](https://codeforces.com/blog/entry/155741) is now available!\n\n[Full text and comments »](https://codeforces.com/blog/entry/155601) \n\n![](//codeforces.com/codeforces.org/s/99500/images/icons/paperclip-16x16.png) Announcement of [Codeforces Round 1115 (Div. 2)](https://codeforces.com/contest/2252) \n\n* [![Vote: I like it](//codeforces.com/codeforces.org/s/99500/images/actions/voteup-gray.png \"Vote: I like it\")](#)\n* +184\n* [![Vote: I do not like it](//codeforces.com/codeforces.org/s/99500/images/actions/votedown-gray.png \"Vote: I do not like it\")](#)\n\n* [![Author](//codeforces.com/codeforces.org/s/99500/images/blog/user_16x16.png \"Author\")](https://codeforces.com/profile/Bufu) [Bufu ](https://codeforces.com/profile/Bufu)\n* ![Publication date](//codeforces.com/codeforces.org/s/99500/images/blog/date_16x16.png \"Publication date\") 3 weeks ago\n* [![Comments](//codeforces.com/codeforces.org/s/99500/images/blog/comments_16x16.png \"Comments\")](https://codeforces.com/blog/entry/155601#comments) [158 ](https://codeforces.com/blog/entry/155601#comments)\n\n  \n[ Codeforces Round 1114 (Div. 3) ](https://codeforces.com/blog/entry/155597) \n\nBy [yse](https://codeforces.com/profile/yse \"Candidate Master yse\"), 3 weeks ago, ![In English](//codeforces.com/codeforces.org/s/99500/images/flags/24/gb.png \"In English\") \n\n## Hello, Codeforces!\n\nI am very excited to invite you to participate in [Codeforces Round 1114 (Div. 3)](https://codeforces.com/contest/2254 \"Codeforces Round 1114 (Div. 3)\"), which will take place on [Aug/04/2026 17:35 (Moscow time)](https://www.timeanddate.com/worldclock/fixedtime.html?day=4&month=8&year=2026&hour=17&min=35&sec=0&p1=166). You will be given $$$2$$$ hours and $$$15$$$ minutes to solve $$$7$$$ problems, where one problem will be split into subtasks. All problems were authored and prepared by me.\n\nThe round will be hosted by rules of educational rounds (extended ICPC). Thus, all solutions will be judged on preliminary tests during the round, and after the round, there will be a 12-hour phase of **open hacks**. After the open hack phase, all accepted solutions will be rejudged on successful hacks. Also, note that there is no score distribution but the usual penalty of **10 minutes** for each wrong submission, following the rules of educational rounds.\n\n[Remember](https://codeforces.com/blog/entry/59228) that only the trusted participants of the third division will be included in the official standings table. As it is written by link, this is a compulsory measure for combating unsporting behavior. To qualify as a _trusted participant of the third division_, you must:\n\n* take part in at least five rated rounds (and solve at least one problem in each of them)\n* do not have a rating of 1900 or higher at any moment in time.\n\nRegardless of whether you are a trusted participant of the third division or not, if your rating is less than 1600, then the round will be rated for you (unless you register unrated).\n\nI would like to thank the following people for making this round possible:\n\n* [cry](https://codeforces.com/profile/cry \"International Master cry\") for coordinating the round;\n* [\\_\\_baozii\\_\\_](https://codeforces.com/profile/%5F%5Fbaozii%5F%5F \"International Grandmaster __baozii__\") for red testing;\n* [temporary1](https://codeforces.com/profile/temporary1 \"Master temporary1\"), [Proof\\_by\\_QED](https://codeforces.com/profile/Proof%5Fby%5FQED \"Master Proof_by_QED\") for orange testing;\n* [SpyrosAliv](https://codeforces.com/profile/SpyrosAliv \"Candidate Master SpyrosAliv\"), [Argentum47](https://codeforces.com/profile/Argentum47 \"Candidate Master Argentum47\"), [Friedrich](https://codeforces.com/profile/Friedrich \"Candidate Master Friedrich\"), [omsincoconut](https://codeforces.com/profile/omsincoconut \"Candidate Master omsincoconut\"), [wakanda-forever](https://codeforces.com/profile/wakanda-forever \"Candidate Master wakanda-forever\"), [reirugan](https://codeforces.com/profile/reirugan \"Candidate Master reirugan\"), [cgmoreda](https://codeforces.com/profile/cgmoreda \"Candidate Master cgmoreda\") for purple testing;\n* [DivinePunishment](https://codeforces.com/profile/DivinePunishment \"Expert DivinePunishment\"), [Mousa](https://codeforces.com/profile/Mousa \"Expert Mousa\"), [Wageeh](https://codeforces.com/profile/Wageeh \"Expert Wageeh\"), [wuhudsm](https://codeforces.com/profile/wuhudsm \"Expert wuhudsm\"), [chromate00](https://codeforces.com/profile/chromate00 \"Expert chromate00\"), [detective...dots](https://codeforces.com/profile/detective...dots \"Expert detective...dots\"), [Borhom](https://codeforces.com/profile/Borhom \"Expert Borhom\") for blue testing;\n* [Mr\\_Bald](https://codeforces.com/profile/Mr%5FBald \"Specialist Mr_Bald\"), [ALnQ417](https://codeforces.com/profile/ALnQ417 \"Specialist ALnQ417\") for cyan testing;\n* [Vladosiya](https://codeforces.com/profile/Vladosiya \"Expert Vladosiya\") for statement translation and testing;\n* [MikeMirzayanov](https://codeforces.com/profile/MikeMirzayanov \"Headquarters, MikeMirzayanov\") for developing Codeforces and Polygon.\n\nGood luck, and most importantly, have fun!\n\n#### Update: [Tutorial](https://codeforces.com/blog/entry/155666)\n\n[Full text and comments »](https://codeforces.com/blog/entry/155597) \n\n![](//codeforces.com/codeforces.org/s/99500/images/icons/paperclip-16x16.png) Announcement of [Codeforces Round 1114 (Div. 3)](https://codeforces.com/contest/2254) \n\n* [![Vote: I like it](//codeforces.com/codeforces.org/s/99500/images/actions/voteup-gray.png \"Vote: I like it\")](#)\n* +212\n* [![Vote: I do not like it](//codeforces.com/codeforces.org/s/99500/images/actions/votedown-gray.png \"Vote: I do not like it\")](#)\n\n* [![Author](//codeforces.com/codeforces.org/s/99500/images/blog/user_16x16.png \"Author\")](https://codeforces.com/profile/yse) [yse ](https://codeforces.com/profile/yse)\n* ![Publication date](//codeforces.com/codeforces.org/s/99500/images/blog/date_16x16.png \"Publication date\") 3 weeks ago\n* [![Comments](//codeforces.com/codeforces.org/s/99500/images/blog/comments_16x16.png \"Comments\")](https://codeforces.com/blog/entry/155597#comments) [162 ](https://codeforces.com/blog/entry/155597#comments)\n\n  \n[ Codeforces Round 1113 (Div. 2) ](https://codeforces.com/blog/entry/155549) \n\n\n...20220 bytes truncated...\n\nThe tool call succeeded but the output was truncated. 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              "order": 1,
              "content": "Do not expand the platforms into cells; their total length can be enormous. Instead, look at what happens when a path leaves an interval. Since one jump has length at most $x$, its first landing after the interval is only $0,1,\\ldots,x-1$ cells past the interval's right boundary."
            },
            {
              "order": 2,
              "content": "Represent an interval by an $x\\times x$ matrix $M$. Let $M[a][b]$ be the minimum penalty when the Beaver starts $a$ cells after the interval's left boundary and first lands $b$ cells after its right boundary. For a short interval, also let a state that already lies past the interval pass through with cost $0$; this small convention makes skipped platforms work automatically."
            },
            {
              "order": 3,
              "content": "For one platform of length $d$ and penalty $s$, an actual start $a<d$ and exit offset $b$ have distance $d+b-a$. The minimum number of jumps is $\\left\\lceil\\frac{d+b-a}{x}\\right\\rceil$; only the last jump leaves the platform and is free. Hence\n$$M[a][b]=\\left(\\left\\lceil\\frac{d+b-a}{x}\\right\\rceil-1\\right)s.$$\nIf $a\\ge d$, set only $M[a][a-d]=0$."
            },
            {
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              "content": "For consecutive intervals $A$ and $B$, condition on the offset $k$ of the first landing after $A$:\n$$M_{A+B}[a][b]=\\min_k\\bigl(M_A[a][k]+M_B[k][b]\\bigr).$$\nThis is min-plus matrix multiplication, so it is associative. Store these products in a segment tree; changing either $d_i$ or $s_i$ changes only one leaf."
            },
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              "content": "For a query $[l,r]$ with $l<r$, get the matrix product for platforms $l,\\ldots,r-1$ and take its row $0$. If its value at offset $i$ is $v_i$, then the first landing on platform $r$ is its cell $i$, and finishing costs $\\left\\lceil\\frac{d_r-1-i}{x}\\right\\rceil s_r$. Therefore\n$$\\min_{0\\le i<\\min(x,d_r)}\\left(v_i+\\left\\lceil\\frac{d_r-1-i}{x}\\right\\rceil s_r\\right).$$\nFor $l=r$, only that final-platform term with $i=0$ remains."
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          "editorial": "Expanding every platform into cells is dead on arrival: the total length can reach $10^{13}$. The useful fact is not that each platform is short. It is that every **jump** is short, with $x\\le 5$.\n\n## Boundary states\n\nGive an interval of platforms local coordinates. Its first cell has coordinate $0$, and if the interval contains $L$ cells, its cells have coordinates $0$ through $L-1$.\n\nSuppose the Beaver starts inside this interval. Consider the first landing at or after coordinate $L$. The preceding position was at most $L-1$, and the jump length is at most $x$, so that landing has coordinate at most $L+x-1$. Therefore, only these $x$ exit positions matter:\n\n$$L, L+1, \\ldots, L+x-1.$$\n\nFor an interval $I$, define an $x\\times x$ matrix $M_I$ as follows. For $0\\le a,b<x$ and $a<L$,\n\n$$M_I[a][b]$$\n\nis the minimum penalty of a route that starts at coordinate $a$ and whose first landing outside $I$ is exactly coordinate $L+b$.\n\nThere is one annoying case: an interval can contain fewer than $x$ cells. During a later merge, a jump may skip that whole interval, or a represented starting position may already be in the next interval. We remove the annoyance with a virtual convention:\n\n- If $a\\ge L$, set $M_I[a][a-L]=0$.\n- Set every other entry in that row to infinity.\n\nThis means, \"we are already past this interval, so shift the offset and do nothing.\" It is not a real zero-length jump. It is only algebraic glue. Without it, short platforms create ugly special cases everywhere, which is generally where bugs breed and start paying rent.\n\n## One platform\n\nConsider one platform with length $d$ and penalty $s$. Start at its cell with offset $a<d$, and require the first outside landing to have offset $b$. The total displacement is\n\n$$D=d+b-a.$$\n\nEvery jump has length at most $x$, so at least\n\n$$t=\\left\\lceil\\frac{D}{x}\\right\\rceil$$\n\njumps are necessary. This number is also achievable while keeping every landing except the last one inside the platform. Intuitively, reserve a sufficiently long final jump across the boundary and distribute the remaining distance among the earlier jumps.\n\nThe first $t-1$ jumps start and end on this platform, so each costs $s$. The last jump lands outside it and costs nothing. Thus\n\n$$M[a][b]=(t-1)s=\\left(\\left\\lceil\\frac{d+b-a}{x}\\right\\rceil-1\\right)s.$$\n\nFor rows with $a\\ge d$, use the virtual transition $M[a][a-d]=0$ described above. This constructs a leaf matrix in $O(x^2)$ time.\n\nIn code, every ceiling division uses\n\n$$\\left\\lceil\\frac{u}{x}\\right\\rceil=\\frac{u+x-1}{x}$$\n\nwith integer division.\n\n## Joining intervals\n\nLet $A$ and $B$ be consecutive intervals. Take any route represented by the matrix of $A+B$, and inspect its first landing at or after the end of $A$. Let its offset from that boundary be $k$.\n\nThe part before that landing is represented by $M_A[a][k]$. From that exact position onward, the remaining route is represented by $M_B[k][b]$. Therefore,\n\n$$M_{A+B}[a][b]=\\min_{0\\le k<x}\\left(M_A[a][k]+M_B[k][b]\\right).$$\n\nThis also covers both awkward-looking situations:\n\n- If the start position is already inside $B$, a virtual row of $A$ shifts it into the correct row of $B$.\n- If the jump leaving $A$ skips all of $B$, a virtual row of $B$ shifts that landing to an exit position of $A+B$.\n\nConversely, any two transitions joined at the same $k$ form a valid route through $A+B$. So the formula is exact, not merely a relaxation.\n\nThe operation is ordinary matrix multiplication with `+` replacing multiplication and `min` replacing addition. In other words, it is a min-plus product. It is associative, which is the entire reason a segment tree can enter the chat.\n\n## Segment tree\n\nBuild one leaf matrix for each platform. Each internal node stores the min-plus product of its left child's matrix and then its right child's matrix. Padding leaves use the min-plus identity matrix: zero on the diagonal and infinity elsewhere.\n\nA length or penalty update changes only one platform matrix. Rebuild that leaf and all its ancestors.\n\nFor a range query, matrix order matters. Decompose the range into the usual $O(\\log n)$ canonical segment-tree nodes and process those nodes strictly from left to right.\n\nWe only need row $0$ of the range product, not the entire product. Start with a vector\n\n$$dp[0]=0,\\qquad dp[i]=\\infty\\text{ for }i>0.$$\n\nWhen appending a node matrix $M$, update\n\n$$next[b]=\\min_a\\left(dp[a]+M[a][b]\\right).$$\n\nApplying one matrix costs $O(x^2)$, so a query for the needed row costs $O(x^2\\log n)$ instead of multiplying full matrices in $O(x^3\\log n)$. The segment tree still stores full matrices because updates must rebuild arbitrary ancestors.\n\nA useful side effect is that changing a platform length still affects only one leaf. Global cell coordinates shift, but every matrix uses coordinates relative to its own boundaries, and composition handles the shifts automatically.\n\n## Finishing a query\n\nFor a query $[l,r]$ with $l<r$, query the product for platforms $l,l+1,\\ldots,r-1$. Starting state $0$ means the first cell of platform $l$.\n\nAfter applying that product, let $dp[i]$ be the minimum cost when the first landing after platform $r-1$ is offset $i$ into platform $r$. Only\n\n$$0\\le i<\\min(x,d_r)$$\n\nare valid, because landing at $i\\ge d_r$ would skip the destination platform, and the Beaver cannot move backward.\n\nFrom offset $i$, the last cell is $d_r-1-i$ cells ahead. The minimum number of remaining jumps is\n\n$$\\left\\lceil\\frac{d_r-1-i}{x}\\right\\rceil.$$\n\nEvery one of those jumps starts and lands on platform $r$, so every one costs $s_r$. The answer is\n\n$$\\boxed{\\min_{0\\le i<\\min(x,d_r)}\\left(dp[i]+\\left\\lceil\\frac{d_r-1-i}{x}\\right\\rceil s_r\\right)}.$$\n\nIf $l=r$, the Beaver starts at offset $0$ of the final platform, so the answer directly becomes\n\n$$\\left\\lceil\\frac{d_l-1}{x}\\right\\rceil s_l.$$\n\n## Correctness proof\n\n**Lemma 1.** The leaf matrix of one platform has the stated meaning.\n\nFor an actual start $a<d$, reaching the required exit needs displacement $d+b-a$, hence at least $t=\\left\\lceil(d+b-a)/x\\right\\rceil$ jumps. Such a route exists with only its last landing outside the platform. Exactly its first $t-1$ jumps have both endpoints on the platform, so its minimum penalty is $(t-1)s$. For $a\\ge d$, the virtual transition changes only the coordinate origin and has cost $0$. Thus every leaf entry is correct.\n\n**Lemma 2.** The min-plus product of two consecutive interval matrices correctly represents their concatenation.\n\nEvery valid route has a unique first landing at or after the boundary between the intervals; call its offset $k$. Splitting there gives costs represented by the two matrix entries, so the route's cost appears in the product. Conversely, joining two represented routes at the same $k$ gives a valid route through the concatenation. Virtual rows correctly cover starts or landings that skip a short interval. Taking the minimum over $k$ therefore gives exactly the optimum.\n\n**Lemma 3.** Every segment-tree node stores the correct matrix for its interval.\n\nLeaves are correct by Lemma 1. Each internal node concatenates its two children using the correct operation from Lemma 2. Induction on the tree proves the claim.\n\n**Lemma 4.** The query formula returns the minimum cost for $[l,r]$.\n\nBy Lemma 3, the queried matrices produce the minimum cost for every possible first landing offset $i$ on platform $r$. From such an offset, the shortest route to its last cell uses $\\left\\lceil(d_r-1-i)/x\\right\\rceil$ internal jumps, each costing $s_r$. Every complete route has exactly one such first offset, and every considered prefix plus suffix is valid. Minimizing over all valid $i$ therefore returns precisely the optimum.\n\n**Theorem.** Every printed answer is the minimum possible penalty after all preceding updates.\n\nUpdates rebuild the changed leaf and all affected ancestors, preserving Lemma 3. Lemma 4 then proves every subsequent answer.\n\n## Complexity\n\nLet the segment-tree size be the next power of two above $n$.\n\n- Building takes $O(nx^3)$ time.\n- A length or penalty update takes $O(x^3\\log n)$ time.\n- An answer query takes $O(x^2\\log n+x)$ time.\n- Memory use is $O(nx^2)$.\n\nAll costs require `long long`: valid answers can be close to $10^{18}$. The implementation uses a larger finite infinity whose additions still fit in signed 64-bit arithmetic.",
          "solution": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nvoid setIO() {\n    ios::sync_with_stdio(false);\n    cin.tie(nullptr);\n}\n\nconstexpr int MAX_X = 5;\nconstexpr ll INF = 4'000'000'000'000'000'000LL;\n\nint x;\n\nstruct Matrix {\n    ll a[MAX_X * MAX_X];\n};\n\nMatrix identityMatrix() {\n    Matrix m;\n    fill(begin(m.a), end(m.a), INF);\n    for (int i = 0; i < x; ++i) {\n        m.a[i * MAX_X + i] = 0;\n    }\n    return m;\n}\n\nMatrix platformMatrix(int d, int s) {\n    Matrix m;\n    fill(begin(m.a), end(m.a), INF);\n\n    for (int i = 0; i < x; ++i) {\n        if (i < d) {\n            for (int j = 0; j < x; ++j) {\n                ll distance = (ll)d + j - i;\n                ll jumps = (distance + x - 1) / x;\n                m.a[i * MAX_X + j] = (jumps - 1) * s;\n            }\n        } else {\n            // The represented position already lies beyond this short platform.\n            m.a[i * MAX_X + (i - d)] = 0;\n        }\n    }\n    return m;\n}\n\ninline void compose(Matrix& out, const Matrix& left, const Matrix& right) {\n    for (int i = 0; i < x; ++i) {\n        for (int j = 0; j < x; ++j) {\n            ll best = INF;\n            for (int k = 0; k < x; ++k) {\n                best = min(best,\n                           left.a[i * MAX_X + k] + right.a[k * MAX_X + j]);\n            }\n            out.a[i * MAX_X + j] = best;\n        }\n    }\n}\n\nstruct SegmentTree {\n    int size = 1;\n    unique_ptr<Matrix[]> tree;\n\n    SegmentTree(const vector<int>& d, const vector<int>& s) {\n        while (size < (int)d.size()) {\n            size <<= 1;\n        }\n        tree.reset(new Matrix[2 * size]);\n\n        Matrix id = identityMatrix();\n        for (int i = 0; i < size; ++i) {\n            tree[size + i] = i < (int)d.size() ? platformMatrix(d[i], s[i]) : id;\n        }\n        for (int p = size - 1; p > 0; --p) {\n            compose(tree[p], tree[p * 2], tree[p * 2 + 1]);\n        }\n    }\n\n    void update(int pos, const Matrix& value) {\n        int p = size + pos;\n        tree[p] = value;\n        for (p >>= 1; p > 0; p >>= 1) {\n            compose(tree[p], tree[p * 2], tree[p * 2 + 1]);\n        }\n    }\n\n    array<ll, MAX_X> rangeRow(int l, int r) const {\n        int leftNodes[32], rightNodes[32];\n        int leftCount = 0, rightCount = 0;\n\n        for (l += size, r += size; l < r; l >>= 1, r >>= 1) {\n            if (l & 1) {\n                leftNodes[leftCount++] = l++;\n            }\n            if (r & 1) {\n                rightNodes[rightCount++] = --r;\n            }\n        }\n\n        array<ll, MAX_X> dp;\n        dp.fill(INF);\n        dp[0] = 0;\n\n        auto apply = [&](int node) {\n            array<ll, MAX_X> next;\n            next.fill(INF);\n            for (int j = 0; j < x; ++j) {\n                for (int i = 0; i < x; ++i) {\n                    next[j] = min(next[j],\n                                  dp[i] + tree[node].a[i * MAX_X + j]);\n                }\n            }\n            dp = next;\n        };\n\n        for (int i = 0; i < leftCount; ++i) {\n            apply(leftNodes[i]);\n        }\n        for (int i = rightCount - 1; i >= 0; --i) {\n            apply(rightNodes[i]);\n        }\n        return dp;\n    }\n};\n\nint main() {\n    setIO();\n\n    int n, q;\n    cin >> n >> q >> x;\n\n    vector<int> d(n), s(n);\n    for (int& value : d) {\n        cin >> value;\n    }\n    for (int& value : s) {\n        cin >> value;\n    }\n\n    SegmentTree seg(d, s);\n\n    while (q--) {\n        char type;\n        cin >> type;\n\n        if (type == '1') {\n            int i, value;\n            cin >> i >> value;\n            --i;\n            d[i] = value;\n            seg.update(i, platformMatrix(d[i], s[i]));\n        } else if (type == '2') {\n            int i, value;\n            cin >> i >> value;\n            --i;\n            s[i] = value;\n            seg.update(i, platformMatrix(d[i], s[i]));\n        } else {\n            int l, r;\n            cin >> l >> r;\n            --l;\n            --r;\n\n            if (l == r) {\n                ll distance = (ll)d[l] - 1;\n                cout << (distance + x - 1) / x * s[l] << '\\n';\n                continue;\n            }\n\n            auto dp = seg.rangeRow(l, r);\n            ll answer = INF;\n            for (int i = 0; i < min(x, d[r]); ++i) {\n                ll distance = (ll)d[r] - 1 - i;\n                ll jumps = (distance + x - 1) / x;\n                answer = min(answer, dp[i] + jumps * s[r]);\n            }\n            cout << answer << '\\n';\n        }\n    }\n}"
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                {
                  "order": 1,
                  "content": "Do not expand the platforms into cells; their total length can be enormous. Instead, look at what happens when a path leaves an interval. Since one jump has length at most $x$, its first landing after the interval is only $0,1,\\ldots,x-1$ cells past the interval's right boundary."
                },
                {
                  "order": 2,
                  "content": "Represent an interval by an $x\\times x$ matrix $M$. Let $M[a][b]$ be the minimum penalty when the Beaver starts $a$ cells after the interval's left boundary and first lands $b$ cells after its right boundary. For a short interval, also let a state that already lies past the interval pass through with cost $0$; this small convention makes skipped platforms work automatically."
                },
                {
                  "order": 3,
                  "content": "For one platform of length $d$ and penalty $s$, an actual start $a<d$ and exit offset $b$ have distance $d+b-a$. The minimum number of jumps is $\\left\\lceil\\frac{d+b-a}{x}\\right\\rceil$; only the last jump leaves the platform and is free. Hence\n$$M[a][b]=\\left(\\left\\lceil\\frac{d+b-a}{x}\\right\\rceil-1\\right)s.$$\nIf $a\\ge d$, set only $M[a][a-d]=0$."
                },
                {
                  "order": 4,
                  "content": "For consecutive intervals $A$ and $B$, condition on the offset $k$ of the first landing after $A$:\n$$M_{A+B}[a][b]=\\min_k\\bigl(M_A[a][k]+M_B[k][b]\\bigr).$$\nThis is min-plus matrix multiplication, so it is associative. Store these products in a segment tree; changing either $d_i$ or $s_i$ changes only one leaf."
                },
                {
                  "order": 5,
                  "content": "For a query $[l,r]$ with $l<r$, get the matrix product for platforms $l,\\ldots,r-1$ and take its row $0$. If its value at offset $i$ is $v_i$, then the first landing on platform $r$ is its cell $i$, and finishing costs $\\left\\lceil\\frac{d_r-1-i}{x}\\right\\rceil s_r$. Therefore\n$$\\min_{0\\le i<\\min(x,d_r)}\\left(v_i+\\left\\lceil\\frac{d_r-1-i}{x}\\right\\rceil s_r\\right).$$\nFor $l=r$, only that final-platform term with $i=0$ remains."
                }
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              "editorial": "Expanding every platform into cells is dead on arrival: the total length can reach $10^{13}$. The useful fact is not that each platform is short. It is that every **jump** is short, with $x\\le 5$.\n\n## Boundary states\n\nGive an interval of platforms local coordinates. Its first cell has coordinate $0$, and if the interval contains $L$ cells, its cells have coordinates $0$ through $L-1$.\n\nSuppose the Beaver starts inside this interval. Consider the first landing at or after coordinate $L$. The preceding position was at most $L-1$, and the jump length is at most $x$, so that landing has coordinate at most $L+x-1$. Therefore, only these $x$ exit positions matter:\n\n$$L, L+1, \\ldots, L+x-1.$$\n\nFor an interval $I$, define an $x\\times x$ matrix $M_I$ as follows. For $0\\le a,b<x$ and $a<L$,\n\n$$M_I[a][b]$$\n\nis the minimum penalty of a route that starts at coordinate $a$ and whose first landing outside $I$ is exactly coordinate $L+b$.\n\nThere is one annoying case: an interval can contain fewer than $x$ cells. During a later merge, a jump may skip that whole interval, or a represented starting position may already be in the next interval. We remove the annoyance with a virtual convention:\n\n- If $a\\ge L$, set $M_I[a][a-L]=0$.\n- Set every other entry in that row to infinity.\n\nThis means, \"we are already past this interval, so shift the offset and do nothing.\" It is not a real zero-length jump. It is only algebraic glue. Without it, short platforms create ugly special cases everywhere, which is generally where bugs breed and start paying rent.\n\n## One platform\n\nConsider one platform with length $d$ and penalty $s$. Start at its cell with offset $a<d$, and require the first outside landing to have offset $b$. The total displacement is\n\n$$D=d+b-a.$$\n\nEvery jump has length at most $x$, so at least\n\n$$t=\\left\\lceil\\frac{D}{x}\\right\\rceil$$\n\njumps are necessary. This number is also achievable while keeping every landing except the last one inside the platform. Intuitively, reserve a sufficiently long final jump across the boundary and distribute the remaining distance among the earlier jumps.\n\nThe first $t-1$ jumps start and end on this platform, so each costs $s$. The last jump lands outside it and costs nothing. Thus\n\n$$M[a][b]=(t-1)s=\\left(\\left\\lceil\\frac{d+b-a}{x}\\right\\rceil-1\\right)s.$$\n\nFor rows with $a\\ge d$, use the virtual transition $M[a][a-d]=0$ described above. This constructs a leaf matrix in $O(x^2)$ time.\n\nIn code, every ceiling division uses\n\n$$\\left\\lceil\\frac{u}{x}\\right\\rceil=\\frac{u+x-1}{x}$$\n\nwith integer division.\n\n## Joining intervals\n\nLet $A$ and $B$ be consecutive intervals. Take any route represented by the matrix of $A+B$, and inspect its first landing at or after the end of $A$. Let its offset from that boundary be $k$.\n\nThe part before that landing is represented by $M_A[a][k]$. From that exact position onward, the remaining route is represented by $M_B[k][b]$. Therefore,\n\n$$M_{A+B}[a][b]=\\min_{0\\le k<x}\\left(M_A[a][k]+M_B[k][b]\\right).$$\n\nThis also covers both awkward-looking situations:\n\n- If the start position is already inside $B$, a virtual row of $A$ shifts it into the correct row of $B$.\n- If the jump leaving $A$ skips all of $B$, a virtual row of $B$ shifts that landing to an exit position of $A+B$.\n\nConversely, any two transitions joined at the same $k$ form a valid route through $A+B$. So the formula is exact, not merely a relaxation.\n\nThe operation is ordinary matrix multiplication with `+` replacing multiplication and `min` replacing addition. In other words, it is a min-plus product. It is associative, which is the entire reason a segment tree can enter the chat.\n\n## Segment tree\n\nBuild one leaf matrix for each platform. Each internal node stores the min-plus product of its left child's matrix and then its right child's matrix. Padding leaves use the min-plus identity matrix: zero on the diagonal and infinity elsewhere.\n\nA length or penalty update changes only one platform matrix. Rebuild that leaf and all its ancestors.\n\nFor a range query, matrix order matters. Decompose the range into the usual $O(\\log n)$ canonical segment-tree nodes and process those nodes strictly from left to right.\n\nWe only need row $0$ of the range product, not the entire product. Start with a vector\n\n$$dp[0]=0,\\qquad dp[i]=\\infty\\text{ for }i>0.$$\n\nWhen appending a node matrix $M$, update\n\n$$next[b]=\\min_a\\left(dp[a]+M[a][b]\\right).$$\n\nApplying one matrix costs $O(x^2)$, so a query for the needed row costs $O(x^2\\log n)$ instead of multiplying full matrices in $O(x^3\\log n)$. The segment tree still stores full matrices because updates must rebuild arbitrary ancestors.\n\nA useful side effect is that changing a platform length still affects only one leaf. Global cell coordinates shift, but every matrix uses coordinates relative to its own boundaries, and composition handles the shifts automatically.\n\n## Finishing a query\n\nFor a query $[l,r]$ with $l<r$, query the product for platforms $l,l+1,\\ldots,r-1$. Starting state $0$ means the first cell of platform $l$.\n\nAfter applying that product, let $dp[i]$ be the minimum cost when the first landing after platform $r-1$ is offset $i$ into platform $r$. Only\n\n$$0\\le i<\\min(x,d_r)$$\n\nare valid, because landing at $i\\ge d_r$ would skip the destination platform, and the Beaver cannot move backward.\n\nFrom offset $i$, the last cell is $d_r-1-i$ cells ahead. The minimum number of remaining jumps is\n\n$$\\left\\lceil\\frac{d_r-1-i}{x}\\right\\rceil.$$\n\nEvery one of those jumps starts and lands on platform $r$, so every one costs $s_r$. The answer is\n\n$$\\boxed{\\min_{0\\le i<\\min(x,d_r)}\\left(dp[i]+\\left\\lceil\\frac{d_r-1-i}{x}\\right\\rceil s_r\\right)}.$$\n\nIf $l=r$, the Beaver starts at offset $0$ of the final platform, so the answer directly becomes\n\n$$\\left\\lceil\\frac{d_l-1}{x}\\right\\rceil s_l.$$\n\n## Correctness proof\n\n**Lemma 1.** The leaf matrix of one platform has the stated meaning.\n\nFor an actual start $a<d$, reaching the required exit needs displacement $d+b-a$, hence at least $t=\\left\\lceil(d+b-a)/x\\right\\rceil$ jumps. Such a route exists with only its last landing outside the platform. Exactly its first $t-1$ jumps have both endpoints on the platform, so its minimum penalty is $(t-1)s$. For $a\\ge d$, the virtual transition changes only the coordinate origin and has cost $0$. Thus every leaf entry is correct.\n\n**Lemma 2.** The min-plus product of two consecutive interval matrices correctly represents their concatenation.\n\nEvery valid route has a unique first landing at or after the boundary between the intervals; call its offset $k$. Splitting there gives costs represented by the two matrix entries, so the route's cost appears in the product. Conversely, joining two represented routes at the same $k$ gives a valid route through the concatenation. Virtual rows correctly cover starts or landings that skip a short interval. Taking the minimum over $k$ therefore gives exactly the optimum.\n\n**Lemma 3.** Every segment-tree node stores the correct matrix for its interval.\n\nLeaves are correct by Lemma 1. Each internal node concatenates its two children using the correct operation from Lemma 2. Induction on the tree proves the claim.\n\n**Lemma 4.** The query formula returns the minimum cost for $[l,r]$.\n\nBy Lemma 3, the queried matrices produce the minimum cost for every possible first landing offset $i$ on platform $r$. From such an offset, the shortest route to its last cell uses $\\left\\lceil(d_r-1-i)/x\\right\\rceil$ internal jumps, each costing $s_r$. Every complete route has exactly one such first offset, and every considered prefix plus suffix is valid. Minimizing over all valid $i$ therefore returns precisely the optimum.\n\n**Theorem.** Every printed answer is the minimum possible penalty after all preceding updates.\n\nUpdates rebuild the changed leaf and all affected ancestors, preserving Lemma 3. Lemma 4 then proves every subsequent answer.\n\n## Complexity\n\nLet the segment-tree size be the next power of two above $n$.\n\n- Building takes $O(nx^3)$ time.\n- A length or penalty update takes $O(x^3\\log n)$ time.\n- An answer query takes $O(x^2\\log n+x)$ time.\n- Memory use is $O(nx^2)$.\n\nAll costs require `long long`: valid answers can be close to $10^{18}$. The implementation uses a larger finite infinity whose additions still fit in signed 64-bit arithmetic.",
              "solution": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nvoid setIO() {\n    ios::sync_with_stdio(false);\n    cin.tie(nullptr);\n}\n\nconstexpr int MAX_X = 5;\nconstexpr ll INF = 4'000'000'000'000'000'000LL;\n\nint x;\n\nstruct Matrix {\n    ll a[MAX_X * MAX_X];\n};\n\nMatrix identityMatrix() {\n    Matrix m;\n    fill(begin(m.a), end(m.a), INF);\n    for (int i = 0; i < x; ++i) {\n        m.a[i * MAX_X + i] = 0;\n    }\n    return m;\n}\n\nMatrix platformMatrix(int d, int s) {\n    Matrix m;\n    fill(begin(m.a), end(m.a), INF);\n\n    for (int i = 0; i < x; ++i) {\n        if (i < d) {\n            for (int j = 0; j < x; ++j) {\n                ll distance = (ll)d + j - i;\n                ll jumps = (distance + x - 1) / x;\n                m.a[i * MAX_X + j] = (jumps - 1) * s;\n            }\n        } else {\n            // The represented position already lies beyond this short platform.\n            m.a[i * MAX_X + (i - d)] = 0;\n        }\n    }\n    return m;\n}\n\ninline void compose(Matrix& out, const Matrix& left, const Matrix& right) {\n    for (int i = 0; i < x; ++i) {\n        for (int j = 0; j < x; ++j) {\n            ll best = INF;\n            for (int k = 0; k < x; ++k) {\n                best = min(best,\n                           left.a[i * MAX_X + k] + right.a[k * MAX_X + j]);\n            }\n            out.a[i * MAX_X + j] = best;\n        }\n    }\n}\n\nstruct SegmentTree {\n    int size = 1;\n    unique_ptr<Matrix[]> tree;\n\n    SegmentTree(const vector<int>& d, const vector<int>& s) {\n        while (size < (int)d.size()) {\n            size <<= 1;\n        }\n        tree.reset(new Matrix[2 * size]);\n\n        Matrix id = identityMatrix();\n        for (int i = 0; i < size; ++i) {\n            tree[size + i] = i < (int)d.size() ? platformMatrix(d[i], s[i]) : id;\n        }\n        for (int p = size - 1; p > 0; --p) {\n            compose(tree[p], tree[p * 2], tree[p * 2 + 1]);\n        }\n    }\n\n    void update(int pos, const Matrix& value) {\n        int p = size + pos;\n        tree[p] = value;\n        for (p >>= 1; p > 0; p >>= 1) {\n            compose(tree[p], tree[p * 2], tree[p * 2 + 1]);\n        }\n    }\n\n    array<ll, MAX_X> rangeRow(int l, int r) const {\n        int leftNodes[32], rightNodes[32];\n        int leftCount = 0, rightCount = 0;\n\n        for (l += size, r += size; l < r; l >>= 1, r >>= 1) {\n            if (l & 1) {\n                leftNodes[leftCount++] = l++;\n            }\n            if (r & 1) {\n                rightNodes[rightCount++] = --r;\n            }\n        }\n\n        array<ll, MAX_X> dp;\n        dp.fill(INF);\n        dp[0] = 0;\n\n        auto apply = [&](int node) {\n            array<ll, MAX_X> next;\n            next.fill(INF);\n            for (int j = 0; j < x; ++j) {\n                for (int i = 0; i < x; ++i) {\n                    next[j] = min(next[j],\n                                  dp[i] + tree[node].a[i * MAX_X + j]);\n                }\n            }\n            dp = next;\n        };\n\n        for (int i = 0; i < leftCount; ++i) {\n            apply(leftNodes[i]);\n        }\n        for (int i = rightCount - 1; i >= 0; --i) {\n            apply(rightNodes[i]);\n        }\n        return dp;\n    }\n};\n\nint main() {\n    setIO();\n\n    int n, q;\n    cin >> n >> q >> x;\n\n    vector<int> d(n), s(n);\n    for (int& value : d) {\n        cin >> value;\n    }\n    for (int& value : s) {\n        cin >> value;\n    }\n\n    SegmentTree seg(d, s);\n\n    while (q--) {\n        char type;\n        cin >> type;\n\n        if (type == '1') {\n            int i, value;\n            cin >> i >> value;\n            --i;\n            d[i] = value;\n            seg.update(i, platformMatrix(d[i], s[i]));\n        } else if (type == '2') {\n            int i, value;\n            cin >> i >> value;\n            --i;\n            s[i] = value;\n            seg.update(i, platformMatrix(d[i], s[i]));\n        } else {\n            int l, r;\n            cin >> l >> r;\n            --l;\n            --r;\n\n            if (l == r) {\n                ll distance = (ll)d[l] - 1;\n                cout << (distance + x - 1) / x * s[l] << '\\n';\n                continue;\n            }\n\n            auto dp = seg.rangeRow(l, r);\n            ll answer = INF;\n            for (int i = 0; i < min(x, d[r]); ++i) {\n                ll distance = (ll)d[r] - 1 - i;\n                ll jumps = (distance + x - 1) / x;\n                answer = min(answer, dp[i] + jumps * s[r]);\n            }\n            cout << answer << '\\n';\n        }\n    }\n}"
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